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Solve each system by the substitution method. $$\left\\{\begin{array}{l} 2 x+y-4 \\ (x+1)^{2}+(y-2)^{2}-4 \end{array}\right.$$

Short Answer

Expert verified
The system of equations has no solution.

Step by step solution

01

Rearrange Linear Equation

The linear equation in the system is \(2x + y = 4\). This can be rearranged to solve for \(y\), giving the new equation \(y = 4 - 2x\).
02

Substitute into Circle Equation

Substitute \(y = 4 - 2x\) into the circle equation to get a quadratic equation: \((x+1)^2 + [(4-2x) - 2]^2 - 4 = 0\). Simplify this equation to \(x^2 - 2x + 5 = 0\).
03

Solve Quadratic Equation

To solve this equation, use the quadratic formula \(x = [-(-2) ± sqrt{(-2)^2 - 4*1*5}]/2*1\), resulting in \(x = 1 ± sqrt{1 - 5}\). Since \(1 - 5\) is negative, there is no real solution for \(x\).
04

No Solution for the System

Because there are no real solutions for \(x\), there are also no corresponding values for \(y\) that would solve the system. Therefore, the system of equations has no solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Equations
In mathematics, a "system of equations" consists of multiple equations that are solved together. Each equation represents a condition that the variables must satisfy. Systems of equations can involve different types of equations, such as linear equations and quadratic equations.

The ultimate goal when working with such systems is to find values for the variables that satisfy all the given equations simultaneously. In solving systems of equations using the substitution method, the first step often involves expressing one variable in terms of another from one equation and then substituting that expression into the other equation(s). This approach helps reduce and simplify the problem to having one equation in one variable.

However, sometimes, like in the given problem, you might encounter situations where there are no solutions that satisfy both equations due to the nature of their relationships.
Quadratic Equation
A "quadratic equation" is a type of polynomial equation of degree 2. It has the general form of \[ ax^2 + bx + c = 0 \]. Quadratic equations can model various physical and mathematical phenomena, often involving curves such as parabolas in geometry.

In our context, after substituting one equation into another, we end up with a quadratic equation: \[ x^2 - 2x + 5 = 0 \]. This represents a scenario where a parabola whose roots (solutions) might be real or complex, depending on the discriminant (the expression under the square root in the quadratic formula). The discriminant is calculated as \[ b^2 - 4ac \].

If the discriminant is negative, as in this case where the discriminant is \[ -16 \], the quadratic equation does not yield real number solutions. This means the parabola does not intersect the x-axis, and subsequently, there are no real solutions for the given system.
Linear Equation
A "linear equation" is an equation of the first degree, meaning it involves only the linear terms of the variable(s). It has the form \[ ax + by = c \] for two variables, or simply \[ ax = b \] for one variable. Linear equations typically represent straight lines in a coordinate plane.

In this exercise, we have the linear equation \[ 2x + y = 4 \], which can be rearranged to give \[ y = 4 - 2x \]. This represents a straight line when graphed, and it's often chosen for substitution because of its straightforward structure. Rearranging to express one variable in terms of the other allows you to simplify systems involving both linear and non-linear equations.

The clarity and simplicity of linear equations make them an essential starting point when solving systems. However, as part of this system, even though we expressed \[ y \] in terms of \[ x \], the subsequent substitution into the quadratic format led us to discover that no real solution exists.
No Real Solution
The concept of "no real solution" arises when an equation or a system of equations yields results that are not real numbers. Real numbers are all the numbers that can be found on the number line, including all the rational and irrational numbers, but not imaginary numbers.

In our case, after substitution and simplification, the quadratic equation \[ x^2 - 2x + 5 = 0 \] has a negative discriminant. This indicates that the solutions for \[ x \] are complex numbers, not real ones. Complex numbers involve the square root of a negative number, typically expressed with the imaginary unit \[ i \], where \[ i^2 = -1 \].

Systems with no real solution often imply that the equations represent lines or curves that do not cross each other in the real plane. This scenario underscores the fact that while mathematical systems can be solved, not all will have solutions within the realm of real numbers.

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Most popular questions from this chapter

A theater is presenting a program for students and their parents on drinking and driving. The proceeds will be donated to a local alcohol information center. Admission is \(\$ 2.00\) for parents and \(\$ 1.00\) for students. However, the situation has two constraints: The theater can hold no more than 150 people and every two parents must bring at least one student. How many parents and students should attend to raise the maximum amount of money?

Exercises 116-118 will help you prepare for the material covered in the next section. a. Graph the solution set of the system: $$\left\\{\begin{aligned} x & \geq 0 \\ y & \geq 0 \\ 3 x-2 x & \leq 6 \\ y & \leq-x+7 .\end{aligned}\right.$$ b. List the points that form the corners of the graphed region in part (a). c. Evaluate \(2 x+5 y\) at each of the points obtained in part (b).

Use a system of linear equations to solve. Looking for Mr. Goodbar? It's probably not a good idea if you want to look like Mr. Universe or Julia Roberts. The graph shows the four candy bars with the highest fat content, representing grams of fat and calories in each bar. Based on the graph. (GRAPH CAN'T COPY) A new restaurant is to contain two-seat tables and four-seat tables. Fire codes limit the restaurant's maximum occupancy to 56 customers. If the owners have hired enough servers to handle 17 tables of customers, how many of each kind of table should they purchase?

Describe a situation in your life in which you would really like to maximize something, but you are limited by at least two constraints. Can linear programming be used in this situation? Explain your answer.

Without graphing, in Exercises 73–76, determine if each system has no solution or infinitely many solutions. $$\left\\{\begin{array}{l} 3 x+y<9 \\ 3 x+y>9 \end{array}\right.$$

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