/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 Identify the conic section and u... [FREE SOLUTION] | 91Ó°ÊÓ

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Identify the conic section and use technology to graph it. $$x^{2}+y^{2}+6 x-8 y+5=0$$

Short Answer

Expert verified
Answer: The given equation represents a circle, with center (-3, 4) and radius \(\sqrt{20}\).

Step by step solution

01

Identify the conic section represented by the equation

To identify the conic section, we will examine the given equation: $$x^{2}+y^{2}+6 x-8 y+5=0$$ Both x and y are squared, and their coefficients are the same (in this case, 1). This indicates that the equation represents a circle.
02

Rewrite the equation in standard form

To better identify the features of the circle, rewrite the equation in standard form: $$(x-a)^2 + (y-b)^2 = r^2$$ where (a, b) is the center of the circle and r is the radius. To do this, complete the square for the x and y terms: $$x^{2}+6 x+y^{2}-8 y=-5$$ Completing the square, we get: $$(x^2+6x+9)+(y^2-8y+16)=-5+9+16$$ Simplify the equation to obtain the standard form: $$(x+3)^2 + (y-4)^2 = 20$$ Now we can easily determine the center and radius of the circle.
03

Determine the center and radius of the circle

From the equation in standard form: $$(x+3)^2 + (y-4)^2 = 20$$ We can determine the center and radius of the circle: - Center (a, b) = (-3, 4) - Radius r = \(\sqrt{20}\)
04

Use technology to graph the circle

Now that we have identified the center and radius of the circle, we can use technology to graph the circle. You can use graphing calculators, websites, or software such as Desmos, GeoGebra, or WolframAlpha to plot the conic section. When graphing the circle, enter the equation in either the given form or the standard form, and the software will generate the graph for you. Be sure to note the center (-3, 4) and radius \(\sqrt{20}\) in your graph to check that it matches the circle you plotted.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circle Equation
A circle is a unique type of conic section characterized by its geometric properties. The most general equation of a circle in the coordinate plane can be derived from the standard form. In our exercise, the given equation is \[x^{2} + y^{2} + 6x - 8y + 5 = 0.\] We identify it as a circle because both the x and y terms are squared, and they have identical coefficients. Here, the coefficient is 1. This equality implies there's no elongation along any axis, confirming it's a circle. Understanding this is crucial as other conic sections, like ellipses and hyperbolas, vary in their term coefficients.
Completing the Square
Completing the square is a method used to rewrite quadratic equations to make them easier to analyze or graph. This technique transforms the equation by grouping the x and y terms. We'll use it to express our circle equation in standard form.- Start with the original equation: \[x^{2} + y^{2} + 6x - 8y + 5 = 0.\]- Move the constant to the other side: \[x^{2} + 6x + y^{2} - 8y = -5.\]- For the x terms \((x^2 + 6x)\), add and subtract 9. For the y terms \((y^2 - 8y)\), add and subtract 16: \[(x^2 + 6x + 9) + (y^2 - 8y + 16) = -5 + 9 + 16.\]- Simplifying gives us: \[(x+3)^2 + (y-4)^2 = 20.\] This approach helps reveal the circle's geometric features by rearranging its equation into an easily interpretable format.
Standard Form of a Circle
The standard form of a circle's equation is crucial for identifying and graphing circles. It typically looks like this:\[(x-a)^2 + (y-b)^2 = r^2,\]where \((a, b)\) is the center of the circle and \(r\) is the radius. This format is straightforward because it directly provides the circle’s geometric properties.
In our derived equation, \[(x+3)^2 + (y-4)^2 = 20,\] we identify the center as \((-3, 4)\) by recognizing that \(x\)-coordinate is shifted by \(+3\) and \(y\)-coordinate by \(+4\). The radius is the square root of 20, \(r = \sqrt{20}.\)Transforming the circle’s equation into standard form simplifies determining these attributes, clarifying the graphing process.
Graphing Technology
In the modern educational environment, technology is a vital tool for visualizing mathematical concepts. Graphing technology, like calculators or software including Desmos, GeoGebra, or WolframAlpha, simplifies the process of graphing complex equations like conics. Here's a simple approach:
  • Enter the circle's equation either in its original or standard form.
  • Graphing software will automatically adjust and provide a visual representation of the circle.
  • Use the obtained center and radius (\((-3, 4)\) and \(\sqrt{20}\)) to verify the accuracy of the graph.
Technology not only helps to check your work but also assists in understanding the spatial relationship of different parts of the circle. It’s an excellent aid for ensuring your calculated and graphical results are aligned.

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Most popular questions from this chapter

Halley's Comet has an elliptical orbit, with eccentricity .97 and the sun as a focus. The length of the major axis of the orbit is 3364.74 million miles. Using the sun as the pole and assuming the major axis of the orbit is perpedicular to the polar axis, find a polar equation for the orbit.

Use the information given in Special Topics 10.3. A and summarized in the endpapers at the beginning of this book to find a parameterization of the conic section whose rectangular equation is given. Confirm your answer by graphing. $$\frac{(y-2)^{2}}{36}-\frac{(x-5)^{2}}{24}=1$$

Set your calculator for radian mode and for simultaneous graphing mode [check your instruction manual for how to do this]. Particles \(A, B,\) and \(C\) are moving in the plane, with their positions at time \(t\) seconds given by: \(A: \quad x=8 \cos t \quad\) and \(\quad y=5 \sin t\) \(B: \quad x=3 t \quad\) and \(\quad y=5 t\) \(\begin{array}{llll}C: & x=3 t & \text { and } & y=4 t\end{array}\) (a) Graph the paths of \(A\) and \(B\) in the window with \(0 \leq x \leq 12,0 \leq y \leq 6,\) and \(0 \leq t \leq 2 .\) The paths intersect, but do the particles actually collide? That is, are they at the same point at the same time? [For slow motion, choose a very small \(t \text { step, such as } .01 .]\) (b) Set \(t\) step \(=.05\) and use trace to estimate the time at which \(A\) and \(B\) are closest to each other. (c) Graph the paths of \(A\) and \(C\) and determine geometrically [as in part (b)] whether they collide. Approximately when are they closest? (d) Confirm your answers in part (c) as follows. Explain why the distance between particles \(A\) and \(C\) at time \(t\) is given by $$d=\sqrt{(8 \cos t-3 t)^{2}+(5 \sin t-4 t)^{2}}$$ \(A\) and \(C\) will collide if \(d=0\) at some time. Using function graphing mode, graph this distance function when \(0 \leq t \leq 2,\) and using zoom-in if necessary, show that \(d\) is always positive. Find the value of \(t\) for which \(d\) is smallest.

Show that the ball's path in Example 9 is a parabola by eliminating the parameter in the parametric equations \(x=\left(140 \cos 31^{\circ}\right) t \quad\) and \(\quad y=\left(140 \sin 31^{\circ}\right) t-16 t^{2}\) [Hint: Solve the first equation for \(t\), and substitute the result in the second equation. \(]\)

Find a rectangular equation that is equivalent to the given polar equation. $$r=\frac{6}{1-\cos \theta}$$

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