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Let \(z=f(x, y), x=x(u, v), y=y(u, v)\) and \(x(4,5)=2, y(4,5)=3 .\) Calculate the partial derivative in terms of \(a, b, c, d, e, k, p, q, r, s, t, w:\) $$\begin{aligned} &f_{x}(4,5)=a \quad f_{y}(4,5)=c \quad x_{u}(4,5)=e \quad y_{u}(4,5)=p\\\ &f_{x}(2,3)=b \quad f_{y}(2,3)=d \quad x_{v}(4,5)=k \quad y_{v}(4,5)=q\\\ &x_{u}(2,3)=r \quad y_{u}(2,3)=s \quad x_{v}(2,3)=t \quad y_{v}(2,3)=w \end{aligned}$$ $$z_{v}(4,5)$$

Short Answer

Expert verified
\(z_v(4,5) = a \cdot k + c \cdot q\).

Step by step solution

01

Understand the problem

We need to calculate the partial derivative \(z_v(4,5)\) given a function \(z = f(x,y)\) with the transformations \(x = x(u,v)\) and \(y = y(u,v)\). We have specific values for derivatives at points \((2,3)\) and \((4,5)\), and we will use the chain rule to express \(z_v\) in terms of known partial derivatives.
02

Recall the chain rule

The chain rule for this problem is given by: \[z_v = f_x \cdot x_v + f_y \cdot y_v\] where \(f_x\) and \(f_y\) are partial derivatives of \(f\) with respect to \(x\) and \(y\), and \(x_v\) and \(y_v\) are partial derivatives of \(x\) and \(y\) with respect to \(v\).
03

Use given values for \(z_v(4,5)\)

We only need the values at \((4,5)\): \[f_x(4,5) = a, \ f_y(4,5) = c, \ x_v(4,5) = k, \ y_v(4,5) = q\] Substitute these values into the chain rule formula for \(z_v\): \[z_v(4,5) = a \cdot k + c \cdot q\]
04

Calculate \(z_v(4,5)\)

Now perform the calculation: \[z_v(4,5) = a \times k + c \times q\] Substitute the given values \(a, c, k,\) and \(q\), to finalize the calculation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule in Multivariable Calculus
Calculating partial derivatives in a multivariable context often requires the chain rule. This rule helps us differentiate a composite function, where the variables themselves are functions of other variables. Imagine you have a function like \(z = f(x, y)\) and within it, \(x\) and \(y\) are given by \(x = x(u, v)\) and \(y = y(u, v)\). To find the derivative of \(z\) with respect to \(v\), you'll consider how both \(x\) and \(y\) influence \(z\) through \(v\).
The chain rule states:
  • \(z_v = f_x \cdot x_v + f_y \cdot y_v\)
This means that the rate of change of \(z\) with respect to \(v\), \(z_v\), is the sum of the products of the partial derivatives of \(f\) with respect to \(x\) and \(y\), and the partial derivatives of \(x\) and \(y\) with respect to \(v\).
This formula extracts how \(z\) changes through both variables \(x\) and \(y\), which are themselves affected by changes in \(u\) and \(v\). By substituting in known values of these partial derivatives at specific points, we can evaluate \(z_v\). This interconnectedness perfectly demonstrates the beauty of the chain rule in multivariable calculus.
Understanding Multivariable Calculus
Multivariable calculus extends calculus concepts to functions of multiple variables. While single-variable calculus focuses on derivatives and integrals concerning one variable, multivariable calculus deals with functions of two or more variables such as \(f(x, y)\). In our problem:
  • \(z = f(x, y)\) is affected by \(u\) and \(v\) through \(x\) and \(y\).
  • Consequently, getting the derivative \(z_v\) involves partial differentiation.
Partial differentiation is a technique for finding the derivative concerning one variable while keeping others constant. It's akin to "slicing" through a surface parallel to one of the axes in a higher-dimensional space. In multivariable calculus, you'd often deal with tasks like finding tangent planes, evaluating gradients, or computing changes in surface curvature.
This enriched toolbox allows you to tackle complex real-world problems involving motion across surfaces, optimization, and changes in fields such as physics and engineering. Being comfortable in navigating multivariable landscapes opens up insights into pattern formations, dynamic systems, and natural phenomena.
Function Transformation and Their Impact
In calculus, function transformation involves changing one function into another to better understand, analyze, or compute its properties. In this context, we're dealing with how functions \(x = x(u, v)\) and \(y = y(u, v)\) impact \(z = f(x, y)\). This transformation links different sets of variables and allows us to analyze complex interactions within multivariable systems.
  • When transforming functions, it's vital to recognize which variables depend on others and how changes propagate through these dependencies.
  • Our scenario shows how \(x\) and \(y\) depend on \(u\) and \(v\), influencing \(z\).
Function transformation is not merely a mechanical process—it helps readers conceptualize how modifications to input variables affect the outputs and the function's behavior. It forms the backbone for applications ranging from physics to computer graphics, where understanding complex changes allows us to simulate reality, model systems accurately, and exceed traditional boundaries.
By using these transformations effectively, we derive meaningful interpretations of data and predictive models, ensuring our computations stay aligned with real-world dynamics and expectations.

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Most popular questions from this chapter

Find grad \(f\) from the differential. $$d f=2 x d x+10 y d y$$

Find an equation for the tangent plane to \(z=f(x, y)\) at (3,-2) if the differential at (3,-2) is \(d f=5 d x+d y\) and \(f(3,-2)=8\)

the point is on the surface in 3 -space. (a) Find the differential of the equation (that is, of each side). (b) Find \(d z\) at the point. (c) Find an equation of the tangent plane to the surface at the point. $$x^{2}+y^{2}+z^{2}+1=x y z+2 x^{2}+3 y^{2}-2 z^{2},(1,1,1)$$

(a) Check the local linearity of \(f(x, y)=e^{-x} \sin y\) near \(x=1, y=2\) by making a table of values of \(f\) for \(x=0.9,1.0,1.1\) and \(y=1.9,2.0,2.1\) Express values of \(f\) with 4 digits after the decimal point. Then make a table of values for \(x=\) 0.99,1.00,1.01 and \(y=1.99,2.00 .2 .01,\) again showing 4 digits after the decimal point. Do both tables look nearly linear? Does the second table look more linear than the first? (b) Give the local linearization of \(f(x, y)=e^{-x} \sin y\) at \((1,2),\) first using your tables, and second using the fact that \(f_{x}(x, y)=-e^{-x} \sin y\) and \(f_{y}(x, y)=\) \(e^{-x} \cos y\)

Let \(f(x, y)=\sqrt{x+2 y+1}\) (a) Compute the local linearization of \(f\) at (0,0) (b) Compute the quadratic Taylor polynomial for \(f\) at (0,0) (c) Compare the values of the linear and quadratic approximations in part (a) and part (b) with the true values for \(f(x, y)\) at the points (0.1,0.1) \((-0.1,0.1),(0.1,-0.1),(-0.1,-0.1) .\) Which approximation gives the closest values?

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