Chapter 21: Problem 1
Decide if the parameterization describes a curve or a surface. $$\vec{r}(s)=s \vec{i}+(3-s) \vec{j}+s^{2} \vec{k}$$
Short Answer
Expert verified
The parameterization describes a curve.
Step by step solution
01
Understand the parameterization
The given parameterization is \( \vec{r}(s) = s \vec{i} + (3-s) \vec{j} + s^2 \vec{k} \). This expression is a function of a single variable, \( s \). This means that the function describes a path traced out as \( s \) varies.
02
Analyze dimensionality
Since the parameterization depends on only one parameter, \( s \), it suggests that it traces a one-dimensional set of points in three-dimensional space. This is characteristic of a curve.
03
Conclude the nature of the parameterization
Given that \( \vec{r}(s) \) is defined solely in terms of a single parameter \( s \), without any other independent variable, the parameterization describes a curve rather than a surface.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Functions
Vector functions are a powerful tool to represent curves and surfaces in mathematics. A vector function, such as \( \vec{r}(s) = s \vec{i} + (3-s) \vec{j} + s^2 \vec{k} \), is an expression that maps a number, or parameter, to a vector in space. The parameter, here represented by \( s \), controls the position on the path described by the vector function.
The components of the vector \( \vec{r}(s) \) correspond to directions in space. Each term in the vector function is multiplied by the vector unit: \( \vec{i} \), \( \vec{j} \), and \( \vec{k} \), which denote the x, y, and z axes, respectively. As \( s \) changes, the values output by the vector function change, tracing out a path through space.
The components of the vector \( \vec{r}(s) \) correspond to directions in space. Each term in the vector function is multiplied by the vector unit: \( \vec{i} \), \( \vec{j} \), and \( \vec{k} \), which denote the x, y, and z axes, respectively. As \( s \) changes, the values output by the vector function change, tracing out a path through space.
- The function describes how to move along this path for different values of \( s \).
- It involves a combination of linear and quadratic terms that describe the changes in position.
- Because it uses vectors, it can easily be adapted to a variety of problems in physics and engineering.
Three-Dimensional Space
In mathematics and physics, three-dimensional space is where we naturally describe our physical universe. It consists of three axes: the x-axis, the y-axis, and the z-axis, which together define any point in space using coordinates \( (x, y, z) \). The vector function \( \vec{r}(s) = s \vec{i} + (3-s) \vec{j} + s^2 \vec{k} \) exists in this space.
- The vector \( s \vec{i} + (3-s) \vec{j} + s^2 \vec{k} \) specifies a position as a combination of each axis.
- The coordinate \( s \vec{i} \) represents how far to the right or left to move along the x-axis.
- The term \( (3-s) \vec{j} \) specifies movement up or down along the y-axis.
- The quadratic \( s^2 \vec{k} \) indicates movement parallel to the z-axis, affected by the square of the parameter \( s \).
One-Dimensional Sets
In mathematics, a one-dimensional set is a collection of points that can be described by one parameter, typically embodying the simplest possible curve in space. The given parameterization \( \vec{r}(s) = s \vec{i} + (3-s) \vec{j} + s^2 \vec{k} \) represents a one-dimensional set because it depends solely on the single variable \( s \).
- Since there is only one parameter, any change in \( s \) produces a unique point on the curve.
- This continuous, smooth path in the three-dimensional space forms a one-dimensional object.
- Unlike a two-dimensional or surface parameterization, which would require two parameters (such as \( u \) and \( v \)), a one-dimensional parameterization dwells on how one parameter affects the positioning of points along a curve.