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Use the given constraints to find the maximum value of the objective function and the ordered pair \((x, y)\) that produces the maximum value. \(x \geq 0, y \geq 0\) \(3 x+4 y \leq 48\) \(2 x+y \leq 22\) \(y \leq 9\) a. Maximize: \(z=100 x+120 y\) b. Maximize: \(z=100 x+140 y\)

Short Answer

Expert verified
For both parts, the maximum value of the objective function occurs at (8, 9). The maximum value for part (a) is 2000 and for part (b) is 2120.

Step by step solution

01

- Understand the Constraints

Identify and list the given constraints: 1. Non-negativity constraints: - \( x \geq 0 \) - \( y \geq 0 \) 2. Linear inequalities: - \( 3x + 4y \leq 48 \) - \( 2x + y \leq 22 \) - \( y \leq 9 \)
02

- Graph the Feasible Region

Plot each inequality constraint on a coordinate system. The feasible region will be the intersection of the half-planes defined by these inequalities. Remember to include the non-negativity constraints.
03

- Identify Corner Points

Determine the points of intersection (corner points) within the feasible region: - (0, 0): Intersection of \( x = 0 \) and \( y = 0 \) - (0, 9): Intersection of \( y = 9 \) and \( y \leq 9 \) - (8, 9): Intersection of \( 3x + 4y = 48 \) and \( y = 9 \) - (11, 0): Intersection of \( 2x + y = 22 \) and \( y = 0 \)
04

- Calculate Objective Function at Each Corner Point (Part a)

Evaluate \( z = 100x + 120y \) at each corner point: - (0, 0): \( z = 100(0) + 120(0) = 0 \) - (0, 9): \( z = 100(0) + 120(9) = 1080 \) - (8, 9): \( z = 100(8) + 120(9) = 2000 \) - (11, 0): \( z = 100(11) + 120(0) = 1100 \)
05

- Find Maximum Value for Part a

The highest value of \( z = 2000 \) occurs at the point (8, 9).
06

- Calculate Objective Function at Each Corner Point (Part b)

Evaluate \( z = 100x + 140y \) at each corner point: - (0, 0): \( z = 100(0) + 140(0) = 0 \) - (0, 9): \( z = 100(0) + 140(9) = 1260 \) - (8, 9): \( z = 100(8) + 140(9) = 2120 \) - (11, 0): \( z = 100(11) + 140(0) = 1100 \)
07

- Find Maximum Value for Part b

The highest value of \( z = 2120 \) occurs at the point (8, 9).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Objective Function
The objective function is a key component in linear programming problems. It is the function that you are trying to maximize or minimize. In this exercise, we have two different objective functions for Parts a and b.
For Part a, the objective function is:

For Part b, the objective function is: The goal is to find the values of and that either maximize or minimize these functions under the given constraints.
An objective function typically represents costs, profits, or some measure of performance and guides decision-making by providing a criterion for optimization.
Feasible Region
The feasible region is the set of all possible points that satisfy the constraints of a linear programming problem. This region represents all the viable solutions to the problem and is usually visualized on a graph.
To determine the feasible region, plot the constraints on a coordinate system and find the area where all the inequalities overlap. Don't forget that it also includes non-negativity constraints ( ), meaning all solutions must lie in the first quadrant.
In this problem, our constraints are: - The feasible region will be the intersection of these inequalities. This region essentially holds all the potential (x, y) pairs that we can evaluate to find the maximum value of our objective function.
Corner Points
Corner points, also known as vertices, are critical in solving linear programming problems. These points occur where the boundary lines of the feasible region intersect. The significance of these points lies in the fact that the maximum or minimum value of the objective function will always occur at one of the corner points.
To find these points, you need to solve the systems of equations formed by the intersecting lines of the constraints. In this exercise, the corner points are:
- Evaluate the objective function at each of these corner points to find the optimal solution. This method ensures you consider all possible maximum or minimum values within the feasible region.
Non-Negativity Constraints
Non-negativity constraints are a fundamental aspect of linear programming problems. They restrict the variables to being zero or positive, ensuring that the solutions are practical and realistic for problems involving quantities like production units, resources, or other non-negative values.
In this exercise, the non-negativity constraints are given as: - This means our solutions must lie in the first quadrant of the coordinate system, where both and are zero or positive.
These constraints simplify the problem and ensure that the feasible region is bounded within the first quadrant, making the problem easier to solve and more aligned with real-world scenarios.
Linear Inequalities
Linear inequalities are expressions that show the relationship between two variables under specific constraints. They form the boundary lines of the feasible region in a linear programming problem.
In this exercise, the constraints are represented by the following linear inequalities:- Each of these inequalities represents a half-plane on the graph. The feasible region is where all these half-planes intersect.
Understanding linear inequalities is crucial because they define the limits within which the objective function can be optimized. By graphing these inequalities, you can visually identify the feasible region and the corner points, which are essential for solving the problem.

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Most popular questions from this chapter

Jonas performed an experiment for his science fair project. He learned that rinsing lettuce in vinegar kills more bacteria than rinsing with water or with a popular commercial product. As a follow-up to his project, he wants to determine the percentage of bacteria killed by rinsing with a diluted solution of vinegar. a. How much water and how much vinegar should be mixed to produce 10 cups of a mixture that is \(40 \%\) vinegar? b. How much pure vinegar and how much \(40 \%\) vinegar solution should be mixed to produce 10 cups of a mixture that is \(60 \%\) vinegar?

A sporting goods store sells two types of exercise bikes. The deluxe model costs the store $$\$ 540$$ from the manufacturer and the standard model costs the store $$\$ 420$$ from the manufacturer. The profit that the store makes on the deluxe model is $$\$ 180$$ and the profit on the standard model is $$\$ 120$$. The monthly demand for exercise bikes is at most \(30 .\) Furthermore, the store manager does not want to spend more than $$\$ 14,040$$ on inventory for exercise bikes. a. Determine the number of deluxe models and the number of standard models that the store should have in its inventory each month to maximize profit. (Assume that all exercise bikes in inventory are sold.) b. What is the maximum profit? c. If the profit on the deluxe bikes were $$\$ 150$$ and the profit on the standard bikes remained the same, how many of each should the store have to maximize profit?

Solve the system using any method. $$ \begin{array}{l} 4(x-2)=6 y+3 \\ \frac{1}{4} x-\frac{3}{8} y=-\frac{1}{2} \end{array} $$

Refer to Section 2.5 for a review of linear cost functions and linear revenue functions. A vendor at a carnival sells cotton candy and caramel apples for \(\$ 2.00\) each. The vendor is charged \(\$ 100\) to set up his booth. Furthermore, the vendor's average cost for each product he produces is approximately \(\$ 0.75\) a. Write a linear cost function representing the cost \(C(x)\) (in \(\$$ ) to produce \)x\( products. b. Write a linear revenue function representing the revenue \)R(x)\( (in \$) for selling \)x$ products. c. Determine the number of products to be produced and sold for the vendor to break even. d. If 60 products are sold, will the vendor make money or lose money?

Solve the system of equations by using the addition method. (See Examples \(3-4)\) $$ \begin{array}{l} 2 x+11 y=4 \\ 3 x-6 y=5 \end{array} $$

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