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Convert the equation from polar coordinates into rectangular coordinates. $$ 5 r=\cos (\theta) $$

Short Answer

Expert verified
The rectangular form of the equation is \( 5x^2 + 5y^2 - x = 0 \).

Step by step solution

01

Understand Polar and Rectangular Coordinates

Polar coordinates are in the form \((r, \theta)\), where \( r \) is the radius and \( \theta \) is the angle. Rectangular coordinates are in the form \((x, y)\). The main goal is to convert the given polar equation into an equivalent rectangular form by using known relationships between these coordinates.
02

Apply Conversion Formulas

Remember the conversion formulas: \( x = r \cos(\theta) \) and \( y = r \sin(\theta) \). Additionally, \( r^2 = x^2 + y^2 \). In this problem, you need \( r \) and \( \cos(\theta) \) to convert the equation.
03

Rewrite Given Polar Equation

The given polar equation is \( 5r = \cos(\theta) \). We rewrite it as \( r(5) = \cos(\theta) \) to make substitution simpler.
04

Substitute Using \( x \) and \( r \)

Since \( x = r \cos(\theta) \), we can express \( \cos(\theta) = \frac{x}{r} \). Substitute this into the equation: \( 5r = \frac{x}{r} \).
05

Simplify Substituted Equation

Multiply both sides of the equation \( 5r = \frac{x}{r} \) by \( r \) to eliminate the fraction: \[ 5r^2 = x \]
06

Use \( r^2 = x^2 + y^2 \) to Replace \( r^2 \)

Substitute \( r^2 = x^2 + y^2 \) into the equation from Step 5: \( 5(x^2 + y^2) = x \).
07

Final Rectangular Form

Distribute and rearrange the terms to get the equation into standard form: \[ 5x^2 + 5y^2 - x = 0 \]. This is the rectangular form of the given polar equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
In polar coordinates, any point in a plane is described by two values: the radius \( r \) and the angle \( \theta \). The radius \( r \) represents the distance from the origin to the point, while \( \theta \) depicts the angle formed with the positive x-axis.

This coordinate system is particularly handy in situations where circular or rotational motion is involved. It focuses on the relationship between the distance and direction relative to the origin, making it useful for certain mathematical and engineering problems. Understanding polar coordinates allows for different perspectives on the geometry and can simplify complex conditions where traditional Cartesian, or rectangular, coordinates might be cumbersome.
Rectangular Coordinates
Rectangular coordinates, often referred to as Cartesian coordinates, use a different approach to mapping points on a plane. Here, each point is defined by a pair \( (x, y) \), where \( x \) and \( y \) are the horizontal and vertical distances from the origin, respectively.

Unlike polar coordinates, which measure distance and angle, rectangular coordinates stick to direct measurements along the axes. These direct measurements make calculations straightforward for a lot of algebraic operations and are the basis for most graphs you see, hence their widespread use in many mathematical applications.
Coordinate Conversion
Converting between polar and rectangular coordinates involves using trigonometric relationships to translate \((r, \theta)\) into \((x, y)\) and vice versa. The key formulas for the conversion are:\[x = r \cos(\theta)\] and \[y = r \sin(\theta)\].

Additionally, knowing that \( r^2 = x^2 + y^2 \) allows us to work between the two systems effectively. The conversion process requires a solid grasp of the relationships between the sine, cosine, and their respective coordinates to ensure accurate translations. This is essential in fields that transition between these coordinate systems, like physics and engineering.
Trigonometric Identities
Trigonometric identities play a pivotal role in the conversion between polar and rectangular coordinates. Basic identities such as \( \cos(\theta) = \frac{x}{r} \) and \( \sin(\theta) = \frac{y}{r} \) are often used to bridge the two systems.

Knowing these identities is crucial, as they not only help in converting coordinates but also assist in simplifying expressions and solving equations. They serve as foundational tools in trigonometry and are frequently employed in analytical geometry and calculus.

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Most popular questions from this chapter

The captain of the SS Bigfoot sees a signal flare at a bearing of \(\mathrm{N} 15^{\circ} \mathrm{E}\) from her current location. From his position, the captain of the HMS Sasquatch finds the signal flare to be at a bearing of \(\mathrm{N} 75^{\circ} \mathrm{W}\). If the SS Bigfoot is 5 miles from the HMS Sasquatch and the bearing from the SS Bigfoot to the HMS Sasquatch is \(\mathrm{N} 50^{\circ} \mathrm{E}\), find the distances from the flare to each vessel, rounded to the nearest tenth of a mile.

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