Chapter 6: Problem 132
Find the smallest value of \(n\) such that the remainder estimate \(\left|R_{n}\right| \leq \frac{M}{(n+1) !}(x-a)^{n+1}\), where \(M\) is the maximum value of \(\left|f^{(n+1)}(z)\right|\) on the interval between \(a\) and the indicated point, yields \(\left|R_{n}\right| \leq \frac{1}{1000}\) on the indicated interval. $$ f(x)=\sin x \text { on }[-\pi, \pi], a=0 $$
Short Answer
Step by step solution
Identify the Function and its Derivatives
Determine Maximum M within Interval
Apply Remainder Estimation Formula
Experiment with Values of n
Confirm Smallest n
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor Series
Remainder Estimate
Sine Function
Derivative
- First derivative: \( f'(x) = \,\cos x\, \)
- Second derivative: \( f''(x) = -\sin x \)
- Third derivative: \( f'''(x) = -\cos x \)
- Fourth derivative: \( f^{(4)}(x) = \sin x \)