Chapter 14: Problem 73
Let \(f(100,100)=500\) and \(\operatorname{grad} f(100,100)=2 \vec{t}+3 \vec{j}\) (a) Find the directional derivative of \(f\) at the point (100,100) in the direction \(\vec{i}+\vec{j}\) (b) Use the directional derivative to approximate \(f(102,102)\)
Short Answer
Expert verified
(a) The directional derivative is \( \frac{5}{\sqrt{2}} \). (b) \( f(102, 102) \approx 505. \)
Step by step solution
01
Normalize the Direction Vector
The direction vector \( \vec{i} + \vec{j} \) needs to be normalized before using it to find the directional derivative. To normalize, divide the vector by its magnitude. The magnitude is \( \| \vec{i} + \vec{j} \| = \sqrt{1^2 + 1^2} = \sqrt{2} \). So, the normalized vector is \( \left(\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right) \).
02
Calculate the Directional Derivative
The directional derivative \( D_{\vec{u}} f \) at a point \( (x, y) \) in the direction of the unit vector \( \vec{u} \) is given by \( abla f \cdot \vec{u} \). Here, \( abla f = 2\vec{i} + 3\vec{j} = (2, 3) \). The dot product is: \[ D_{\vec{u}} f = \left( 2, 3 \right) \cdot \left( \frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}} \right) = \frac{2}{\sqrt{2}} + \frac{3}{\sqrt{2}} = \frac{5}{\sqrt{2}}. \]
03
Approximate Change in f
Use the directional derivative to approximate the change in the function \( f \) moving from \((100, 100)\) to \((102, 102)\). The directional change can be computed as \( D_{\vec{u}} f \) times the distance moved in the direction. Here, the distance is \( \sqrt{(102-100)^2 + (102-100)^2} = \sqrt{8} = 2\sqrt{2} \). The approximate change is: \[ \Delta f \approx D_{\vec{u}} f \cdot 2\sqrt{2} = \frac{5}{\sqrt{2}} \cdot 2\sqrt{2} = 5. \]
04
Calculate the Approximate Value of f(102, 102)
The new function value can be estimated by adding the approximate change \( \Delta f \) to the value of \( f(100,100) \). Thus, \( f(102, 102) \approx 500 + 5 = 505. \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gradient Vector
The gradient vector, often denoted as \( abla f \), is a vector that provides valuable information about the rate and direction of change of a function at a particular point. It is composed of the partial derivatives of the function with respect to each variable in a multivariable function. For instance, in the case of the function \( f(x, y) \), the gradient vector is defined as:
The gradient vector is a crucial tool in finding the directional derivative, which tells us how the function changes as we move in a specific direction.
- \( abla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y} \right) \)
The gradient vector is a crucial tool in finding the directional derivative, which tells us how the function changes as we move in a specific direction.
Normalization of Vectors
Normalization is a process that converts any given vector into a unit vector.
- A unit vector maintains the same direction as the original vector but has a magnitude of 1.
- This is vital when calculating the directional derivative since the direction must be a unit vector.
- Calculate the magnitude: \( \| \vec{i} + \vec{j} \| = \sqrt{1^2 + 1^2} = \sqrt{2} \).
- Divide each component by this magnitude to create the normalized vector: \( \left( \frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}} \right) \).
Vector Magnitude
Vector magnitude, or the length of a vector, is a measure of how long the vector is. For a given vector \( \vec{a} = (a_1, a_2) \), its magnitude is calculated as:
For instance, calculating the magnitude of \( \vec{i} + \vec{j} \) reveals \( \sqrt{2} \), enabling us to normalize it effectively.Understanding the magnitude gives insight into the size of the vector, which is a critical factor when examining the overall geometry of vector spaces.
- \( \| \vec{a} \| = \sqrt{a_1^2 + a_2^2} \).
For instance, calculating the magnitude of \( \vec{i} + \vec{j} \) reveals \( \sqrt{2} \), enabling us to normalize it effectively.Understanding the magnitude gives insight into the size of the vector, which is a critical factor when examining the overall geometry of vector spaces.
Dot Product
The dot product is an algebraic operation that takes two equal-length sequences of numbers (usually coordinate vectors) and returns a single number. Essentially, it is a way to multiply two vectors to yield a scalar, and is calculated by summing the products of their corresponding components:
The dot product thus bridges vectors and scalars, providing a fundamental tool to interpret vector alignment and influence on space.
- For vectors \( \vec{a} = (a_1, a_2) \) and \( \vec{b} = (b_1, b_2) \), the dot product is \( \vec{a} \cdot \vec{b} = a_1b_1 + a_2b_2 \).
The dot product thus bridges vectors and scalars, providing a fundamental tool to interpret vector alignment and influence on space.