Chapter 16: Problem 14
Sketch the region of integration. $$\int_{3}^{4} \int_{3 \pi / 4}^{3 x / 2} f(r, \theta) r d \theta d r$$
Short Answer
Expert verified
The region is a sector in polar coordinates between two radial lines for \( r = 3 \) to 4, spanning angles from \( \theta = 135 \) degrees to \( \theta = \frac{3r}{2} \).
Step by step solution
01
Understand the Limits of Integration
The given double integral is \( \int_{3}^{4} \int_{3 \pi / 4}^{3 x / 2} f(r, \theta) r \ d \theta \ dr \). This indicates that \( r \) varies from 3 to 4, and for each \( r \), \( \theta \) ranges from \( \frac{3\pi}{4} \) to \( \frac{3r}{2} \).
02
Sketch the r Limits
On a graph in polar coordinates, draw radial lines corresponding to \( r = 3 \) and \( r = 4 \). These will form boundary circles; \( r = 3 \) is an inner circle and \( r = 4 \) is an outer circle. They specify the radial distance from the origin in the region.
03
Sketch the θ Limits
For \( r \), \( \theta \) varies from \( \frac{3\pi}{4} \) (around 135 degrees on a polar plot) to \( \frac{3r}{2} \). On the graph, draw the line \( \theta = \frac{3\pi}{4} \). \( \theta = \frac{3r}{2} \) should be drawn as a varying line, starting from \( r = 3 \) with \( \theta = \frac{9\pi}{6} \) or \( \pi \) (180 degrees) and extending to \( r = 4 \) with \( \theta = 6\pi / 4 \) or \( 1.5\pi \) (270 degrees).
04
Identify the Region of Integration
The region of integration is the area on the polar coordinate plot defined by the intersection of the circles \( r = 3 \) and \( r = 4 \) and bounded by the lines \( \theta = \frac{3\pi}{4} \) and \( \theta = \frac{3r}{2} \). The region is a sector that starts at \( \theta = 135\) degrees, spans outwards as \( r \) increases, and terminates at the line \( \theta = \frac{3r}{2} \) for each \( r \). This sector moves from a starting angle \( \theta = 135 \) degrees to different end angles depending on \( r \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
Polar coordinates are a method of representing points in a plane using a distance and an angle. In contrast to the rectangular coordinate system (which uses an x-coordinate and a y-coordinate), polar coordinates specify locations by a radius (\( r \)) and an angle (\( \theta \)).
- The radius (\( r \)) is the distance from the origin to the point.
- The angle (\( \theta \)) is measured in radians or degrees, starting from the positive x-axis, counter-clockwise.
- \( x = r \cos(\theta) \)
- \( y = r \sin(\theta) \)
- The reverse transformation is given by:
- \( r = \sqrt{x^2 + y^2} \)
- \( \theta = \text{tan}^{-1}(\frac{y}{x}) \)
Double Integrals
Double integrals are a core tool in multivariable calculus, allowing us to integrate functions of two variables over a given region.This concept extends the idea of a single integral to two dimensions, making it useful for calculating areas, volumes, and other quantities that accumulate over a 2D space.Consider a region \( D \) in the xy-plane and a function \( f(x, y) \). The double integral of \( f \) over \( D \) is written as:\[\int \int_{D} f(x, y) \, dA\]where \( dA \) represents an infinitesimal element of area in \( D \).In the context of polar coordinates, the double integral takes a slightly altered form:\[\int_{r_1}^{r_2} \int_{\theta_1}^{\theta_2} f(r, \theta) r \, d\theta \, dr\]Here,
- The presence of \( r \, d\theta \, dr \) accounts for the change in area element size when transforming from Cartesian to polar coordinates.
- \( r \theta \) themselves define the bounds of integration instead of traditional x and y limits.
Region of Integration
The region of integration defines the specific area within which an integral is evaluated. To solve a double integral problem, one must accurately sketch and understand this region in the given coordinate system, in this case, polar coordinates.
- In polar coordinates, thee region is defined by both radius limits and angle limits.
- The given limits for radius are \( r = 3 \) to \( r = 4 \), creating two concentric circles.
- The angle varies from \( \theta = \frac{3\pi}{4} \) to \( \theta = \frac{3r}{2} \).
- Draw two circles centered at the origin with radii 3 and 4.
- Draw a line at \( \theta = \frac{3\pi}{4} \), marking the beginning of the sector.
- For each \( r \), sketch lines at \( \theta = \frac{3r}{2} \) until the outer circle is reached.