Chapter 3: Problem 52
Let \(f(x)=\sqrt{x}-\frac{1}{2} .\) In trying to use the Newton-Raphson method to find a zero of \(f\), determine what goes wrong when we choose a. \(c_{1}=1\) b. \(c_{1}=4\)
Short Answer
Expert verified
Choosing \(c_1=1\) causes an undefined expression at \(c_2=0\), and \(c_1=4\) results in a negative \(c_2=-2\) which is invalid for \(f(x)=\sqrt{x}-\frac{1}{2}\).
Step by step solution
01
Understand the Problem
We need to find the zero of the function \(f(x) = \sqrt{x} - \frac{1}{2}\) using the Newton-Raphson method. This method requires the derivative \(f'(x)\) and an initial guess \(c_1\). We'll analyze what happens when we choose \(c_1=1\) and \(c_1=4\).
02
Calculate the Derivative
Compute the derivative of the function \(f(x) = \sqrt{x} - \frac{1}{2}\). The derivative is \(f'(x) = \frac{1}{2\sqrt{x}}\).
03
Apply Newton-Raphson Formula
The Newton-Raphson formula is given by \(c_{n+1} = c_n - \frac{f(c_n)}{f'(c_n)}\). We'll apply this formula to both \(c_1 = 1\) and \(c_1 = 4\).
04
Step 4a: Evaluate for c1=1
Start with \(c_1 = 1\). Calculate \(f(1) = \sqrt{1} - \frac{1}{2} = \frac{1}{2}\) and \(f'(1) = \frac{1}{2 \cdot 1} = \frac{1}{2}\). Use the Newton-Raphson formula: \(c_{2} = 1 - \frac{1/2}{1/2} = 0\). This would lead to the evaluation of \(f(0)\), which is not possible as \(\sqrt{0}\) is allowed, but the subsequent zero will not help in further steps.
05
Step 4b: Evaluate for c1=4
Start with \(c_1 = 4\). Calculate \(f(4) = \sqrt{4} - \frac{1}{2} = 2 - \frac{1}{2} = \frac{3}{2}\) and \(f'(4) = \frac{1}{2 \cdot 2} = \frac{1}{4}\). Using the Newton-Raphson formula: \(c_{2} = 4 - \frac{3/2}{1/4} = 4 - 6 = -2\). The result \(c_2 = -2\) is not suitable since \(f(x)\) is defined for non-negative \(x\) only.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative Calculation
When using the Newton-Raphson method, accurately computing the derivative of a function plays a pivotal role in ensuring the method's success. For the function given in the exercise, \( f(x) = \sqrt{x} - \frac{1}{2} \), calculating its derivative means finding how the function changes with respect to \( x \).
This is done by applying derivatives to each term in the function separately. The function \( f(x) = \sqrt{x} \) represents a power function, and its derivative is calculated via the power rule. Knowing that the derivative of \( \sqrt{x} \) is given by \( \frac{1}{2\sqrt{x}} \), the derivative for the entire function becomes:
This is done by applying derivatives to each term in the function separately. The function \( f(x) = \sqrt{x} \) represents a power function, and its derivative is calculated via the power rule. Knowing that the derivative of \( \sqrt{x} \) is given by \( \frac{1}{2\sqrt{x}} \), the derivative for the entire function becomes:
- \( f'(x) = \frac{1}{2\sqrt{x}} \)
Zero of a Function
Finding a zero of a function involves locating an \( x \)-value for which the function evaluates to zero. In simpler terms, it's the point where the graph of the function crosses the \( x \)-axis. For the function \( f(x) = \sqrt{x} - \frac{1}{2} \), we seek an \( x \) such that \( f(x) = 0 \).
The equation \( \sqrt{x} = \frac{1}{2} \) leads us to find that:
Understanding zeros is fundamental in calculus because it involves root-finding, a process applicable in various mathematical and real-world problems. The challenge here is selecting appropriate initial guesses in the Newton-Raphson method to quickly converge to this zero without diverging.
The equation \( \sqrt{x} = \frac{1}{2} \) leads us to find that:
- \( x = \left(\frac{1}{2}\right)^2 = \frac{1}{4} \)
Understanding zeros is fundamental in calculus because it involves root-finding, a process applicable in various mathematical and real-world problems. The challenge here is selecting appropriate initial guesses in the Newton-Raphson method to quickly converge to this zero without diverging.
Initial Guess Selection
One critical component of the Newton-Raphson method is choosing a suitable initial guess \( c_1 \) for starting iterations. The choice of \( c_1 \) can greatly influence whether the method converges to the zero, how fast it converges, or if it diverges altogether.
Inappropriate selection of \( c_1 \) can even lead to mathematically invalid operations, such as taking the square root of a negative number, which occurred in our example. Choosing \( c_1 = 1 \), led the first iteration to a valid calculation but subsequent steps explored invalid domains. On the other hand, \( c_1 = 4 \) created a negative \( c_2 = -2 \), unsuitable for \( f(x) \) since the square root function is defined for non-negative numbers only.
Possible strategies for selecting a good initial guess are:
Inappropriate selection of \( c_1 \) can even lead to mathematically invalid operations, such as taking the square root of a negative number, which occurred in our example. Choosing \( c_1 = 1 \), led the first iteration to a valid calculation but subsequent steps explored invalid domains. On the other hand, \( c_1 = 4 \) created a negative \( c_2 = -2 \), unsuitable for \( f(x) \) since the square root function is defined for non-negative numbers only.
Possible strategies for selecting a good initial guess are:
- Choosing \( c_1 \) close to the expected zero if known.
- Analyzing the function's graph to identify regions where the function approaches zero.
- Avoiding areas where the function derivative might be very small to prevent division by small numbers in the formula.