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Use the vertex and intercepts to sketch the graph of each quadratic function. Give the equation of the parabola's axis of symmetry. Use the graph to determine the function's domain and range. $$f(x)=(x-3)^{2}+2$$

Short Answer

Expert verified
The vertex of the quadratic function \(f(x)=(x-3)^{2}+2\) is at \((3,2)\). The axis of symmetry is given by \(x=3\). The domain is all real numbers, or \(x \in (-\infty, +\infty)\), and the range is \(y \geq 2\) or \([2, +\infty)\).

Step by step solution

01

Identify the Vertex

The given function is in vertex form \(f(x) = a(x-h)^2 + k\). Compare the given function \(f(x)=(x-3)^{2}+2\) with the vertex form to find that the vertex is at \((h, k) = (3,2)\).
02

Sketch the Graph

Plot the vertex at point \((3,2)\). Because the coefficient of \(x^2\) is positive, the parabola opens upwards. The graph is a U-shaped curve that has its lowest point, the vertex, at \((3,2)\).
03

Identify the Axis of Symmetry

The axis of symmetry for a parabola in vertex form is expressed by the equation \(x=h\). Thus, for this given function, the equation of the axis of symmetry is \(x=3\).
04

Identify the Domain

The domain of a quadratic function is all real numbers, as there is no restriction on the input values for the function. Therefore, the domain of the given function is \(x \in (-\infty, +\infty)\).
05

Identify the Range

The range of a quadratic function depends on the direction in which the parabola opens. Because our parabola opens upwards, the range is all y-values greater than or equal to the y-coordinate of the vertex, so the range of the given function is \(y \geq 2\) or \([2, +\infty)\).

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