Chapter 4: Problem 1
Calculate the indefinite integral. $$ \int\left(x^{2}-5 x\right) d x $$
Short Answer
Expert verified
\( \frac{x^3}{3} - \frac{5x^2}{2} + C \)
Step by step solution
01
Understand the Problem
We need to evaluate the indefinite integral \( \int (x^2 - 5x) \, dx \). An indefinite integral represents the antiderivative of a function.
02
Break Down the Integral
The integral can be split into two separate integrals: \( \int x^2 \, dx \) and \( \int -5x \, dx \). This follows from the property of integrals that allows us to handle each term separately.
03
Integrate Each Term
Find the antiderivative of each term independently. The antiderivative of \( x^2 \) is \( \frac{x^3}{3} \), and the antiderivative of \( -5x \) is \( -\frac{5x^2}{2} \).
04
Combine the Results
Combine the antiderivatives to get \( \int (x^2 - 5x) \, dx = \frac{x^3}{3} - \frac{5x^2}{2} + C \). Remember to add the constant of integration \( C \) because the integral is indefinite.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Antiderivative
When we talk about an *indefinite integral*, we're really looking for the antiderivative of a given function. It's important to understand that finding the antiderivative is like reverse-engineering differentiation.
For instance:
Breaking down each part: the antiderivative of \(x^2\) gives us \(\frac{x^3}{3}\), because differentiating \(\frac{x^3}{3}\) brings us back to \(x^2\). Similarly, for \(-5x\), its antiderivative is \(-\frac{5x^2}{2}\). Just like a puzzle, placing the antiderivatives of these individual terms back together reveals our original integral.
For instance:
- We know that the derivative of a function gives us its rate of change.
- The antiderivative, on the other hand, gives us back the original function from its rate of change.
Breaking down each part: the antiderivative of \(x^2\) gives us \(\frac{x^3}{3}\), because differentiating \(\frac{x^3}{3}\) brings us back to \(x^2\). Similarly, for \(-5x\), its antiderivative is \(-\frac{5x^2}{2}\). Just like a puzzle, placing the antiderivatives of these individual terms back together reveals our original integral.
Integral Calculus
Integral calculus is a broad and fascinating topic that essentially deals with accumulation and finding total values. When thinking about integrals:
This is a powerful concept because it allows mathematicians and scientists to reverse the "derivative" process, filling in many missing pieces when dealing with real-world applications or simply solving mathematical puzzles. Integral calculus helps bridge the gap between understanding rates of change and total accumulation, making it a crucial tool in many fields.
- *Definite integrals* help us understand the area under a curve over a specific interval.
- *Indefinite integrals*, on the other hand, describe general antiderivatives and give us potential "original functions."
This is a powerful concept because it allows mathematicians and scientists to reverse the "derivative" process, filling in many missing pieces when dealing with real-world applications or simply solving mathematical puzzles. Integral calculus helps bridge the gap between understanding rates of change and total accumulation, making it a crucial tool in many fields.
Constant of Integration
The constant of integration \( C \) is an essential component whenever we find an indefinite integral. It might seem like a small detail, but it has a big role.
When we differentiate a function, any constant term vanishes. This means there are countless possible original functions that could provide the same derivative. This uncertainty manifests as the constant \( C \) in our antiderivative solutions.
Think of \( C \) as a way to "complete the picture." Without it, we'd miss out on various versions of possible solutions, each differing only by a constant amount. In the context of our problem:
When we differentiate a function, any constant term vanishes. This means there are countless possible original functions that could provide the same derivative. This uncertainty manifests as the constant \( C \) in our antiderivative solutions.
Think of \( C \) as a way to "complete the picture." Without it, we'd miss out on various versions of possible solutions, each differing only by a constant amount. In the context of our problem:
- Once we evaluate \( \int (x^2 - 5x) \, dx \), we obtain \( \frac{x^3}{3} - \frac{5x^2}{2} + C \).
- Here, \( C \) represents all those infinite possibilities that share the same derivative.