Chapter 6: Problem 133
Find the smallest value of \(n\) such that the remainder estimate \(\left|R_{n}\right| \leq \frac{M}{(n+1) !}(x-a)^{n+1}\), where \(M\) is the maximum value of \(\left|f^{(n+1)}(z)\right|\) on the interval between \(a\) and the indicated point, yields \(\left|R_{n}\right| \leq \frac{1}{1000}\) on the indicated interval. $$ f(x)=\cos x \text { on }\left[-\frac{\pi}{2}, \frac{\pi}{2}\right], a=0 $$
Short Answer
Step by step solution
Understand the Function and Interval
Derivative Calculation
Find Maximum \( M \) for \( n+1 \) Derivative
Set Up the Remainder Formula and Solve
Calculate \( n \, \text{with Integer Trial} \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosine Function
Maximum Value Estimation
- The periodic and bounded nature of sine and cosine eases the process of finding maximum values.
- Being consistent in estimating \( M \) across intervals helps achieve better approximations in Taylor series.
Derivative Calculation
- \( f'(x) = -\sin x \)
- \( f''(x) = -\cos x \)
- \( f'''(x) = \sin x \)
- \( f^{(4)}(x) = \cos x \)
Inequality Solving
- Start with initial simple estimates for \( n \).
- Iteratively try successive values, increasing \( n \) till the inequality holds.
- This approach guarantees accuracy in defining bounds for Taylor series approximation.