/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 $$ r=\theta, 0 \leq \theta \le... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

$$ r=\theta, 0 \leq \theta \leq 12 \pi $$

Short Answer

Expert verified
The curve is an Archimedean spiral that makes 6 full turns.

Step by step solution

01

Understand the Problem

This problem involves polar coordinates, where you're given a polar equation \( r = \theta \) with \( \theta \) ranging from \( 0 \) to \( 12\pi \). The task is to understand how the curve behaves over this interval.
02

Analyze the Polar Equation

In the equation \( r = \theta \), both the radius \( r \) and the angle \( \theta \) are the same. As \( \theta \) increases, \( r \) increases proportionally. This means that as you rotate around the origin, the distance from the origin also increases.
03

Recognize the Curve Type

The equation \( r = \theta \) is known as an Archimedean spiral. In this type of curve, as \( \theta \) increases, the radius increases linearly, creating a spiral that moves away from the origin.
04

Consider the Interval

The interval \( 0 \leq \theta \leq 12\pi \) indicates that the curve wraps around the origin several times. Since \( 12\pi \) is equivalent to 6 full rotations (because \(2\pi\) is one full circle), the spiral will make 6 complete turns.
05

Identify Characteristics of the Spiral

For each complete rotation of \( 2\pi \), the radius increases by \( 2\pi \) units. In this case, after 6 rotations, the radius will reach \( 12\pi \). Thus, the spiral starts at the origin and spirals outwards, reaching the radius of \( 12\pi \) at \( \theta = 12\pi \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Archimedean Spiral
An Archimedean spiral is a fascinating mathematical curve that expands outward as it revolves around a central point. The defining characteristic of this spiral is its linear growth: the distance from the center increases at a constant rate as you move around the spiral. This means that if you imagine drawing the spiral from the center outwards, it looks like a growing coil that continuously gets further away from the origin.

In the polar coordinate system, an Archimedean spiral is expressed by the equation \( r = a + b\theta \), where \( a \) and \( b \) are constants. In the case of \( r = \theta \), it is a special form of the Archimedean spiral where \( a = 0 \) and \( b = 1 \). This makes it particularly simple, as the radius \( r \) directly matches the angle \( \theta \) in radians. As \( \theta \) increases, the radial distance increases in such a way that a smooth spiral is formed.
  • The spiral is equi-angular, meaning the angle between successive turns of the spiral is constant.
  • For each full rotation of \(2\pi\), the spiral's radius increases by the same amount.
  • This characteristic makes it a tool for understanding wave patterns and other phenomena that revolve around a point.
Polar Equation
The concept of a polar equation moves away from the traditional x-y Cartesian coordinates, instead using a combination of an angle and a distance from a central point (often called the pole or origin).

A polar equation, such as \( r = \theta \), defines a curve by the relationship between the radius \( r \) and the angle \( \theta \). The task is to understand how this equation dictates the shape or path of the curve.
  • In our specific equation \( r = \theta \), the radius is equal to the angle, linking the two dimensions directly.
  • This dynamic allows one to imagine that as the angle \( \theta \) increases by small increments, the radius increases as well, creating a spiraled pattern outward.
  • Each increment in \( \theta \) translates to an equal increment in the distance from the origin, resulting in a consistent and predictable path, notably producing an Archimedean spiral.
r = θ
The shorthand expression \( r = \theta \) encapsulates a simple yet powerful relationship in polar coordinates. Here, each increase in \( \theta \) directly corresponds to an increase in the radius \( r \).

This straight-forward equation sets the stage for constructing spirals systematically.
  • The given interval \( 0 \leq \theta \leq 12\pi \) signifies that as \( \theta \) rotates from 0 to \( 12\pi \), the curve will complete multiple loops around the central point.
  • Because \(2\pi\) is one complete revolution in radians, \( 12\pi \) constitutes six full rotations.
  • During these rotations, the spiral lengthens with every circular path, capturing both the beauty and mathematical elegance of how a simple linear function can model growth patterns through curvilinear motion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Approximate the component form of the vector \(\vec{v}\) using the information given about its magnitude and direction. Round your approximations to two decimal places. \(\|\vec{v}\|=63.92\); when drawn in standard position \(\vec{v}\) makes a \(78.3^{\circ}\) angle with the positive \(x\) -axis

In Exercises \(41-50\), use set-builder notation to describe the polar region. Assume that the region contains its bounding curves. The region in Quadrant I which lies inside both the circle \(r=3\) as well as the rose \(r=6 \sin (2 \theta)\).

The London Eye is a popular tourist attraction in London, England and is one of the largest Ferris Wheels in the world. It has a diameter of 135 meters and makes one revolution (counterclockwise) every 30 minutes. It is constructed so that the lowest part of the Eye reaches ground level, enabling passengers to simply walk on to, and off of, the ride. Find a sinsuoid which models the height \(h\) of the passenger above the ground in meters \(t\) minutes after they board the Eye at ground level.

The table below lists the average temperature of Lake Erie as measured in Cleveland, Ohio on the first of the month for each month during the years \(1971-2000 .^{19}\) For example, \(t=3\) represents the average of the temperatures recorded for Lake Erie on every March 1 for the years 1971 through 2000 . $$ \begin{array}{|l|r|r|r|r|r|r|r|r|r|r|r|r|} \hline \text { Month } & & & & & & & & & & & & \\ \text { Number, } t & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 \\ \hline \begin{array}{l} \text { Temperature } \\ \left({ }^{\circ} \mathrm{F}\right), T \end{array} & 36 & 33 & 34 & 38 & 47 & 57 & 67 & 74 & 73 & 67 & 56 & 46 \\ \hline \end{array} $$ (a) Using the techniques discussed in Example 11.1.2, fit a sinusoid to these data. (b) Using a graphing utility, graph your model along with the data set to judge the reasonableness of the fit. (c) Use the model you found in part 8 a to predict the average temperature recorded for Lake Erie on April \(15^{\text {th }}\) and September \(15^{\text {th }}\) during the years \(1971-2000 .^{20}\) (d) Compare your results to those obtained using a graphing utility.

Discuss with your classmates why the Law of Sines cannot be used to find the angles in the triangle when only the three sides are given. Also discuss what happens if only two sides and the angle between them are given. (Said another way, explain why the Law of Sines cannot be used in the SSS and SAS cases.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.