Chapter 19: Problem 44
Explain what is wrong with the statement. $$\operatorname{div}(2 x \vec{i})=2 \vec{i}$$
Short Answer
Expert verified
The divergence is 2, not the vector \(2 \vec{i}\).
Step by step solution
01
Understand the Divergence Operation
The divergence of a vector field \( \vec{F} = P \vec{i} + Q \vec{j} + R \vec{k} \) in 3D is given by \( \operatorname{div}\vec{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \). In our case, the vector field is \( 2x \vec{i} \), which implies \( P = 2x \), \( Q = 0 \), and \( R = 0 \).
02
Calculate Partial Derivatives
For the given vector field \( 2x \vec{i} \), calculate the partial derivatives. We have \( \frac{\partial P}{\partial x} = \frac{\partial}{\partial x}(2x) = 2 \). Since \( Q = 0 \), \( \frac{\partial Q}{\partial y} = 0 \), and since \( R = 0 \), \( \frac{\partial R}{\partial z} = 0 \).
03
Compute the Divergence
Now that we have the partial derivatives, compute the divergence. Substituting into the formula gives us \( \operatorname{div}(2x \vec{i}) = 2 + 0 + 0 = 2 \).
04
Identify the Error in the Original Statement
The initial statement \( \operatorname{div}(2x \vec{i}) = 2 \vec{i} \) is incorrect because divergence is a scalar, not a vector. The correct divergence is the scalar value \( 2 \), not the vector \( 2 \vec{i} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Field
A vector field is a mathematical construct where each point in space is associated with a vector. Vectors have both magnitude and direction. When dealing with vector fields, like in physics or engineering, we often express them in terms of the standard basis vectors \( \vec{i} \), \( \vec{j} \), and \( \vec{k} \).
In the context of the exercise, the vector field is given by \( 2x \vec{i} \). This means that at any point \( (x, y, z) \), the field assigns the vector \( 2x \vec{i} \), implying that the field is dependent only on the \( x \)-coordinate, while the components in the \( y \)- and \( z \)-directions are zero.
Understanding the structure of a vector field such as \( 2x \vec{i} \) is crucial for computing operations like divergence, which tell us how the field spreads out from a point.
In the context of the exercise, the vector field is given by \( 2x \vec{i} \). This means that at any point \( (x, y, z) \), the field assigns the vector \( 2x \vec{i} \), implying that the field is dependent only on the \( x \)-coordinate, while the components in the \( y \)- and \( z \)-directions are zero.
Understanding the structure of a vector field such as \( 2x \vec{i} \) is crucial for computing operations like divergence, which tell us how the field spreads out from a point.
Partial Derivatives
Partial derivatives are tools used to measure how a function changes as one of its variables changes, holding all others constant. This becomes particularly useful when analyzing vector fields that depend on multiple variables, like \( x \), \( y \), and \( z \).
For the vector field \( 2x \vec{i} \), we only need to consider the partial derivative of \( P = 2x \) with respect to \( x \), because the other components, \( Q \) and \( R \), are zero. Computing the partial derivative \( \frac{\partial (2x)}{\partial x} \) results in \( 2 \).
Partial derivatives are fundamental in calculus and are used to form the divergence of a vector field, which measures the rate at which volume expands or contracts at a point.
For the vector field \( 2x \vec{i} \), we only need to consider the partial derivative of \( P = 2x \) with respect to \( x \), because the other components, \( Q \) and \( R \), are zero. Computing the partial derivative \( \frac{\partial (2x)}{\partial x} \) results in \( 2 \).
Partial derivatives are fundamental in calculus and are used to form the divergence of a vector field, which measures the rate at which volume expands or contracts at a point.
Scalar Result
A scalar is a single number, in contrast to a vector, which has multiple components. The concept of scalar results comes into play when we compute the divergence of a vector field.
The divergence of any vector field results in a scalar, rather than a vector. This scalar value indicates how much the field diverges from or converges to a point. In our exercise, the divergence of \( 2x \vec{i} \) is \( 2 \), showing a uniform expansion from any point along the direction of \( \vec{i} \).
A fundamental error in understanding divergence is assuming the result remains a vector. In mathematical operations on vector fields, ensuring the correct type of result (vector or scalar) is key to avoiding misinterpretation and errors.
The divergence of any vector field results in a scalar, rather than a vector. This scalar value indicates how much the field diverges from or converges to a point. In our exercise, the divergence of \( 2x \vec{i} \) is \( 2 \), showing a uniform expansion from any point along the direction of \( \vec{i} \).
A fundamental error in understanding divergence is assuming the result remains a vector. In mathematical operations on vector fields, ensuring the correct type of result (vector or scalar) is key to avoiding misinterpretation and errors.