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Find the flux of \(\vec{F}\) through the closed cylinder of \(\mathrm{ra}\) dius \(2,\) centered on the \(z\) -axis, with \(3 \leq z \leq 7,\) if \(\vec{F}=\left(x+3 e^{y z}\right) \vec{i}+\left(\ln \left(x^{2} z^{2}+1\right)+y\right) \vec{j}+z \vec{k}\).

Short Answer

Expert verified
The flux through the cylinder is \( 48\pi \).

Step by step solution

01

Understanding the Problem

We need to find the flux of the vector field \( \vec{F} \) through a closed cylinder centered on the z-axis with a given radius and height, defined by \( 3 \leq z \leq 7 \). The vector field is \( \vec{F}=(x+3e^{yz})\mathbf{i}+(\ln(x^2z^2+1)+y)\mathbf{j}+z\mathbf{k} \).
02

Using the Divergence Theorem

The Divergence Theorem relates the flux of a vector field through a closed surface to the volume integral of the divergence of the field. Mathematically, it states: \( \iint_{S} \vec{F} \cdot \vec{n} \, dS = \iiint_{V} abla \cdot \vec{F} \, dV \). Here, \( S \) is our closed surface (the cylinder), and \( V \) is the volume it encloses.
03

Calculating the Divergence of \( \vec{F} \)

Calculate \( abla \cdot \vec{F} \). We find the partial derivatives: \( \frac{\partial}{\partial x}(x + 3e^{yz}) = 1 \), \( \frac{\partial}{\partial y}(\ln(x^2z^2+1) + y) = 1 \), and \( \frac{\partial}{\partial z}(z) = 1 \). Thus, \( abla \cdot \vec{F} = 1 + 1 + 1 = 3 \).
04

Setting Up the Volume Integral

We integrate the divergence \( 3 \) over the volume \( V \) of the cylinder: \[ \iiint_{V} 3 \, dV = 3 \cdot \text{volume of the cylinder}. \] The limits are \( 0 \leq \theta \leq 2\pi \), \( 0 \leq r \leq 2 \), \( 3 \leq z \leq 7 \).
05

Calculating the Volume of the Cylinder

The volume of a cylinder is given by \( V = \pi r^2 h \). Here, \( r = 2 \) and \( h = 7 - 3 = 4 \). So, \( V = \pi \times 4 \times 4 = 16\pi \).
06

Evaluating the Volume Integral

Substitute the volume of the cylinder into the integral: \( 3 \times 16\pi = 48\pi \).
07

Conclusion

The flux of the vector field \( \vec{F} \) through the closed cylinder is \( 48\pi \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Flux
Flux represents the flow of a vector field through a surface. In simple terms, it tells us how much of something (like fluid or force) is passing through a specific area. When we talk about the flux of a vector field, we are considering how the field lines penetrate a surface.

In mathematical terms, flux through a surface is calculated using an integral. If we have a vector field \( \vec{F} \) and a surface \( S \) with an outward normal vector \( \vec{n} \), the flux is given by the surface integral \( \iint_{S} \vec{F} \cdot \vec{n} \, dS \). This integral computes the sum of the dot products of \( \vec{F} \) and \( \vec{n} \) over the entire surface.
- Flux can be positive or negative, indicating the direction of flow relative to the surface.
- In a closed surface, a positive flux indicates a net "outflow," while negative flux indicates a net "inflow."

The Divergence Theorem, used in the given solution, converts this surface integral into a volume integral, simplifying the computation.
Vector Field
A vector field is a mathematical construct where we assign a vector to each point in space. Essentially, it is a function that associates a vector to each point in a region. This concept is widely used in physics and engineering to represent quantities like velocity, force, or electromagnetic fields.

