Chapter 11: Problem 69
Find the indicated complex roots. Express your answers in polar form and then convert them into rectangular form. the three cube roots of \(z=64\)
Short Answer
Expert verified
The cube roots of 64 in rectangular form are 4, \(-2 + 2i\sqrt{3}\), and \(-2 - 2i\sqrt{3}\).
Step by step solution
01
Convert to Polar Form
To find the cube roots of \(z=64\), we first express \(64\) in polar form. Since \(64\) is a real number, it is located on the real axis, making its magnitude \(r=64\) and its angle (argument) \( \theta = 0 \). Thus, in polar form we have \(z = 64(\cos 0 + i \sin 0)\).
02
Find Cube Roots in Polar Form
For the cube roots, we use the formula for nth roots of a complex number: \( z_k = r^{1/n} \left( \cos \frac{\theta + 2\pi k}{n} + i \sin \frac{\theta + 2\pi k}{n} \right) \) where \( n = 3 \) and \( k = 0, 1, 2 \). Here, \( r = 64 \) and \( \theta = 0 \), so \( r^{1/3} = 4 \). The roots then are:
03
Compute Cube Roots for k=0,1,2
- For \(k=0\): \(z_0 = 4\left( \cos 0 + i \sin 0 \right) = 4\) - For \(k=1\): \(z_1 = 4\left( \cos \frac{2\pi}{3} + i \sin \frac{2\pi}{3} \right) \) - For \(k=2\): \(z_2 = 4\left( \cos \frac{4\pi}{3} + i \sin \frac{4\pi}{3} \right) \)
04
Convert to Rectangular Form
Convert each of the polar forms to rectangular form: - For \(z_0\): Already in rectangular form, \(4 + 0i\)- For \(z_1\): \(4\left( \cos \frac{2\pi}{3} + i \sin \frac{2\pi}{3} \right) = 4(-\frac{1}{2} + i \frac{\sqrt{3}}{2}) = -2 + 2i\sqrt{3}\)- For \(z_2\): \(4\left( \cos \frac{4\pi}{3} + i \sin \frac{4\pi}{3} \right) = 4(-\frac{1}{2} - i \frac{\sqrt{3}}{2}) = -2 - 2i\sqrt{3}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Form
The polar form of a complex number is a way to represent complex numbers on a coordinate plane using a radius and an angle. It is especially helpful when dealing with powers, roots, and trigonometric functions. Essentially, any complex number can be expressed as \[ z = r(\cos \theta + i \sin \theta) \] where \( r \) is the magnitude (or absolute value) of the complex number and \( \theta \) is the argument, which is the angle formed with the positive real axis.
- \( r \) is calculated as the square root of the sum of the squares of the real and imaginary parts of the complex number.
- \( r = \sqrt{x^2 + y^2} \)
- \( \theta \) is found by taking the \( \arctan \left( \frac{y}{x} \right) \) , giving you an angle in the complex plane.
Rectangular Form
The rectangular form, also known as Cartesian form, is a more common representation of complex numbers. It appears as \( z = x + yi \), where \( x \) is the real part and \( yi \) is the imaginary part. This form is typically used when working with addition, subtraction, and multiplication of complex numbers.
- \( x \) represents the horizontal position on the complex plane, i.e., the real component.
- \( yi \) represents the vertical position on the complex plane, i.e., the imaginary component, where \( i \) is the imaginary unit \( \sqrt{-1} \).
- \( x = r \cos \theta \)
- \( y = r \sin \theta \)
Cube Roots
Finding cube roots of complex numbers is a fascinating and frequently encountered challenge in mathematics. The formula used for finding the \( n \)-th roots, including cube roots, is\[ z_k = r^{1/n} \left( \cos \frac{\theta + 2\pi k}{n} + i \sin \frac{\theta + 2\pi k}{n} \right) \] where \( n \) is the number of roots you are seeking, and \( k \) ranges from 0 to \( n-1 \).
- \( r^{1/n} \) is the principal root, or the real part of the root for a given \( n \).
- For each value of \( k \), you calculate one specific root with a unique angle.
- \( z_0 = 4 \left( \cos 0 + i \sin 0 \right) = 4 \)
- \( z_1 = 4 \left( \cos \frac{2\pi}{3} + i \sin \frac{2\pi}{3} \right) \)
- \( z_2 = 4 \left( \cos \frac{4\pi}{3} + i \sin \frac{4\pi}{3} \right) \)