Chapter 7: Problem 27
Find an equation of the ellipse, centered at the origin, satisfying the conditions. Bccentricity \(\frac{2}{3},\) horizontal major axis of length 6
Short Answer
Expert verified
The equation is \( \frac{x^2}{9} + \frac{y^2}{5} = 1 \).
Step by step solution
01
Identify Conditions
We are given that the eccentricity of the ellipse is \( e = \frac{2}{3} \) and the length of the major axis is 6. The major axis being horizontal indicates \( a > b \). The center of the ellipse is at the origin.
02
Determine Semi-major Axis
The length of the major axis is 6, so the semi-major axis \( a \) is half of that. Thus, \( a = \frac{6}{2} = 3 \).
03
Calculate Semi-minor Axis
For an ellipse, the relationship between semi-major axis \( a \), semi-minor axis \( b \), and eccentricity \( e \) is \( e = \frac{\sqrt{a^2 - b^2}}{a} \). We know \( e = \frac{2}{3} \), so \( \frac{\sqrt{3^2 - b^2}}{3} = \frac{2}{3} \).
04
Solve for Semi-minor Axis
Multiplying both sides by 3 gives \( \sqrt{3^2 - b^2} = 2 \). Squaring both sides gives \( 9 - b^2 = 4 \). Solving for \( b^2 \), we get \( b^2 = 5 \). Therefore, \( b = \sqrt{5} \).
05
Write the Ellipse Equation
The standard form of the ellipse equation with a horizontal major axis is \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \). Substituting \( a = 3 \) and \( b = \sqrt{5} \), the equation becomes \( \frac{x^2}{9} + \frac{y^2}{5} = 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Eccentricity
Eccentricity is a measure of how much an ellipse deviates from being a perfect circle. It tells us the shape and degree of elongation of the ellipse. The eccentricity of an ellipse is represented by the symbol \( e \) and can take values between 0 and 1:
- If \( e = 0 \), the ellipse is actually a circle.
- If \( e \) is closer to 1, the ellipse is more elongated.
Semi-major axis
The semi-major axis of an ellipse is one of its most important elements. It represents half of the longest diameter of the ellipse and is denoted by \( a \). When you think about the semi-major axis, consider it as the main stretch along the width.
- For a horizontal ellipse, the semi-major axis lies along the x-axis.
- Its length is half of the total major axis.
Semi-minor axis
The semi-minor axis is another critical element of an ellipse. It extends half the distance of the shortest diameter of the ellipse, and is denoted by \( b \). For our ellipse centered at the origin:
- The horizontal ellipse implies the semi-minor axis is oriented vertically.
- The formula \( e = \frac{\sqrt{a^2 - b^2}}{a} \) connects the semi-minor axis to eccentricity and the semi-major axis.
Equation of ellipse
The equation of an ellipse is the mathematical description of its shape. For an ellipse centered at the origin with a horizontal major axis, the standard form of the equation is:\[\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\]This is derived by considering how distances \( x \) and \( y \) change relative to the semi-major axis \( a \) and semi-minor axis \( b \). Substituting our calculated values, \( a = 3 \) and \( b = \sqrt{5} \), we form the equation:\[\frac{x^2}{9} + \frac{y^2}{5} = 1\]This equation represents all points \( (x, y) \) that create the shape of the ellipse. Understanding how \( a \) and \( b \) fit into this formula is crucial for graphing and analyzing ellipses in coordinate geometry.