Chapter 7: Problem 19
Find the Laplace transforms of the functions given in Problems 11 through \(22 .\) $$ f(t)=0 \text { if } t<1 ; f(t)=t \text { if } t \geqq 1 $$
Short Answer
Expert verified
The Laplace transform of the function is \( \frac{e^{-s}}{s^2} \).
Step by step solution
01
Understanding the Function
The given function is piecewise, defined as \( f(t) = 0 \) if \( t < 1 \) and \( f(t) = t \) if \( t \geq 1 \). This means that the function is zero from \( t = 0 \) to \( t = 1 \), and from \( t = 1 \) onward, the function follows a linear path equal to \( t \).
02
Express Function Using Heaviside Function
Express the piecewise function using the Heaviside step function. The function can be written as \( f(t) = t imes u(t-1) \), where \( u(t-1) \) is the Heaviside step function that activates at \( t = 1 \).
03
Recall the Laplace Transform of a Shifted Function
For a function \( f(t) = g(t-a)u(t-a) \), the Laplace transform is given by \( e^{-as}G(s) \), where \( G(s) \) is the Laplace transform of \( g(t) \). Here, \( g(t) = t \) and \( a = 1 \).
04
Find the Laplace Transform of \( g(t) = t \)
The Laplace transform of \( t \) is \( \frac{1}{s^2} \), using the formula for the Laplace transform of \( t^n \) which is \( \frac{n!}{s^{n+1}} \). In this case, \( n = 1 \).
05
Apply the Laplace Transform Formula with Shift
Substitute \( g(t) = t \) and \( a = 1 \) into the formula. The Laplace transform of \( f(t) = t u(t-1) \) becomes \( e^{-s} \times \frac{1}{s^2} \).
06
Write the Final Laplace Transform
The final expression, which is the Laplace transform of the given function, is \( \mathcal{L}\{f(t)\} = \frac{e^{-s}}{s^2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Heaviside Step Function
The Heaviside Step Function, often denoted as \( u(t-a) \), plays a crucial role in transforming piecewise functions. It's essentially a switch that can turn a function "on" or "off" at a certain point on the timeline, marked by \( a \). For instance, in the function given in the exercise, the Heaviside function was used to "activate" the function at \( t=1 \). This means that before \( t=1 \), our function \( f(t) \) was equal to 0. When \( t \) reached and exceeded 1, the Heaviside function allowed \( f(t) \) to follow the form of \( t \).
The Heaviside step function is particularly powerful due to its simplicity:
The Heaviside step function is particularly powerful due to its simplicity:
- It is 0 for all values less than the specified point \( a \).
- It becomes 1 at \( t = a \) and stays 1 for all \( t \geq a \).
Piecewise Functions
Piecewise functions are a way of describing a function that behaves differently in different intervals of its domain. They are defined by multiple sub-functions, each applying to a certain interval of the main function's domain. In the original exercise context, the function \( f(t) \) was defined such that:
The representation of piecewise functions often becomes simplified with Heaviside step functions. Instead of directly stating the behavior in intervals, the Heaviside simplifies them into a single expression. It transforms the need for conditional flow into a mathematical one-liner that packages the entire behavior elegantly.
- For \( t < 1 \), \( f(t) = 0 \).
- For \( t \geq 1 \), \( f(t) = t \).
The representation of piecewise functions often becomes simplified with Heaviside step functions. Instead of directly stating the behavior in intervals, the Heaviside simplifies them into a single expression. It transforms the need for conditional flow into a mathematical one-liner that packages the entire behavior elegantly.
Function Transformation
Function transformation involves changing a function's appearance, position, or scale in its graph. It’s a central concept when working with the Laplace Transform to solve differential equations or analyze systems. In the exercise, we used function transformation to apply the Laplace Transform to a modified version of \( f(t) \).
A significant form of transformation in this example is the shift property using the Heaviside step function. Here's how it works:
These transformations firmly nestle inside control theory, signal processing, and system modeling, allowing for manipulation and interpretative solutions of systems.
A significant form of transformation in this example is the shift property using the Heaviside step function. Here's how it works:
- Shift the function to appear at a later time. This transformation is done through \( g(t) = t \), turning it into \( g(t-a) = (t-1) \).
- The function \( f(t) = g(t-a)u(t-a) \) extracts the gapped part with \( a \) as the shift, which compresses or shifts its graph towards a specific point in time.
These transformations firmly nestle inside control theory, signal processing, and system modeling, allowing for manipulation and interpretative solutions of systems.