Chapter 1: Problem 3
Sketch the curves below by eliminating the parameter \(t\). Give the orientation of the curve. $$ x=2 t+4, y=t-1 $$
Short Answer
Expert verified
The parametric form corresponds to the line \(x = 2y + 6\), oriented from bottom left to top right as \(t\) increases.
Step by step solution
01
Express Parameter in Terms of Another Variable
The given equations are parametric equations with a parameter \(t\): \(x = 2t + 4\) and \(y = t - 1\). To eliminate \(t\), we need to express \(t\) in terms of either \(x\) or \(y\). Let's find \(t\) in terms of \(y\):\[ y = t - 1 \]\[ t = y + 1 \].
02
Substitute Expression into Other Equation
Now that we have \(t = y + 1\), substitute it into the equation for \(x\):\[ x = 2t + 4\]\[ x = 2(y + 1) + 4\].
03
Simplify the Equation
Continuing from the substitution, simplify the equation:\[x = 2(y + 1) + 4 \]\[ x = 2y + 2 + 4 \]\[ x = 2y + 6 \].This is the equation of the curve in \(xy\)-plane form, a linear equation in the form of \(x = 2y + 6\).
04
Determine the Orientation
To find the orientation, examine how \(x\) and \(y\) change with \(t\):- As \(t\) increases, \(x = 2t + 4\) increases, so \(x\) increases.- As \(t\) increases, \(y = t - 1\) also increases, so \(y\) increases.Thus, the curve is oriented with both \(x\) and \(y\) increasing as \(t\) increases.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Eliminating the Parameter
Eliminating the parameter is a useful technique when working with parametric equations. It allows us to simplify the equations by removing the parameter, in this case, the parameter is \( t \). Simplifying equations enables us to better understand the relationship between \( x \) and \( y \) directly. For the given exercise, we started with the equations \( x = 2t + 4 \) and \( y = t - 1 \). We aimed to write \( t \) in terms of \( y \) because it made the substitution straightforward: we rearranged \( y = t - 1 \) to get \( t = y + 1 \).
This new expression for \( t \) was substituted back into the \( x \) equation: \( x = 2(y + 1) + 4 \). After expanding and simplifying, this gave us \( x = 2y + 6 \). This is a clear, non-parametric equation in terms of \( x \) and \( y \), describing a line in the plane without reference to any parameter.
This new expression for \( t \) was substituted back into the \( x \) equation: \( x = 2(y + 1) + 4 \). After expanding and simplifying, this gave us \( x = 2y + 6 \). This is a clear, non-parametric equation in terms of \( x \) and \( y \), describing a line in the plane without reference to any parameter.
- The primary goal is to connect \( x \) and \( y \) without \( t \).
- It simplifies analyzing and plotting the curve.
Curve Sketching
Once the parameter has been eliminated, we are left with a more traditional algebraic equation. In this task, the result was \( x = 2y + 6 \), which is a linear equation. To sketch the curve, recognize that this equation represents a line in the Cartesian plane. Linear equations take the form \( y = mx + b \) where \( m \) is the slope and \( b \) is the y-intercept. However, for this line, it is expressed as \( x = 2y + 6 \), implying that rearranging it might help to find more familiar traits.
Rearranged, it is \( y = \frac{x-6}{2} \). This form tells us the slope of the line is \( \frac{1}{2} \) and the y-intercept is \(-3\). Curve sketching involves:
Rearranged, it is \( y = \frac{x-6}{2} \). This form tells us the slope of the line is \( \frac{1}{2} \) and the y-intercept is \(-3\). Curve sketching involves:
- Knowing that for every increase in \( y \), \( x \) increases twice as much, as \( x \) depends directly on \( 2y \).
- The line crosses the y-axis at \(-3\), which can be a critical feature in drawing it.
Orientation of the Curve
Understanding the orientation of the curve in a parametric equation involves looking at how \( x \) and \( y \) change with respect to \( t \). Orientation tells us the direction in which the curve is traced as \( t \) moves from its initial to final values. For the parametric equations \( x = 2t + 4 \) and \( y = t - 1 \):
- As \( t \) increases, \( x = 2t + 4 \) also increases because the coefficient of \( t \) is positive.
- Similarly, \( y = t - 1 \) increases with \( t \), as again the coefficient for \( t \) is positive.