Chapter 11: Problem 45
For the given vector \(\vec{v}\), find the magnitude \(\|\vec{v}\|\) and an angle \(\theta\) with \(0 \leq \theta<360^{\circ}\) so that \(\vec{v}=\|\vec{v}\|\langle\cos (\theta), \sin (\theta)\rangle\) (See Definition 11.8.) Round approximations to two decimal places. $$ \vec{v}=\langle-7,24\rangle $$
Short Answer
Step by step solution
Find the Magnitude of the Vector
Compute the Magnitude
Determine the Angle Using components
Compute the Angle in Radians
Convert Radians to Degrees
Adjust the Angle to be Within 0 to 360 Degrees
Verify with the Definition
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Magnitude
Here’s the formula to find the magnitude:
- \( \|\vec{v}\| = \sqrt{a^2 + b^2} \)
- First, square the components: \((-7)^2 = 49\) and \(24^2 = 576\).
- Add these squares together: \(49 + 576 = 625\).
- Take the square root of this sum: \(\sqrt{625} = 25\).
Angle Determination
For a vector \(\vec{v} = \langle a, b \rangle\), the angle \(\theta\) with the \(x\)-axis can be found using the inverse tangent function (arctan), as follows:
- \( \theta = \arctan \left( \frac{b}{a} \right) \)
For the example vector \(\vec{v} = \langle -7, 24 \rangle\), calculating \(\theta = \arctan \left( \frac{24}{-7} \right)\) results in an angle in radians. This might initially be negative or a small angle depending on the quadrant, and later needs converting to the suitable angle between \(0\) and \(360\) degrees.
Conversion Between Radians and Degrees
To convert from radians to degrees, use this formula:
- \(\theta_{degrees} = \theta_{radians} \times \frac{180}{\pi}\)
Then, adjust this angle to ensure it falls within the standard range of \(0\) to \(360\) degrees. If the angle is negative, add \(360\) to bring it to the positive rotation direction of a full circle, obtaining approximately \(285.52^\circ\).
Component Form of Vectors
The components of the vector help clarify its direction and magnitude, which aids in performing algebraic operations like addition, subtraction, and scaling on vectors. When understanding vectors, especially in physics or engineering, this component form is essential.
Due to the relationship with its magnitude and direction (angle), any vector can also be represented using trigonometry as \(\|\vec{v}\| \langle \cos(\theta), \sin(\theta) \rangle\), where \(\theta\) is the angle the vector makes with the positive \(x\)-axis. In this expression, \(\cos(\theta)\) gives proportion along the \(x\)-axis, and \(\sin(\theta)\) along the \(y\)-axis. Thus, it connects the abstract algebraic representation with geometrical visualization.