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Give an example of: A vector field \(\vec{F}(x, y, z)\) such that the path \(\vec{r}(t)=\) \(\overrightarrow{t i}+t^{2} \vec{j}+t^{3} \vec{k}\) is a flow line.

Short Answer

Expert verified
\(\vec{F}(x, y, z) = \hat{i} + 2\sqrt{y} \hat{j} + 3\sqrt[3]{z}^2 \hat{k}\)

Step by step solution

01

Understand the Flow Line Concept

A vector field \(\vec{F}(x, y, z)\) is defined to have a path \(\vec{r}(t)\) as its flow line if the velocity of the path \(\frac{d\vec{r}(t)}{dt}\) is equal to the vector field evaluated at \(\vec{r}(t)\). In mathematical terms, \(\vec{F}(\vec{r}(t)) = \frac{d\vec{r}}{dt}\) for all \(t\).
02

Differentiate the Path Function

Calculate the derivative of \(\vec{r}(t) = t\hat{i} + t^2 \hat{j} + t^3 \hat{k}\) with respect to \(t\).\[ \frac{d\vec{r}(t)}{dt} = \frac{d}{dt}(t\hat{i} + t^2 \hat{j} + t^3 \hat{k}) = \hat{i} + 2t \hat{j} + 3t^2 \hat{k} \]
03

Construct the Vector Field

The vector field \(\vec{F}(x, y, z)\) must satisfy \(\vec{F}(\vec{r}(t)) = \frac{d\vec{r}}{dt}\). Given that\(\frac{d\vec{r}(t)}{dt} = \hat{i} + 2t \hat{j} + 3t^2 \hat{k}\), and knowing the relation:\(x = t\), \(y = t^2\), and \(z = t^3\), we substitute these back to get:\[ \vec{F}(x, y, z) = \hat{i} + 2\sqrt{y} \hat{j} + 3\sqrt[3]{z}^2 \hat{k} \].
04

Verify the Vector Field

Substitute the expressions for \(x\), \(y\), and \(z\) back into \(\vec{F}(x, y, z)\). For \(x = t\), \(y = t^2\), and \(z = t^3\), confirm: - \(\vec{F}(x, y, z) = \hat{i} + 2t \hat{j} + 3t^2 \hat{k}\).This matches \(\frac{d\vec{r}}{dt}\). Thus, the constructed vector field is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Flow Line
A flow line in the context of vector fields is a concept that describes a path or trajectory a particle follows under the influence of a vector field. When we say a path is a flow line of a vector field \( \vec{F}(x, y, z) \), it means that at every point along the path, the path's velocity is equal to the vector field value at that point. In mathematical terms, this is expressed as \( \vec{F}(\vec{r}(t)) = \frac{d\vec{r}}{dt} \), meaning that the vector field matches the derivative of the path function for all times \( t \).

Understanding flow lines helps in visualizing how vector fields can influence movement. It is like drawing a map where at every point, the directional flow shows how something, like a particle or fluid, would move. This is extensively used in physics and engineering to understand phenomena like fluid flow or electromagnetic field distributions.
Differentiation
Differentiation is the process of finding the rate at which a function changes at any given point, which in simpler terms, finds the slope of the function at a point. When you differentiate a path function \( \vec{r}(t) = t\hat{i} + t^2 \hat{j} + t^3 \hat{k} \), you are calculating the velocity of the path, represented as the rate of change of this path with respect to time.

For the given path, differentiating each component with respect to \( t \) gives us:
  • The \( x \)-component: \( \frac{d}{dt}(t) = 1 \)
  • The \( y \)-component: \( \frac{d}{dt}(t^2) = 2t \)
  • The \( z \)-component: \( \frac{d}{dt}(t^3) = 3t^2 \)
When we combine these, the rate of change or the velocity vector is \( \hat{i} + 2t \hat{j} + 3t^2 \hat{k} \). Differentiation here provides crucial insight into how the object moves at any time \( t \), effectively describing its motion governed by the vector field.
Path Function
The path function describes the position of a point or particle at any time \( t \). In our scenario, we were given a specific path function \( \vec{r}(t) = t\hat{i} + t^2 \hat{j} + t^3 \hat{k} \). This equation precisely maps out where the point is at any moment.

A path function can often be seen as a mathematical journey or track that the particle follows. The components \( t \hat{i}, t^2 \hat{j}, \) and \( t^3 \hat{k} \) indicate how the particle moves along the \( x, y, \) and \( z \) axes over time. This simple representation can describe very complex movements depending on the path function structure. When used with vector fields, path functions help establish flow lines, showing how the directional field guides movement.
Velocity of the Path
The velocity of the path is a vector that represents how fast and in which direction a path function's corresponding position changes over time. In essence, it tells you how an object's position shifts at any given time along the flow line.

This is connected to the differentiation process. After determining the derivative of a path function \( \vec{r}(t) = t\hat{i} + t^2 \hat{j} + t^3 \hat{k} \), i.e., \( \frac{d\vec{r}}{dt} = \hat{i} + 2t \hat{j} + 3t^2 \hat{k} \), we receive a velocity vector. This vector signifies that at any time \( t \):
  • The object moves at a speed of 1 unit along the \( i \)-axis,
  • 2t units along the \( j \)-axis,
  • and 3t^2 units along the \( k \)-axis.
This velocity vector provides the instantaneous speed and direction of the particle on its path at each moment \( t \). Understanding the velocity helps in analyzing how quickly an object is moving and in which direction at any point in time, giving us a dynamic view of the motion described by the path function.

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Most popular questions from this chapter

Are the statements true or false? Give reasons for your answer. Both \(x=-t+1, y=2 t\) and \(x=2 s, y=-4 s+2\) describe the same line.

A plane from Denver, Colorado, (altitude 1650 meters) flies to Bismark, North Dakota (altitude 550 meters). It travels at \(650 \mathrm{km} /\) hour at a constant height of 8000 meters above the line joining Denver and Bismark. Bismark is about \(850 \mathrm{km}\) in the direction \(60^{\circ}\) north of east from Denver. Find parametric equations describing the plane's motion. Assume the origin is at sea level beneath Denver, that the \(x\) -axis points east and the \(y\) -axis points north, and that the earth is flat. Measure distances in kilometers and time in hours.

Consider the line \(x=5-2 t, y=3+7 t, z=4 t\) and the plane \(a x+b y+c z=d\). All the following questions have many possible answers. Find values of \(a, b, c, d\) such that: (a) The plane is perpendicular to the line. (b) The plane is perpendicular to the line and through the point (5,3,0) (c) The line lies in the plane.

Give an example of: A nonconstant vector field that is parallel to \(\vec{i}+\vec{j}+\vec{k}\) at every point.

Suppose \(\vec{r}(t)=\cos t \vec{i}+\sin t \vec{j}+2 t \vec{k}\) represents the position of a particle on a helix, where \(z\) is the height of the particle above the ground. (a) Is the particle ever moving downward? When? (b) When does the particle reach a point 10 units above the ground? (c) What is the velocity of the particle when it is 10 units above the ground? (d) When it is 10 units above the ground, the particle leaves the helix and moves along the tangent. Find parametric equations for this tangent line.

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