/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 A college theater has a seating ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A college theater has a seating capacity of 2000 . It reserves \(x\) tickets for students and \(y\) tickets for general admission. For parts (a)-(d) write an inequality to represent the given statement. a. The total number of seats available is at most 2000 . b. The college wants to reserve at least 3 times as many student tickets as general admission tickets. c. The number of student tickets cannot be negative. d. The number of general admission tickets cannot be negative. e. Graph the solution set to the system of inequalities from parts (a)-(d).

Short Answer

Expert verified
The inequalities are: \( x + y \leq 2000 \), \( x \geq 3y \), \( x \geq 0 \), and \( y \geq 0 \). The solution is graphed and found at the intersection of these regions.

Step by step solution

01

Define variables

Let \( x \) represent the number of student tickets and \( y \) represent the number of general admission tickets.
02

Formulate the inequality for part (a)

The total number of seats available is at most 2000: \[ x + y \leq 2000 \]
03

Formulate the inequality for part (b)

The college wants to reserve at least 3 times as many student tickets as general admission tickets: \[ x \geq 3y \]
04

Formulate the inequality for part (c)

The number of student tickets cannot be negative: \[ x \geq 0 \]
05

Formulate the inequality for part (d)

The number of general admission tickets cannot be negative: \[ y \geq 0 \]
06

Graphing the solution (overview)

Graph the solution set by plotting each inequality on the coordinate plane. The solution set will be the region where all the inequalities overlap.
07

Graphing the inequality from part (a)

Graph \( x + y \leq 2000 \). This is a line with a slope of -1 intersecting the x-axis at 2000 and the y-axis at 2000. Shade below the line.
08

Graphing the inequality from part (b)

Graph \( x \geq 3y \). This is a line with a slope of 1/3. Shade above the line. The line passes through the origin and increases by 1 unit of x for every 3 units of y.
09

Graphing the inequality from part (c)

For \( x \geq 0 \), shade to the right of the y-axis, ensuring that \( x \) is always non-negative.
10

Graphing the inequality from part (d)

For \( y \geq 0 \), shade above the x-axis, ensuring that \( y \) is always non-negative.
11

Identify the solution set

The solution set is the intersection of all the shaded regions from the inequalities. This will form a region where all conditions are satisfied.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

linear inequalities
Linear inequalities represent mathematical expressions where the two sides are not equal but have a specific relational property. They typically involve a variable where the expression might be \(\leq\) (less than or equal to) or \(\geq\) (greater than or equal to) rather than an equal sign. For example, in the problem, we use the inequality \[ x + y \leq 2000 \] to convey that the sum of student tickets and general admission tickets must not exceed 2000.
Linear inequalities form straight lines when graphed and divide the plane into two regions: one that satisfies the inequality and one that does not. Understanding how to interpret and manipulate these inequalities is a key skill in algebra.
system of inequalities
A system of inequalities consists of multiple inequalities that need to be satisfied simultaneously. In the theater problem, we have four inequalities:
\[ x + y \leq 2000 \], which ensures the total tickets do not exceed 2000;
\[ x \geq 3y \], reserving at least three times more student tickets;
\[ x \geq 0 \] and \[ y \geq 0 \], which make sure ticket counts are non-negative.
To solve a system of inequalities, we graph each inequality on the same coordinate plane. The solution set is the region where all the inequalities overlap.
graphing inequalities
Graphing inequalities involves plotting the inequality lines and shading the appropriate regions. Here’s how to graph each inequality from the exercise:
1. \[ x + y \leq 2000 \]: Graph this as a line that intercepts the y-axis at 2000 and the x-axis at 2000. Shade below the line.
2. \[ x \geq 3y \]: This forms a line through the origin where for every 1 unit of x, y increases by 1/3. Shade above this line.
3. \[ x \geq 0 \]: Shade to the right of the y-axis.
4. \[ y \geq 0 \]: Shade above the x-axis.
The combined shaded areas from all inequalities represent the feasible region. This region is where all conditions are met.
college algebra
College algebra often deals with more complex problems like systems of inequalities. These problems require skills in both algebraic manipulation and graphical representation. Students learn to:
  • Define and interpret inequalities.
  • Formulate equations representing real-world scenarios.
  • Graph solutions on a coordinate plane.
  • Find regions where multiple inequalities overlap.
In the college theater problem, applying these skills helps determine how many of each type of ticket can be sold while staying within constraints.
non-negative constraints
Non-negative constraints pertain to variables that cannot take negative values. Often, this is because negative quantities do not make sense in the context of the problem. In the theater problem, it does not make sense to sell a negative number of tickets. Therefore, we use the inequalities \[ x \geq 0 \] and \[ y \geq 0 \] to ensure the number of tickets is always zero or positive. These constraints are essential in maintaining realistic and interpretable solutions within the feasible region of a graph.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the given constraints to find the maximum value of the objective function and the ordered pair \((x, y)\) that produces the maximum value. \(x \geq 0, y \geq 0\) \(x+y \leq 20\) \(x+2 y \leq 36\) \(x \leq 14\) a. Maximize: \(z=12 x+15 y\) b. Maximize: \(z=15 x+12 y\)

Two runners begin at the same point on a \(390-\mathrm{m}\) circular track and run at different speeds. If they run in opposite directions, they pass each other in \(30 \mathrm{sec}\). If they run in the same direction, they meet each other in \(130 \mathrm{sec}\). Find the speed of each runner.

Jonas performed an experiment for his science fair project. He learned that rinsing lettuce in vinegar kills more bacteria than rinsing with water or with a popular commercial product. As a follow-up to his project, he wants to determine the percentage of bacteria killed by rinsing with a diluted solution of vinegar. a. How much water and how much vinegar should be mixed to produce 10 cups of a mixture that is \(40 \%\) vinegar? b. How much pure vinegar and how much \(40 \%\) vinegar solution should be mixed to produce 10 cups of a mixture that is \(60 \%\) vinegar?

Solve the system using any method. $$ \begin{array}{l} \frac{x-2}{8}+\frac{y+1}{2}=-6 \\ \frac{x-2}{2}-\frac{y+1}{4}=12 \end{array} $$

A paving company delivers gravel for a road construction project. The company has a large truck and a small truck. The large truck has a greater capacity, but costs more for fuel to operate. The load capacity and cost to operate each truck per load are given in the table. $$ \begin{array}{|l|c|c|} \hline & \text { Load Capacity } & \text { Cost per Load } \\ \hline \text { Small truck } & 18 \mathrm{yd}^{3} & \$ 120 \\ \hline \text { Large truck } & 24 \mathrm{yd}^{3} & \$ 150 \\ \hline \end{array} $$ The company must deliver at least 288 yd \(^{3}\) of gravel to stay on schedule. Furthermore, the large truck takes longer to load and cannot make as many trips as the small truck. As a result, the number of trips made by the large truck is at most \(\frac{3}{4}\) times the number of trips made by the small truck. a. Determine the number of trips that should be made by the large truck and the number of trips that should be made by the small truck to minimize cost. b. What is the minimum cost to deliver gravel under these constraints?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.