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Graph the equations. \(y=x^{2}-4\)

Short Answer

Expert verified
Graph the vertex (0, -4) and the points (-2, 0) and (2, 0), then draw an upward-opening parabola.

Step by step solution

01

Understand the Equation

The given equation is a quadratic equation in the form of \(y = x^2 - 4\). This is a standard form of a parabola opening upwards.
02

Identify the Vertex

For the equation \(y = x^2 - 4\), the vertex form is \(y = (x - h)^2 + k\). Here, \(h = 0\) and \(k = -4\). Therefore, the vertex of the parabola is at the point (0, -4).
03

Determine Points on the Parabola

Select values of \(x\) to find corresponding values of \(y\). For instance, when \(x = -2\), \(y = (-2)^2 - 4 = 0\). Similarly, for \(x = 2\), \(y = (2)^2 - 4 = 0\). These give us points (-2, 0) and (2, 0).
04

Plot the Vertex and Points

Plot the vertex (0, -4) and the points (-2, 0) and (2, 0) on graph paper or a graphing tool.
05

Draw the Parabola

Connect the points smoothly to form a parabola. Make sure that the parabola opens upwards and the vertex is the lowest point.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

quadratic equations
Quadratic equations are a type of polynomial equation of the form \(y = ax^2 + bx + c\). They are called 'quadratic' because the highest degree of the variable is squared. The graph of a quadratic equation is a parabola. The parabola's shape and direction (whether it opens upwards or downwards) depend on the coefficient \(a\). If \(a > 0\), the parabola opens upwards, and if \(a < 0\), it opens downwards.

In our example, \(y = x^2 - 4\), we see that \(a = 1\), which means the parabola opens upwards. Quadratic equations are fundamental in algebra and appear in various real-life contexts like projectile motion, economics, and architecture.

Understanding how to graph these equations helps in visualizing their solutions and behaviors. Graphing involves several steps, including identifying the vertex, plotting points, and drawing the curve. Each step plays a crucial role in creating an accurate graph.
vertex of a parabola
The vertex of a parabola is its highest or lowest point, depending on the direction the parabola opens. For upward-opening parabolas, the vertex is the lowest point, and for downward-opening parabolas, it is the highest. The vertex form of a quadratic equation \(y = a(x - h)^2 + k\) makes it easier to identify the vertex, where \(h\) and \(k\) represent the x and y coordinates of the vertex respectively.

In our equation \(y = x^2 - 4\), we can compare it with the vertex form and find that \(h = 0\) and \(k = -4\). Therefore, the vertex is at point (0, -4). This point acts as the cornerstone for the parabola's shape because it represents the point of symmetry. The axis of symmetry for the parabola passes through the vertex, essentially dividing the parabola into two mirror-image halves.

Knowing the vertex is essential since it helps in plotting the parabola accurately by ensuring that the graph is centered correctly.
plotting points
Plotting points is an integral step when graphing a quadratic equation. After identifying the vertex, the next step includes selecting values of \(x\) to find their corresponding \(y\) values. This is done by substituting the chosen \(x\) values back into the equation. For example, in \(y = x^2 - 4\), if we choose \(x = 1\), we find \(y = (1)^2 - 4 = -3\), giving us the point (1, -3).

It's useful to choose \(x\) values on both sides of the vertex to ensure a symmetrical shape. In the given example, the points (-2, 0) and (2, 0) were chosen, providing additional clarity about the shape and direction of the parabola.

Plotting these points on a graph helps in visualizing the curve better. Always include at least three significant points—the vertex and additional points on either side—to draw an accurate graph.
standard form of a parabola
The standard form of a quadratic equation is \(y = ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants. This form allows us to recognize the basic structure of the parabola. The coefficient \(a\) determines the direction and width of the parabola. When \(a > 0\), the parabola opens upwards. When \(a < 0\), it opens downwards.

From the general form, we can derive the vertex form to make graphing easier. The steps typically involve completing the square, a method used to transform a quadratic equation into the vertex form. However, in simpler cases like \(y = x^2 - 4\), it is apparent that it is already nearly in vertex form with a minor adjustment.

Recognizing whether your quadratic equation is in standard form helps in analyzing and graphing the equation efficiently, leading to better comprehension and visualization of the shape and attributes of the parabola. Understanding these forms can vastly improve your skills in working with quadratic equations.

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Most popular questions from this chapter

A sporting goods store sells two types of exercise bikes. The deluxe model costs the store $$\$ 540$$ from the manufacturer and the standard model costs the store $$\$ 420$$ from the manufacturer. The profit that the store makes on the deluxe model is $$\$ 180$$ and the profit on the standard model is $$\$ 120$$. The monthly demand for exercise bikes is at most \(30 .\) Furthermore, the store manager does not want to spend more than $$\$ 14,040$$ on inventory for exercise bikes. a. Determine the number of deluxe models and the number of standard models that the store should have in its inventory each month to maximize profit. (Assume that all exercise bikes in inventory are sold.) b. What is the maximum profit? c. If the profit on the deluxe bikes were $$\$ 150$$ and the profit on the standard bikes remained the same, how many of each should the store have to maximize profit?

Determine if the ordered pair is a solution to the system of equations. (See Example 1\()\) \(-11 x+6 y=-4\) \(7 x+3 y=23\) a. \(\left(1, \frac{7}{6}\right)\) b. (2,3)

Solve the system using any method. $$ \begin{array}{l} 2 x-7 y=2400 \\ -4 x+1800=y \end{array} $$

Use the given constraints to find the maximum value of the objective function and the ordered pair \((x, y)\) that produces the maximum value. \(x \geq 0, y \geq 0\) \(3 x+4 y \leq 48\) \(2 x+y \leq 22\) \(y \leq 9\) a. Maximize: \(z=100 x+120 y\) b. Maximize: \(z=100 x+140 y\)

Juan borrows \(\$ 100,000\) to pay for medical school. He borrows part of the money from the school whereby he will pay \(4.5 \%\) simple interest. He borrows the rest of the money through a government loan that will charge him \(6 \%\) interest. In both cases, he is not required to pay off the principal or interest during his 4 yr of medical school. However, at the end of \(4 \mathrm{yr}\), he will owe a total of \(\$ 19,200\) for the interest from both loans. How much did he borrow from each source?

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