Chapter 4: Problem 1
In each of Exercises \(1-16,\) use l'Hôpital's Rule to find the limit, if it exists. \(\lim _{x \rightarrow 0}\left(1-e^{x}\right) / x\)
Short Answer
Expert verified
The limit is \(-1\).
Step by step solution
01
Identify the Indeterminate Form
To use l'Hôpital's Rule, first check if the limit \[ \lim _{x \rightarrow 0}\left(1-e^{x}\right) / x \]produces an indeterminate form of \( \frac{0}{0} \). Substituting \( x = 0 \), we have \( 1 - e^0 = 0 \) in the numerator and \( x = 0 \) in the denominator, confirming both are zero. Thus, this is an indeterminate form \( \frac{0}{0} \).
02
Apply l'Hôpital's Rule
l'Hôpital's Rule can be applied to indeterminate forms of \( \frac{0}{0} \) by taking the derivative of the numerator and denominator separately.The derivative of the numerator \( 1 - e^x \) is \( -e^x \), and the derivative of the denominator \( x \) is \( 1 \). Using l'Hôpital's Rule, the limit becomes:\[\lim _{x \rightarrow 0} \frac{-e^x}{1}\]
03
Compute the New Limit
Now, evaluate the new limit:\[\lim _{x \rightarrow 0} -e^x\]Substitute \( x = 0 \) into \( -e^x \):\(-e^0 = -1\).Thus, the limit evaluates to \(-1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Indeterminate Form
When trying to evaluate a limit, you might stumble upon expressions that seem undefined. This can be due to an indeterminate form, which is a result that does not provide enough information to determine the limit's value immediately.
One common indeterminate form occurs as \( \frac{0}{0} \). When both the numerator and denominator of a fraction approach zero as \( x \) approaches a certain point, like in the function \( \lim _{x \rightarrow 0}\left(1-e^{x}\right) / x \), it signals an indeterminate form.
One common indeterminate form occurs as \( \frac{0}{0} \). When both the numerator and denominator of a fraction approach zero as \( x \) approaches a certain point, like in the function \( \lim _{x \rightarrow 0}\left(1-e^{x}\right) / x \), it signals an indeterminate form.
- This does not mean that the limit does not exist; rather, it requires more work to solve.
- Recognizing an indeterminate form is the first step before applying other mathematical rules such as l'Hôpital's Rule.
Limit Evaluation
Limit evaluation is a fundamental concept in calculus used to find the value that a function approaches as the input approaches a certain point. When standard algebraic simplification isn’t enough, you may need more advanced methods. In the case where an indeterminate form is present, l'Hôpital's Rule is a powerful tool.
To evaluate limits using l'Hôpital's Rule:
This process simplifies finding what value the function heads towards as \( x \) nears a point.
To evaluate limits using l'Hôpital's Rule:
- Ensure that the function results in an indeterminate form such as \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \).
- Take the derivative of both the numerator and denominator separately.
- Re-evaluate the limit with these new functions.
This process simplifies finding what value the function heads towards as \( x \) nears a point.
Derivatives
Derivatives play a crucial role when discussing limit evaluation techniques like l'Hôpital's Rule. Derivatives express the rate at which a function is changing at any point. They are central to transforming complex limits into easier-to-handle forms.
In the context of using l’Hôpital's Rule, here's how derivatives are typically employed:
In the context of using l’Hôpital's Rule, here's how derivatives are typically employed:
- Calculating the derivative of the numerator lets us understand how the top part of a fraction behaves near a given point.
- Likewise, the derivative of the denominator helps identify the behavior of the bottom part.