Chapter 20: Problem 11
In Exercises \(6-13,\) compute the curl of the vector field. $$\vec{F}=e^{x} \vec{i}+\cos y \vec{j}+e^{z} \vec{k}$$
Short Answer
Expert verified
The curl of \( \vec{F} \) is \( \vec{0} \).
Step by step solution
01
Recall the definition of Curl
For a vector field \( \vec{F} = P\vec{i} + Q\vec{j} + R\vec{k} \), the curl is defined as \( abla \times \vec{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right) \vec{i} + \left( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \right) \vec{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \vec{k} \).
02
Identify the components of \(\vec{F}\)
The given vector field is \( \vec{F} = e^x \vec{i} + \cos y \vec{j} + e^z \vec{k} \). Thus, \( P = e^x \), \( Q = \cos y \), and \( R = e^z \).
03
Compute \( \frac{\partial R}{\partial y} \) and \( \frac{\partial Q}{\partial z} \)
For \( \frac{\partial R}{\partial y} \): since \( R = e^z \) is independent of \( y \), \( \frac{\partial R}{\partial y} = 0 \). For \( \frac{\partial Q}{\partial z} \): since \( Q = \cos y \) is independent of \( z \), \( \frac{\partial Q}{\partial z} = 0 \).
04
Compute \( \frac{\partial P}{\partial z} \) and \( \frac{\partial R}{\partial x} \)
For \( \frac{\partial P}{\partial z} \): since \( P = e^x \) is independent of \( z \), \( \frac{\partial P}{\partial z} = 0 \). For \( \frac{\partial R}{\partial x} \): since \( R = e^z \) is independent of \( x \), \( \frac{\partial R}{\partial x} = 0 \).
05
Compute \( \frac{\partial Q}{\partial x} \) and \( \frac{\partial P}{\partial y} \)
For \( \frac{\partial Q}{\partial x} \): since \( Q = \cos y \) is independent of \( x \), \( \frac{\partial Q}{\partial x} = 0 \). For \( \frac{\partial P}{\partial y} \): since \( P = e^x \) is independent of \( y \), \( \frac{\partial P}{\partial y} = 0 \).
06
Substitute to find the Curl
Now substitute the computed partial derivatives into the formula: \[ abla \times \vec{F} = \left( 0 - 0 \right) \vec{i} + \left( 0 - 0 \right) \vec{j} + \left( 0 - 0 \right) \vec{k} = \vec{0} \].
07
Conclusion
The curl of the vector field \( \vec{F} = e^x \vec{i} + \cos y \vec{j} + e^z \vec{k} \) is \( \vec{0} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curl of a Vector Field
The concept of the "curl" of a vector field is foundational in vector calculus, often used to describe the amount of rotation a vector field induces around a point. Imagine a small paddle wheel placed within a fluid flow. The way the paddle wheel turns can give you an idea of the curl at that point. More precisely, the curl measures how the flow swirls around a given point. Mathematically, this involves the cross product.
For a given vector field \( \vec{F} = P\vec{i} + Q\vec{j} + R\vec{k} \), the curl \( abla \times \vec{F} \) is found through partial derivatives comparing different components of the field. It creates a new vector field:\[ abla \times \vec{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right) \vec{i} + \left( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \right) \vec{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \vec{k} \].
In the example provided, because all the partial derivatives lead to zero, the result is a vector with all zero components, indicating that the field does not induce any rotation at any point.
For a given vector field \( \vec{F} = P\vec{i} + Q\vec{j} + R\vec{k} \), the curl \( abla \times \vec{F} \) is found through partial derivatives comparing different components of the field. It creates a new vector field:\[ abla \times \vec{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right) \vec{i} + \left( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \right) \vec{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \vec{k} \].
In the example provided, because all the partial derivatives lead to zero, the result is a vector with all zero components, indicating that the field does not induce any rotation at any point.
Partial Derivatives
Partial derivatives are a crucial tool in vector calculus and multi-variable calculus. They represent the rate of change of a function concerning one variable, while keeping others constant. Imagine you are examining a landscape, and you want to know how steeply it rises or falls as you walk in a straight line in one direction. That's similar to a partial derivative.
For a function \( f(x, y, z) \), the partial derivative with respect to \( x \) is denoted as \( \frac{\partial f}{\partial x} \), and it looks at how \( f \) changes as \( x \) changes, if \( y \) and \( z \) remain fixed. In practice:
For a function \( f(x, y, z) \), the partial derivative with respect to \( x \) is denoted as \( \frac{\partial f}{\partial x} \), and it looks at how \( f \) changes as \( x \) changes, if \( y \) and \( z \) remain fixed. In practice:
- To find \( \frac{\partial R}{\partial y} \), one must differentiate \( R \) concerning \( y \) while treating other variables as constants.
- The same logic applies to\( \frac{\partial Q}{\partial z} \), \( \frac{\partial P}{\partial z} \), and so on.
Vector Fields
Vector fields are a fundamental concept in physics and mathematics used to represent the spatial distribution of vectors in a given environment. Think of a weather map showing the direction and speed of wind blowing across a region. The arrows indicate both the direction and the magnitude of the wind, but at each point in space.
In mathematics, a vector field is often expressed as \( \vec{F} = P\vec{i} + Q\vec{j} + R\vec{k} \), where \( P \), \( Q \), and \( R \) are functions of variables like \( x \), \( y \), and \( z \). This setup helps model various phenomena:
In mathematics, a vector field is often expressed as \( \vec{F} = P\vec{i} + Q\vec{j} + R\vec{k} \), where \( P \), \( Q \), and \( R \) are functions of variables like \( x \), \( y \), and \( z \). This setup helps model various phenomena:
- Fluid flow: Describing how fluids like water and air move over time.
- Magnetic fields: Visualizing forces around magnets and electric currents.
- Gravitational fields: Understanding the forces influencing mass bodies.