Chapter 18: Problem 22
Find \(\int_{C} \vec{F} \cdot d \vec{r}\) for the given \(\vec{F}\) and \(C\). \(\overrightarrow{\boldsymbol{F}}=-\vec{y} \vec{i}+x \vec{j}+5 \vec{k}\) and \(C\) is the helix \(x=\cos t, y=\) \(\sin t, z=t,\) for \(0 \leq t \leq 4 \pi\).
Short Answer
Expert verified
The line integral \( \int_{C} \vec{F} \cdot d \vec{r} = 24\pi \).
Step by step solution
01
Understand the Problem
The exercise requires us to evaluate the line integral of the vector field \( \vec{F} = -y \vec{i} + x \vec{j} + 5 \vec{k} \) along a helical curve \( C \) defined by \( x = \cos t \), \( y = \sin t \), and \( z = t \) for \( t \) in the range \( 0 \leq t \leq 4\pi \).
02
Parametrize the Helix
The helix is already parametrized by \( \vec{r}(t) = \cos t \, \vec{i} + \sin t \, \vec{j} + t \, \vec{k} \). This parametrization gives us a path for the line integral.
03
Compute \( d\vec{r} \)
We find the differential \( d\vec{r} \) by differentiating \( \vec{r}(t) \):\[ d\vec{r} = \frac{d}{dt}(\cos t \vec{i} + \sin t \vec{j} + t \vec{k}) \, dt = (-\sin t \vec{i} + \cos t \vec{j} + \vec{k}) \, dt. \]
04
Substitute and Dot Product
Substitute the parametrization into \( \vec{F} \):- \( x = \cos t \), \( y = \sin t \).- Thus, \( \vec{F} = -\sin t \vec{i} + \cos t \vec{j} + 5\vec{k} \).Compute the dot product \( \vec{F} \cdot d\vec{r} \):\[-\sin t (-\sin t) + \cos t \cos t + 5 \cdot 1 = \sin^2 t + \cos^2 t + 5 = 1 + 5 = 6\].
05
Integrate Over the Interval
The line integral becomes:\[ \int_{0}^{4\pi} 6 \, dt = 6t \bigg|_0^{4\pi} = 6(4\pi) - 6(0) = 24\pi. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Fields
In mathematics, a vector field is a function that assigns a vector to every point in space. Think of it as a map that assigns a direction and a magnitude (essentially a little arrow) to each point within an area, a plane, or even a space. For example, the vector field given in this exercise is \( \vec{F} = -y \vec{i} + x \vec{j} + 5 \vec{k} \). Here, \( -y \vec{i}\), \( x \vec{j}\), and \( 5 \vec{k}\) are the vector components in the x, y, and z directions respectively.
Vector fields can represent many physical quantities such as wind speed and direction, magnetic fields, or current flow. In a line integral, which is a key component of vector calculus, we calculate the work done by a vector field in moving an object along a curve. Line integrals have wide utility in physics and engineering as they integrate vector fields along a path or curve like the helical curve in our original problem.
Vector fields can represent many physical quantities such as wind speed and direction, magnetic fields, or current flow. In a line integral, which is a key component of vector calculus, we calculate the work done by a vector field in moving an object along a curve. Line integrals have wide utility in physics and engineering as they integrate vector fields along a path or curve like the helical curve in our original problem.
- Components: Every vector field has different components acting in directions like \( \vec{i}, \vec{j}, \vec{k} \).
- Software Visualization: Many vector fields can be visualized for better understanding through graphing software.
- Physical Representation: Visualizing vector fields as arrows can help understand their path and movement.
Helical Curves
A helical curve, or helix, is a type of curve that looks like the shape of a spring or corkscrew. When you think of a helix, imagine the patterns found in spiral staircases or the way climbing plants coil around a support. In mathematics, a helix is represented using parametric equations.
For example, in the exercise, the helix is defined with the parametric equations: \( x = \cos t \), \( y = \sin t \), and \( z = t \). These equations describe a curve that wraps around a cylinder, going upwards or downwards as the parameter \( t \) changes. The parameter \( t \) acts like time, advancing along the path of the curve. For the line integral, we consider the path described by these equations from \( t = 0 \) to \( t = 4 \pi \).
For example, in the exercise, the helix is defined with the parametric equations: \( x = \cos t \), \( y = \sin t \), and \( z = t \). These equations describe a curve that wraps around a cylinder, going upwards or downwards as the parameter \( t \) changes. The parameter \( t \) acts like time, advancing along the path of the curve. For the line integral, we consider the path described by these equations from \( t = 0 \) to \( t = 4 \pi \).
- Parametric Representation: Helical curves are usually represented with parameters that define how the curve behaves over time.
- Applications: Helices are found in many natural and man-made objects such as DNA and springs.
- Visualization: Visualizing the helix can aid in understanding the line integral path.
Parametric Equations
Parametric equations define a group of related quantities as functions of one or more independent variables called parameters. Instead of relating \(x\) and \(y\) directly, you express them in terms of a third parameter, often \(t\). This is particularly useful for describing curves, as it allows the representation of both static and dynamic forms.
In our exercise, the parametric equations \( x = \cos t \), \( y = \sin t \), and \( z = t \) describe the position of a point on the helix as \( t \) varies. Note how each of \( x \), \( y \), and \( z \) depends on \( t \), which gives the entire path of the curve in three-dimensional space. This parameterization is what makes it possible to compute the line integral along a geometric path, as you use these functions to define the path in terms of just one variable.
In our exercise, the parametric equations \( x = \cos t \), \( y = \sin t \), and \( z = t \) describe the position of a point on the helix as \( t \) varies. Note how each of \( x \), \( y \), and \( z \) depends on \( t \), which gives the entire path of the curve in three-dimensional space. This parameterization is what makes it possible to compute the line integral along a geometric path, as you use these functions to define the path in terms of just one variable.
- Benefits: Parametrization simplifies the process of curve tracing, especially in complex shapes.
- Curve Plotting: By varying \( t \), you can plot each point making up the curve and understand its flow or direction.
- Real-World Use: Parametric equations are essential in animations, physics simulations, and describing motion.