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Solve each rational inequality and graph the solution set on a real number line. Express each solution set in interval notation. $$ \frac{3 x+5}{6-2 x} \geq 0 $$

Short Answer

Expert verified
The solution to the rational inequality \(\frac{3x+5}{6-2x} \geq 0\) is \((-\infty, -5/3] \cup [-5/3, 3) \cup (3, +\infty)\)

Step by step solution

01

Identify the Critical Values

The critical values will give us the intervals to test in the rational inequality. The critical values are when the numerator equals zero and when the denominator equals zero, so we solve for x in both \(3x+5=0\) and \(6-2x=0\). Hence, \(x=-5/3\) and \(x=3\).
02

Prepare the Number line

Draw a number line and mark the critical points, -5/3 and 3, on it. This divides the number line into three intervals: \(-\infty, -5/3\), \(-5/3, 3\), and \(3, +\infty\). We should pay attention to not include critical numbers that make the denominator zero in the solution set.
03

Test each interval

Pick a test number from each interval and determine whether the inequality is satisfied or not. Let's choose the numbers -2, 0, and 4. Substituting these values into the inequality gives \(1/4\), \(-5/3\), and \(7/6\), respectively. As we see, all the results are greater or equal to zero.
04

Write the solution in interval notation

Combine step 2 and 3, we know which intervals satisfy the inequality. Express these intervals in interval notation, we have \((-\infty, -5/3] \cup [-5/3, 3) \cup (3, +\infty)\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Inequality Graphing
Understanding rational inequality graphing is crucial for visualizing the solution sets of rational inequalities.
A rational inequality involves a fraction with a polynomial in the numerator and denominator. The first step in graphing is to find the zeros of the numerator and the denominator, as these will be the critical points where the graph can intersect or approach asymptotes on the number line.

With the critical values identified, the next step is to draw a number line and plot these points carefully. These points divide the number line into intervals, which are then individually tested to determine where the inequality holds true. In a given example, like solving \(\frac{3x+5}{6-2x} \geq 0\), the critical values are \(x=-\frac{5}{3}\) and \(x=3\), which split the number line into distinct regions to analyze.

In practice, we graph a hollow circle at the critical points that are not included in the solution and a filled circle at those that are included. The resulting graph serves as a visual aid to comprehend which intervals satisfy the inequality.
Interval Notation
Interval notation is a succinct way to express ranges of numbers that satisfy an inequality. This notation uses brackets and parentheses to designate inclusive and exclusive boundaries, respectively.

For instance, in the expression \( (-\infty, -\frac{5}{3}] \cup [-\frac{5}{3}, 3) \cup (3, +\infty) \), the different parts of the notation represent different ranges of 'x' values that solve the inequality \(\frac{3x+5}{6-2x} \geq 0\). The square bracket around \( -\frac{5}{3} \) signifies that this value is included in the solution set, while the round parentheses indicate that the endpoints ‘3’ and infinity are not parts of the solution.

When writing solutions, it's key to use the correct notation to reflect whether the critical points are part of the solution (\
Critical Values in Inequalities
Critical values in inequalities are the points where the value of the rational expression may change from positive to negative or vice versa. They are essential in dividing the number line into intervals for further analysis.

Critical values are often determined by setting the numerator and denominator of the rational expression equal to zero. In the case of the example inequality \(\frac{3x+5}{6-2x} \geq 0\), the critical values are \(x=-\frac{5}{3}\) and \(x=3\). These values are where the numerator equals zero, producing a zero value of the expression, or the denominator equals zero, causing the expression to be undefined.

Determining the critical values is a necessary step in the process as it not only identifies potential boundaries of the solution set but also prevents including points in the solution set where the expression is undefined.
Number Line Analysis
Number line analysis is a method used to visually interpret the solution sets of inequalities by dividing the number line into intervals around critical values.

After plotting the critical points on a number line, which are \(x=-\frac{5}{3}\) and \(x=3\) in our running example, we then select test points from each interval to evaluate the inequality. This approach is particularly effective because it allows for a clear visual representation of which intervals satisfy the inequality. Using test points like -2, 0, and 4 helps us determine the sign of the expression in each interval.

The final step involves labelling the number line with shaded or unshaded regions to indicate where the inequality holds true. In the given solution, the entirety of the number line except the point where \(x=3\) is part of the solution, as this point makes the denominator and therefore the entire rational expression undefined. Hence, this point is excluded, and it highlights an essential rule in rational inequalities: never include points that make the denominator zero.

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