Chapter 3: Problem 32
Find the derivative of the function. \(g(t)=\ln (\ln t)\)
Short Answer
Expert verified
The derivative of \( g(t) = \ln(\ln t) \) is \( \frac{1}{t \ln t} \).
Step by step solution
01
Identify the Function Type
The function given is a composition of functions, specifically the natural logarithm of another natural logarithm: \( g(t) = \ln(\ln t) \). This indicates that you will need to apply the chain rule to find its derivative.
02
Apply the Chain Rule
The chain rule states that the derivative of a composition of two functions is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. Here, let \( u = \ln t \), then \( g(t) = \ln u \).
03
Differentiate the Outer Function
Differentiate the outer function \( g(u) = \ln u \) with respect to \( u \). The derivative is \( \frac{d}{du}[\ln u] = \frac{1}{u} \).
04
Differentiate the Inner Function
Differentiate the inner function \( u(t) = \ln t \) with respect to \( t \). The derivative is \( \frac{d}{dt}[\ln t] = \frac{1}{t} \).
05
Combine the Derivatives
Now, apply the chain rule by multiplying the derivative of the outer function by the derivative of the inner function: \( \frac{d}{dt}g(t) = \frac{1}{\ln t} \cdot \frac{1}{t} = \frac{1}{t \ln t} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a powerful tool in calculus for finding the derivative of composite functions. When you have a function inside another function, like in the exercise with \( g(t) = \ln(\ln t) \), understanding how to use the chain rule is essential.
Here's the basic idea of the chain rule: if you have two functions, say \( f \, \text{and} \, g \), where \( f(g(x)) \) is a composition of these two functions, its derivative is given by the formula:
Here's the basic idea of the chain rule: if you have two functions, say \( f \, \text{and} \, g \), where \( f(g(x)) \) is a composition of these two functions, its derivative is given by the formula:
- Find the derivative of the outer function \( f \), evaluating it at the inner function \( g(x) \).
- Find the derivative of the inner function \( g \).
- Multiply these two derivatives.
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is a logarithm to the base \( e \), where \( e \) is approximately 2.71828. It is a common mathematical function used in calculus, especially when dealing with exponential growth.
- The natural logarithm is useful because of its unique properties, such as \( \ln(e^x) = x \).
- In calculus, one fundamental property is that the derivative of \( \ln x \) is \( \frac{1}{x} \).
- This makes the natural logarithm a powerful tool in differentiation, simplifying calculations significantly.
Composition of Functions
Composition of functions involves inserting one function inside another, creating a new function. When differentiating such compositions, as seen in the exercise with \( g(t) = \ln(\ln t) \), this can initially seem daunting.
To get a clear picture, consider this: if \( g(t) = f(u) \) and \( u = h(t) \), then \( g(t) = f(h(t)) \) is a composition. Here, it's essential to:
To get a clear picture, consider this: if \( g(t) = f(u) \) and \( u = h(t) \), then \( g(t) = f(h(t)) \) is a composition. Here, it's essential to:
- Identify the outer function (\( f \)) and the inner function (\( h \)).
- Evaluate the composite function step by step.
- Apply differentiation rules through careful observation.