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In Exercises \(25-36,\) express the number in the form \(a+b i\). $$2(\cos 1.5+i \sin 1.5)$$

Short Answer

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Question: Convert the complex number in polar form 2(cos 1.5 + i sin 1.5) to its rectangular form (a+bi). Answer: The rectangular form of the complex number is approximately 1.07007 + 1.96144i.

Step by step solution

01

Multiply the magnitude

Multiply the magnitude (2) by the trigonometric components: $$2(\cos 1.5+i \sin 1.5)$$
02

Apply the angle addition formulas

Apply the angle addition formulas to expand simplifying the expression: $$(2\cos 1.5) + (2i \sin 1.5)$$
03

Calculate the numerical values

Let's use a calculator to find the numerical values of cosine and sine: $$2\cos 1.5 \approx 1.07007$$ $$2\sin 1.5 \approx 1.96144$$ Plugging these values back into our expression, we get: $$(1.07007) + (1.96144i)$$ Thus, the complex number in the form a+bi is approximately: $$1.07007 + 1.96144i$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Form of Complex Numbers
Complex numbers, often represented as \(a+bi\), can also be expressed in trigonometric form. The trigonometric form is especially helpful for multiplication and division. The key idea here is to represent the complex number in terms of its magnitude (or modulus) and argument (or angle) using trigonometric functions. Imagine a point on the complex plane with coordinates corresponding to a complex number. The distance from this point to the origin is the magnitude, and the angle it forms with the positive x-axis is the argument.

For a complex number \(z = a + bi\), its trigonometric form is \(z = r(\cos \theta + i \sin \theta)\). Here \(r\) is the magnitude, and \(\theta\) is the argument. This representation taps the essence of both geometry and trigonometry, simplifying many complex number operations by converting them into trigonometric identities.
Angle Addition Formulas
When working with complex numbers in trigonometric form, the angle addition formulas become quite handy. They allow you to easily manipulate the trigonometric components of the complex number, especially when you multiply complex numbers together. The angle addition formulas give us a way to determine the cosine and sine of sums of angles, which is crucial in finding the form \(a + bi\).

These formulas are:
  • Cosine Addition: \(\cos(A + B) = \cos A \cdot \cos B - \sin A \cdot \sin B\)
  • Sine Addition: \(\sin(A + B) = \sin A \cdot \cos B + \cos A \cdot \sin B\)
In the context of the exercise, simplifying the expression involves multiplying the magnitude with the trigonometric components, but often these formulas could be applied when dealing with additional terms, just to ensure everything remains precise and clear.
Magnitude in Complex Numbers
Understanding the magnitude in complex numbers is essential, as it grounds the numbers in the complex plane by giving them a scale. The magnitude of a complex number \(a+bi\) is the distance from the origin \((0,0)\) to the point \((a,b)\) in the complex plane. This is calculated as \(r = \sqrt{a^2 + b^2}\).

In the trigonometric form \(z = r(\cos \theta + i \sin \theta)\), the magnitude \(r\) comes directly into play. It not only dictates the length of the line connecting the origin to the complex number but also scales the trigonometric values for cosine and sine. For example, in the problem, the initial magnitude of 2 was used to scale the components \(\cos 1.5\) and \(\sin 1.5\), grounding the complex number in the form \(a + bi\). Recognizing and properly using the magnitude facilitates a seamless translation from trigonometric form to rectangular form.

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Most popular questions from this chapter

Determine whether the given vectors are parallel, orthogonal, or neither. $$2 \mathbf{i}-2 \mathbf{j}, 5 \mathbf{i}+8 \mathbf{j}$$

Let \(\boldsymbol{u}=\langle a, b\rangle\) and \(\boldsymbol{v}=\langle c, d\rangle,\) and let \(r\) and s be scalars. Prove that the stated property holds by calculating the vector on each side of the equal sign. $$(r+s) \mathbf{v}=r \mathbf{v}+s \mathbf{v}$$

find comp, \(u\) $$\mathbf{u}=\mathbf{i}-2 \mathbf{j}, \mathbf{v}=3 \mathbf{i}+\mathbf{j}$$

If forces \(\boldsymbol{u}_{1}, \boldsymbol{u}_{2}, \ldots, \boldsymbol{u}_{k}\) act on an object at the origin, the resultant force is the sum \(u_{1}+u_{2}+\cdots+u_{k} .\) The forces are said to be in equilibrium if their resultant force is \(0 .\) In Exercises 51 and \(52,\) find the resultant force and find an additional force \(v\) that, if added to the system, produces equilibrium. $$\mathbf{u}_{1}=\langle 2,5\rangle, \mathbf{u}_{2}=\langle-6,1\rangle, \mathbf{u}_{3}=\langle-4,-8\rangle$$

The sum of two distinct complex numbers, \(a+b i\) and \(c+d i,\) can be found geometrically by means of the socalled parallelogram rule: Plot the points \(a+b i\) and \(c+d i\) in the complex plane, and form the parallelogram, three of whose vertices are \(0, a+b i,\) and \(c+d i,\) as in the figure. Then the fourth vertex of the parallelogram is the point whose coordinate is the sum $$(a+b i)+(c+d i)=(a+c)+(b+d) i$$ (GRAPH CAN'T COPY). Complete the following proof of the parallelogram rule when \(a \neq 0\) and \(c \neq 0\) (a) Find the slope of the line \(K\) from 0 to \(a+b i .[\text { Hint: } K\) contains the points \((0,0) \text { and }(a, b) .]\) (b) Find the slope of the line \(N\) from 0 to \(c+d i\) (c) Find the equation of the line \(L\) through \(a+b i\) and parallel to line \(N\) of part (b). [Hint: The point \((a, b)\) is on \(L\) find the slope of \(L\) by using part (b) and facts about the slope of parallel lines.] (d) Find the equation of the line \(M\) through \(c+d i\) and parallel to line \(K\) of part (a). (e) Label the lines \(K, L, M,\) and \(N\) in the figure. (f) Show by using substitution that the point \((a+c, b+d)\) satisfies both the equation of line \(L\) and the equation of line \(M .\) Therefore, \((a+c, b+d)\) lies on both \(L\) and \(M\) since the only point on both \(L\) and \(M\) is the fourth vertex of the parallelogram (see the figure), this vertex must be \((a+c, b+d) .\) Hence, this vertex has coordinate $$(a+c)+(b+d) i=(a+b i)+(c+d i)$$

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