Chapter 10: Problem 77
Sketch the graph of the equation. $$r=\sin \theta \tan \theta \quad \text { (cissoid) }$$
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Chapter 10: Problem 77
Sketch the graph of the equation. $$r=\sin \theta \tan \theta \quad \text { (cissoid) }$$
These are the key concepts you need to understand to accurately answer the question.
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Prove that the coordinate conversion formulas are valid when \(r < 0 .[\text {Hint: If } P \text { has coordinates }(x, y) \text { and }(r, \theta), \text { with } r < 0\) verify that the point \(Q\) with rectangular coordinates \((-x,-y)\) has polar coordinates \((-r, \theta) .\) since \(r < 0,-r\) is positive and the conversion formulas proved in the text apply to \(Q .\) For instance, \(-x=-r \cos \theta, \text { which implies that } x=r \cos \theta .]\)
Sketch the graph of the equation. $$r=\sin \theta+\cos \theta$$
Sketch the graphs of the given curves and compare them. Do they differ and if so, how? (a) \(x=t, \quad y=t^{2}\) (b) \(x=\sqrt{t}, \quad y=t\) (c) \(x=e^{t}, \quad y=e^{2 t}\)
If \(a>b>0,\) then the eccentricity of the ellipse $$\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}}=1 \quad \text { or } \quad \frac{(x-h)^{2}}{b^{2}}+\frac{(y-k)^{2}}{a^{2}}=1$$ is the number \(\frac{\sqrt{a^{2}-b^{2}}}{a} .\) Find the eccentricity of the ellipse whose equation is given. $$\frac{(x+5)^{2}}{12}+\frac{(y-4)^{2}}{8}=1$$
Use a calculator in degree mode and assume that air resistance is negligible. A medieval bowman shoots an arrow which leaves the bow 4 feet above the ground with an initial velocity of 88 feet per second at an angle of \(48^{\circ}\) with the horizontal. (a) Graph the arrow's path. (b) Will the arrow go over the 40 -foot-high castle wall that is 200 feet from the archer?
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