Chapter 9: Problem 36
find comp, \(u\) $$\mathbf{u}=\mathbf{i}+\mathbf{j}, \mathbf{v}=-3 \mathbf{i}-2 \mathbf{j}$$
Short Answer
Expert verified
Answer: The vector component of \(\mathbf{u}\) along \(\mathbf{v}\) is \(\frac{15}{13}\mathbf{i} + \frac{10}{13}\mathbf{j}\).
Step by step solution
01
Find the dot product of \(\mathbf{u}\) and \(\mathbf{v}\)
To find the dot product of \(\mathbf{u}\) and \(\mathbf{v}\), we multiply their corresponding components and then add the products. In this case:
$$\mathbf{u} \cdot \mathbf{v} = (\mathbf{i} + \mathbf{j}) \cdot (-3\mathbf{i}-2\mathbf{j}) =(-3)(1) + (-2)(1) = -5$$
02
Calculate the magnitude of \(\mathbf{v}\)
To calculate the magnitude of \(\mathbf{v}\), we have:
$$|\mathbf{v}| = \sqrt{(-3)^2 + (-2)^2} = \sqrt{9 + 4} = \sqrt{13}$$
03
Find the component of \(\mathbf{u}\) along \(\mathbf{v}\)
To find the component of \(\mathbf{u}\) along \(\mathbf{v}\), we use the formula \(comp_\mathbf{v} \mathbf{u} = \frac{\mathbf{u} \cdot \mathbf{v}}{|\mathbf{v}|}\):
$$comp_\mathbf{v} \mathbf{u} = \frac{-5}{\sqrt{13}}$$
04
Find the vector component of \(\mathbf{u}\) along \(\mathbf{v}\)
To find the vector component of \(\mathbf{u}\) along \(\mathbf{v}\), we multiply \(comp_\mathbf{v} \mathbf{u}\) by the unit vector of \(\mathbf{v}\), which is \(\mathbf{v}\) divided by its magnitude:
$$\mathbf{u}_{v} = comp_\mathbf{v} \mathbf{u} \cdot \frac{\mathbf{v}}{|\mathbf{v}|} = \frac{-5}{\sqrt{13}} \cdot \frac{-3\mathbf{i} - 2\mathbf{j}}{\sqrt{13}}$$
$$\mathbf{u}_{v} =\frac{15\mathbf{i} + 10\mathbf{j}}{13}$$
The vector component of \(\mathbf{u}\) along \(\mathbf{v}\) is \(\frac{15}{13}\mathbf{i} + \frac{10}{13}\mathbf{j}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dot Product
The dot product, also known as the scalar product, is a fundamental operation in vector calculus. It allows us to find a scalar from two vectors. To calculate the dot product of two vectors, we multiply their corresponding components and sum the products. For instance, consider two vectors, \( \mathbf{u} = \mathbf{i} + \mathbf{j} \) and \( \mathbf{v} = -3\mathbf{i} - 2\mathbf{j} \). Here, the dot product \( \mathbf{u} \cdot \mathbf{v} \) is calculated as follows:
- Multiply the \( \mathbf{i} \) components: \( (1)(-3) = -3 \)
- Multiply the \( \mathbf{j} \) components: \( (1)(-2) = -2 \)
- Sum these products: \( -3 + (-2) = -5 \)
Magnitude of a Vector
The magnitude of a vector measures its length and is crucial for understanding the vector's size. It's denoted as \(|\mathbf{v}|\). To find the magnitude of a vector in two-dimensional space, such as \( \mathbf{v} = -3\mathbf{i} - 2\mathbf{j} \), we use the Pythagorean theorem. Calculate it as follows:
- Square each component: \((-3)^2 = 9\) and \((-2)^2 = 4\)
- Sum the squared components: \(9 + 4 = 13\)
- Take the square root of the sum: \( \sqrt{13} \)
Vector Components
Vector components are the individual parts that sum up to represent a vector. A vector, such as \( \mathbf{u} = \mathbf{i} + \mathbf{j} \), can be expressed in terms of its components along standard unit vectors. Each component shows how much influence that direction has on the vector:
- \(1\mathbf{i}\) component means it has full one unit in the \(x\)-direction.
- \(1\mathbf{j}\) component indicates one unit in the \(y\)-direction.
Unit Vector
A unit vector is a vector with a magnitude of one. It's used to specify direction without affecting magnitude. Every vector can be converted into a unit vector by dividing it by its magnitude. For vector \( \mathbf{v} = -3\mathbf{i} - 2\mathbf{j} \), the unit vector \( \mathbf{v_{unit}} \) is found by:
- Calculate the magnitude: \(|\mathbf{v}| = \sqrt{13} \)
- Divide each component by its magnitude: \( \frac{-3\mathbf{i} - 2\mathbf{j}}{\sqrt{13}} \)