Chapter 1: Problem 11
\(\lim _{x \rightarrow 0}\left\\{(1+x)^{\frac{2}{x}}\right\\}\) (where \(\\{x\\}\) denotes the fractional part of \(\mathrm{x}\) ) is equal to (A) \(\mathrm{e}^{2}-7\) (B) \(e^{2}-8\) (C) \(\mathrm{e}^{2}-6\) (D) None of these
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Chapter 1: Problem 11
\(\lim _{x \rightarrow 0}\left\\{(1+x)^{\frac{2}{x}}\right\\}\) (where \(\\{x\\}\) denotes the fractional part of \(\mathrm{x}\) ) is equal to (A) \(\mathrm{e}^{2}-7\) (B) \(e^{2}-8\) (C) \(\mathrm{e}^{2}-6\) (D) None of these
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If $\mathrm{f}(\mathrm{x})=\lim _{\mathrm{n} \rightarrow \infty} \frac{2 \mathrm{x}}{\pi} \tan ^{-1} \mathrm{nx}\(, then value of \)\lim _{\mathrm{x} \rightarrow 0}[\mathrm{f}(\mathrm{x})-1]$ is, where [.] represents greatest integer function (A) 0 (B) \(-1\) (C) 1 (D) does not exist
If \(\mathrm{k}\) is an integer such that $\lim _{n \rightarrow \infty}\left(\left(\cos \frac{k \pi}{4}\right)^{n}-\left(\cos \frac{k \pi}{6}\right)^{n}\right)=0$, then (A) \(\mathrm{k}\) is divisible neither by 4 nor by 6 (B) \(\mathrm{k}\) must be divisible by 12 , but not necessarily by 24 (C) \(\mathrm{k}\) must be divisible by 24 (D) either \(\mathrm{k}\) is divisible by 24 or \(\mathrm{k}\) is divisible neither by 4 nor by 6
$\lim _{\mathrm{n} \rightarrow \infty}\left(\frac{\mathrm{n}}{\mathrm{n}^{2}-2}+\frac{4^{\mathrm{n}}(-1)^{\mathrm{n}}}{2^{\mathrm{n}}-1}\right)^{-1}$ is equal to (A) 2 (B) (C) 0 (D) None of these
$\lim _{x \rightarrow 1} \frac{1+\sin \pi\left(\frac{3 x}{1+x^{2}}\right)}{1+\cos \pi x}$ is equal to (A) \(\overline{0}\) (B) 1 (C) 2 (D) None of these
Which of the following limits exist? (where [.] indicates greatest integer function all throughout) (A) \(\lim _{x \rightarrow 1} \frac{\sin [x]}{[x]}\) (B) $\lim _{n \rightarrow \infty}\left(\frac{\mathrm{e}^{\mathrm{n}}}{\pi}\right)^{1 / \mathrm{n}}$ (C) \(\lim _{x \rightarrow 1}\left[\sin \left(\sin ^{-1} x\right)\right]\) (D) \(\lim _{x \rightarrow \pi / 2}\left[\sin ^{-1}(\sin x)\right]\)
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