The vector field \( \vec{F} = (x+3e^{yz})\mathbf{i} + (\ln(x^2z^2+1)+y)\mathbf{j} + z\mathbf{k} \) from the exercise describes how something (like a force or velocity) behaves at every point in space within the region.
- The \( \mathbf{i}, \mathbf{j}, \mathbf{k} \) components represent the vector components along the x, y, and z axes, respectively.
- Each component function (e.g., \( x+3e^{yz} \) for the \( \mathbf{i} \)-component) depends on the location in space, meaning it changes if \( x, y, \) or \( z \) change.

Understanding vector fields is essential in fields like fluid dynamics or electromagnetism where forces and flows are directional dependent.
Cylinder
A cylinder is a three-dimensional shape with straight parallel sides and a circular cross-section. It is one of the simplest types of geometric surfaces. In this exercise, we focus on a closed cylinder on the z-axis with a radius of 2 and height extending from \( z = 3 \) to \( z = 7 \).

For the purpose of calculating flux using the Divergence Theorem, the components of a cylinder include:
  • A curved surface, which in a closed cylinder is the lateral area between the circular top and bottom.

  • Two flat circular "caps" or bases at each end.

To calculate the volume of such a cylinder, you use the formula \( V = \pi r^2 h \), where \( r \) is the radius and \( h \) is the height of the cylinder. In this problem, \( r = 2 \) and \( h = 4 \) (since \( 7 - 3 = 4 \)), giving us a volume of \( 16\pi \).
Understanding the geometry of a cylinder is crucial for setting up the limits of integration and correctly applying the Divergence Theorem.

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Most popular questions from this chapter

Are the statements true or false? Give reasons for your answer. If \(\vec{A}(x, y)\) is the area vector for \(z=f(x, y)\) oriented upward and \(\vec{B}(x, y)\) is the area vector for \(z=-f(x, y)\) oriented upward, then \(\vec{A}(x, y)=-\vec{B}(x, y)\)

A vector field, \(\vec{v},\) in the plane is a point sink at the origin if its direction is toward the origin at every point, its magnitude depends only on the distance from the origin, and its divergence is zero away from the origin. (a) Explain why a point sink at the origin must be of the form \(\vec{v}=\left(f\left(x^{2}+y^{2}\right)\right)(x \vec{i}+y \vec{j})\) for some negative function \(f\) (b) Show that \(\vec{v}=K\left(x^{2}+y^{2}\right)^{-1}(x \vec{i}+y \vec{j})\) is a point sink at the origin if \(K<0\) (c) Determine the magnitude \(\|\vec{v}\|\) of the sink in part (b) as a function of the distance from its center. (d) Sketch \(\vec{v}=-\left(x^{2}+y^{2}\right)^{-1}(x \vec{i}+y \vec{j})\) (e) Show that \(\phi=\frac{K}{2} \log \left(x^{2}+y^{2}\right)\) is a potential function for the sink in part (b).

Let \(B\) be the surface of a box centered at the origin, with edges parallel to the axes and in the planes \(x=\pm 1\) \(y=\pm 1, z=\pm 1,\) and let \(S\) be the sphere of radius 1 centered at origin. (a) Indicate whether the following flux integrals are positive, negative, or zero. No reasons needed. (a) \(\int_{B} x \vec{i} \cdot d \vec{A}\) (b) \(\int_{B} y \vec{i} \cdot d \vec{A}\)

Let \(\vec{H}=\left(e^{x y}+3 z+5\right) \vec{i}+\left(e^{x y}+5 z+3\right) \vec{j}+\left(3 z+e^{x y}\right) \vec{k}\) Calculate the flux of \(\overrightarrow{\boldsymbol{H}}\) through the square of side 2 with one vertex at the origin, one edge along the positive \(y\) -axis, one edge in the \(x z\) plane with \(x>0, z>0\) and the normal \(\vec{n}=\vec{i}-\vec{k}\)

Compute the flux of the vector field \(\vec{F}\) through the surface \(S\). \(\vec{F}=(x-y) \vec{i}+z \vec{j}+3 x \vec{k}\) and \(S\) is the part of the plane \(z=x+y\) above the rectangle \(0 \leq x \leq 2,0 \leq y \leq 3\) oriented unward.

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