/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Sketch the parametric equations ... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the parametric equations by eliminating the parameter. Indicate any asymptotes of the graph. $$ x=\ln (2 t), \quad y=t^{2} $$

Short Answer

Expert verified
The curve is \( y = \frac{e^{2x}}{4} \) with a horizontal asymptote at \( y = 0 \).

Step by step solution

01

Express the Parameter from One Equation

Start by expressing the parameter \( t \) from the equation for \( x \). The equation given is \( x = \ln(2t) \). Solve for \( t \): \( 2t = e^x \), so \( t = \frac{e^x}{2} \).
02

Substitute to Eliminate the Parameter

Use the expression for \( t \) found in Step 1 and substitute it into the equation for \( y \). So, \( y = (t^2) = \left(\frac{e^x}{2}\right)^2 = \frac{e^{2x}}{4} \). This is the Cartesian equation of the curve.
03

Sketch the Graph

The Cartesian equation \( y = \frac{e^{2x}}{4} \) is an exponential function. Its graph is symmetric with respect to the y-axis since \( e^{2x} \) is always positive, leading to \( y > 0 \). Furthermore, as \( x \) approaches negative infinity, \( y \) approaches zero, but never reaches it.
04

Determine Asymptotes

Examine the behavior of the function to find any asymptotes. Here, as \( x \to -\infty \), \( y \to 0 \). Thus, the line \( y = 0 \) is a horizontal asymptote to the graph. There are no vertical asymptotes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eliminating the Parameter
Eliminating the parameter in parametric equations means converting them into a single equation without the parameter. Here, the parameter is \( t \). Start by finding \( t \) from one of the given parametric equations. In this case, from the equation \( x = \ln(2t) \), solve for \( t \) to get \( t = \frac{e^x}{2} \).
Next, substitute this expression for \( t \) into the second parametric equation \( y = t^2 \). This gives us \( y = \left(\frac{e^x}{2}\right)^2 \), which simplifies to \( y = \frac{e^{2x}}{4} \).
This equation, \( y = \frac{e^{2x}}{4} \), is referred to as the Cartesian equation, derived by eliminating the parameter \( t \). No longer do we need \( t \) to understand the relationship between \( x \) and \( y \).
Cartesian Equation
A Cartesian equation describes a curve using two coordinates, typically \( x \) and \( y \), without an external parameter. By eliminating the parameter \( t \) from a parametric set of equations, you obtain such an equation.
In our example, once we solved for \( t \) and substituted into the equation for \( y \), the resulting Cartesian equation was: \( y = \frac{e^{2x}}{4} \).
This equation depicts a continuous relationship where the output \( y \) is dependent on \( x \). In essence, Cartesian equations simplify the complexity of parametric representations, providing a clearer picture of how \( y \) depends on \( x \) directly.
Asymptotes
Asymptotes are lines that a graph approaches but never touches or crosses. They help understand the behavior of a function as it moves towards infinity in either direction.
To find the asymptotes, examine the function's behavior at the extremes of its domain. In the equation \( y = \frac{e^{2x}}{4} \), as \( x \) approaches negative infinity, the value of \( y \) approaches zero.
This behavior indicates the presence of a horizontal asymptote at \( y = 0 \). This means the graph gets closer and closer to this line but doesn't actually touch it as \( x \) decreases indefinitely.
There are no vertical asymptotes in this particular equation, as there are no values of \( x \) that lead to undefined \( y \)-values.
Graph Sketching
Graph sketching is the process of visually representing a function based on its equation. Having the Cartesian equation, \( y = \frac{e^{2x}}{4} \), serves as a guide to this process.
Begin by identifying key features such as intercepts, symmetry, and asymptotes, which were discussed earlier. This equation yields a graph that is symmetric about the y-axis because \( e^{2x} \) remains positive for all values of \( x \).
When sketching, note that all \( y \)-values are positive, as \( \frac{e^{2x}}{4} \) is always greater than zero. The closest the graph gets to the x-axis (\( y = 0 \)) is defined by its horizontal asymptote.
  • The graph starts near the horizontal asymptote and curves upwards as \( x \) increases.
  • No parts of the curve dip below the x-axis.
With these points clear, you can confidently sketch the curve to visualize its growth and limitations.

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