/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Find a rectangular equation that... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find a rectangular equation that is equivalent to the given polar equation. \(r=\sec \theta[\text {Hint}:\) Express the right side in terms of cosine.]

Short Answer

Expert verified
Question: Convert the polar equation \(r=\sec\theta\) to a rectangular equation. Answer: The rectangular equation equivalent to the given polar equation is \(x=1\).

Step by step solution

01

Expressing the right side in terms of cosine

Recall that \(\sec\theta = \frac{1}{\cos\theta}\). So, we have \(r = \frac{1}{\cos\theta}\).
02

Multiply by the denominator

Multiply both sides of the equation by \(\cos\theta\) to get: \(r\cos\theta = 1\)
03

Convert to rectangular coordinates

Now, replace \(r\cos\theta\) with \(x\) in the equation above: \(x = 1\) This is a rectangular equation equivalent to the given polar equation: \(r=\sec\theta\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
Polar coordinates are a two-dimensional coordinate system where each point on a plane is determined by a distance from a reference point and an angle from a reference direction. The reference point (analogous to the origin in Cartesian coordinates) is called the pole, and the ray from the pole in the reference direction is the polar axis.

The polar coordinates are written as a pair \(r, \theta\), where \(r\) is the radius or the distance from the pole, and \(\theta\) is the angle measured in radians from the polar axis. Converting between polar and rectangular coordinates involves trigonometric functions, as seen in converting \(r=\frac{1}{\(cos\theta\)}\) to a rectangular equation.
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, are another way of representing points in a plane using two perpendicular lines; one horizontal (x-axis) and one vertical (y-axis). Each axis has a scale, and the position of any point is given by two numbers, commonly referred to as \(x\) and \(y\).

To convert from polar coordinates \( (r, \theta) \) to rectangular coordinates \( (x, y) \) you use the formulas \( x = r\cos\theta \) and \( y = r\sin\theta \). When solving the equation from the exercise, the trigonometric identity \( r\cos\theta = x \) was used to transform the polar equation \(r=\frac{1}{\cos\theta}\) into the rectangular form \(x = 1\).
Trigonometric Functions
Trigonometric functions are fundamental in the study of periodic phenomena, including waves, oscillations, and circles. They relate the angles of a triangle to the lengths of its sides. The basic trigonometric functions are sine (sin), cosine (cos), tangent (tan), and their reciprocals: cosecant (csc), secant (sec), and cotangent (cot).

For example, \(\cos\theta\) is the ratio of the adjacent side to the hypotenuse in a right-angled triangle, and \(\sec\theta\), which is used in the exercise, is the reciprocal of \(\cos\theta\) hence \(\sec\theta = \frac{1}{\cos\theta}\). Understanding these functions is vital for converting between polar and rectangular equations.
Precalculus
Precalculus is a course that prepares students for calculus, and it includes topics such as functions, complex numbers, trigonometry, vectors, and coordinate systems. It introduces the foundational concepts needed to understand the more advanced mathematics of calculus.

In the context of the given exercise, precalculus provides the tools necessary to understand how polar and rectangular coordinates are related and how to work with trigonometric functions to manipulate and convert between different forms of equations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If \(a, b\) are nonzero constants, show that the graph of \(r=\) \(a \sin \theta+b \cos \theta\) is a circle. \([\text {Hint}: \text { Multiply both sides by } r\) and convert to rectangular coordinates.]

Set your calculator for radian mode and for simultaneous graphing mode [check your instruction manual for how to do this]. Particles \(A, B,\) and \(C\) are moving in the plane, with their positions at time \(t\) seconds given by: \(A: \quad x=8 \cos t \quad\) and \(\quad y=5 \sin t\) \(B: \quad x=3 t \quad\) and \(\quad y=5 t\) \(\begin{array}{llll}C: & x=3 t & \text { and } & y=4 t\end{array}\) (a) Graph the paths of \(A\) and \(B\) in the window with \(0 \leq x \leq 12,0 \leq y \leq 6,\) and \(0 \leq t \leq 2 .\) The paths intersect, but do the particles actually collide? That is, are they at the same point at the same time? [For slow motion, choose a very small \(t \text { step, such as } .01 .]\) (b) Set \(t\) step \(=.05\) and use trace to estimate the time at which \(A\) and \(B\) are closest to each other. (c) Graph the paths of \(A\) and \(C\) and determine geometrically [as in part (b)] whether they collide. Approximately when are they closest? (d) Confirm your answers in part (c) as follows. Explain why the distance between particles \(A\) and \(C\) at time \(t\) is given by $$d=\sqrt{(8 \cos t-3 t)^{2}+(5 \sin t-4 t)^{2}}$$ \(A\) and \(C\) will collide if \(d=0\) at some time. Using function graphing mode, graph this distance function when \(0 \leq t \leq 2,\) and using zoom-in if necessary, show that \(d\) is always positive. Find the value of \(t\) for which \(d\) is smallest.

Identify the conic section and use technology to graph it. $$25 x^{2}+16 y^{2}+50 x+96 y=231$$

Find the polar equation of the conic section that has focus (0,0) and satisfies the given conditions. Hyperbola; vertical directrix to the left of the pole; eccentricity \(2 ;(1,2 \pi / 3)\) is on the graph.

Identify the conic section and use technology to graph it. $$x^{2}+y^{2}+6 x-8 y+5=0$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.