/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 Graph the parabola. $$x=2.3(y+... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graph the parabola. $$x=2.3(y+1)^{2}$$

Short Answer

Expert verified
The parabola opens to the right with vertex at (0, -1).

Step by step solution

01

Identify the Form of the Equation

The given equation is \( x = 2.3(y+1)^2 \). This is a quadratic equation in the form of \( x = a(y - k)^2 + h \), where \( a = 2.3 \), \( h = 0 \), and \( k = -1 \). This indicates a parabola that opens to the right.
02

Determine the Vertex of the Parabola

The vertex of a parabola in the form \( x = a(y - k)^2 + h \) is \((h, k)\). Here, \( h = 0 \) and \( k = -1 \), so the vertex is at the point \((0, -1)\).
03

Identify the Direction of Opening

Since the equation is \( x = 2.3(y+1)^2 \) and the coefficient \( a = 2.3 \) is positive, the parabola opens to the right. In this form, positive \( a \) values indicate a parabola that opens to the right, and negative \( a \) values indicate it opening to the left.
04

Find Additional Points for Graphing

To graph the parabola accurately, choose some values for \( y \) and solve for \( x \). For example:- If \( y = 0 \): \( x = 2.3(0+1)^2 = 2.3 \).- If \( y = 1 \): \( x = 2.3(1+1)^2 = 9.2 \).- If \( y = -2 \): \( x = 2.3(-1)^2 = 2.3 \).These points are (2.3, 0), (9.2, 1), and (2.3, -2).
05

Sketch the Graph

Plot the vertex (0, -1) and the additional points (2.3, 0), (9.2, 1), and (2.3, -2) on a coordinate plane. Draw a smooth curve through these points ensuring that it opens to the right. The curve should be symmetric with respect to the horizontal line \( y = -1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Parabola
A parabola is a U-shaped curve that you may encounter when dealing with quadratic equations. In this case, the equation takes the form \( x = 2.3(y + 1)^2 \). This represents a special type of parabola aligned with the y-axis, which means the opening direction is along the x-axis rather than the more common y-axis alignment.
  • For standard parabolas, the vertex is the central point, and the curve is symmetrical around it.
  • The direction in which a parabola opens is determined by the sign of the coefficient in front of the squared term.
In our example, because the equation is in the form \( x = a(y - k)^2 + h \), and since \( a \) (2.3) is positive, it indicates our parabola opens to the right. The vertex, an essential characteristic of any parabola, is located at the point \((0, -1)\), marking the lowest or highest spot on a vertically oriented parabola or the leftmost for a horizontally oriented one.
Exploring the Vertex Form
The vertex form of a parabola provides a convenient way to determine critical attributes like the vertex and direction. The vertex form can be written as \( x = a(y - k)^2 + h \), resembling a mirror image of the typical \( y = a(x - h)^2 + k \) form used for parabolas opening along the y-axis.
  • The vertex form directly gives us the vertex of the parabola at the point \((h, k)\).
  • The sign and value of the coefficient \( a \) dictate whether the parabola opens to the left or right.
Since our equation is \( x = 2.3(y + 1)^2 \), it fits perfectly into the vertex form structure with \( h = 0 \) and \( k = -1 \). This tells us the parabola's vertex is at \((0, -1)\), providing a starting point for sketching or analyzing the curve.
Graphing the Parabola
Graphing a parabola involves plotting its key points and understanding its general shape. Here, you would start by plotting the vertex, \((0, -1)\), since this represents the central point of symmetry for your parabola.
  • Start by plotting the vertex to provide a clear center point for symmetry.
  • Choose a few values of \( y \) to find additional points along the parabola.
  • For accurate plotting, calculate \( x \) for each chosen \( y \) value.
In our example, by picking some easy-to-calculate points such as \( y = 0 \), \( y = 1 \), and \( y = -2 \), we found points \((2.3, 0)\), \((9.2, 1)\), and \((2.3, -2)\). Plotting these alongside the vertex helps outline the parabola's rightward curve. Once you have plotted these points, draw a smooth, symmetric curve through them to sketch the graph accurately. The parabola is symmetrical about the line \( y = -1 \), ensuring both sides mirror each other perfectly around the vertex.

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