Chapter 20: Problem 7
calculate the circulation, \(\int_{C} \vec{F} \cdot d \vec{r},\) in two ways, directly and using Stokes" Theorem. \(\vec{F}=x y \vec{i}+y z \vec{j}+x z \vec{k}\) and \(C\) is the boundary of \(S\) the surface \(z=1-x^{2}\) for \(0 \leq x \leq 1\) and \(-2 \leq y \leq 2\) oriented upward. Sketch \(S\) and \(C\)
Short Answer
Step by step solution
Parametrize C and Compute Directly
Use Stokes' Theorem
Perform Calculations
Interpretation and Comparison
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Circulation Integral
To compute this, you'll typically need to break the path \( C \) into segments if it forms more complex geometries like a rectangle or a polygon. You then calculate the line integral over each segment:
- Determine the vector field components \( \vec{F} = xy \hat{i} + yz \hat{j} + xz \hat{k} \).
- Evaluate each segment separately along \( C \), calculating \( \vec{F} \cdot d\vec{r} \) for each.
Surface Parametrization
To parametrize a surface, choose parameters that describe all points on it. Usually, these parameters are \( x \) and \( y \), especially if the surface is given explicitly in terms of \( z \).
- The parametrization for our surface might look like \( \vec{r}(x, y) = x \hat{i} + y \hat{j} + (1 - x^2) \hat{k} \).
- This representation converts our surface into a space we can integrate over, matching the region bounds.
Curl of a Vector Field
\[ \text{curl}(\vec{F}) = abla \times \vec{F} \]
This is computed as:
- For the \( \hat{i} \) component, \( \frac{\partial}{\partial y}(xz) - \frac{\partial}{\partial z}(yz) \).
- For the \( \hat{j} \) component, \( \frac{\partial}{\partial z}(xy) - \frac{\partial}{\partial x}(xz) \).
- For the \( \hat{k} \) component, \( \frac{\partial}{\partial x}(yz) - \frac{\partial}{\partial y}(xy) \).
Line Integral
For a vector field \( \vec{F} \), a line integral along a curve \( C \) is computed as:
\[ \int_{C} \vec{F} \cdot d\vec{r} \]
- It involves calculating the dot product of \( \vec{F} \) and \( d\vec{r} \), which is a differential along the curve.
- This computation may include breaking down the path into manageable segments and then summing up the parts.