Chapter 14: Problem 103
Give an example of: A unit vector \(\vec{u}\) such that \(f_{\vec{u}}(0,0)<0,\) given that \(f_{x}(0,0)=2\) and \(f_{y}(0,0)=3\)
Short Answer
Expert verified
A suitable unit vector is \( \vec{u} = \left(-\frac{3}{\sqrt{13}}, \frac{2}{\sqrt{13}}\right) \).
Step by step solution
01
Understand the Problem Statement
We have a function with partial derivatives at the point (0,0) such that \( f_x(0,0) = 2 \) and \( f_y(0,0) = 3 \). We are asked to find a unit vector \( \vec{u} \) such that the directional derivative \( f_{\vec{u}}(0,0) < 0 \).
02
Define the Directional Derivative
The directional derivative of a function \( f \) at a point \( (x, y) \) in the direction of a unit vector \( \vec{u} = (a, b) \) is given by:\[ f_{\vec{u}}(x,y) = f_x(x,y) \, a + f_y(x,y) \, b \] For our problem, this simplifies to:\[ f_{\vec{u}}(0,0) = 2a + 3b \]
03
Set Unit Vector Conditions
A unit vector \( \vec{u} = (a, b) \) must satisfy the condition:\[ a^2 + b^2 = 1 \]
04
Find Values of \( a \) and \( b \)
We need \( 2a + 3b < 0 \), indicating the dot product of the gradient and \( \vec{u} \) should be negative. Let's choose \( \vec{u} \) such that \( 2a + 3b = -k \), where \( k > 0 \).
05
Choose Specific Values
Let's choose specific values satisfying the above conditions. Take \( a = -\frac{3}{\sqrt{13}} \) and \( b = \frac{2}{\sqrt{13}} \). Check:- The unit vector condition: \[ \left( -\frac{3}{\sqrt{13}} \right)^2 + \left( \frac{2}{\sqrt{13}} \right)^2 = \frac{9}{13} + \frac{4}{13} = 1 \]- The directional derivative condition:\[ f_{\vec{u}}(0,0) = 2\left(-\frac{3}{\sqrt{13}}\right) + 3\left( \frac{2}{\sqrt{13}} \right) = -\frac{6}{\sqrt{13}} + \frac{6}{\sqrt{13}} = -\frac{k}{\sqrt{13}} = -\frac{12}{13} \]
06
Confirm the Solution
Substitute values to ensure correctness:The unit vector does satisfy the condition \( 2a + 3b < 0 \) with the expected result. The choice of \( a = -\frac{3}{\sqrt{13}} \) and \( b = \frac{2}{\sqrt{13}} \) makes \( f_{\vec{u}}(0,0) = -\frac{12}{13} < 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Directional Derivatives
The directional derivative is a way to determine the rate of change of a function as one moves in a specific direction. It combines partial derivatives and the direction, encoded as a unit vector.
Think of it as answering the question: "If I move in this precise direction, how fast does my function change?"
To find the directional derivative of a function \( f \) at a point \( (x, y) \), use a unit vector \( \vec{u} = (a, b) \). The formula is:
- \( a \) and \( b \) are components of the unit vector specifying direction.The critical part is ensuring the unit vector follows \( a^2 + b^2 = 1 \). Only then is the direction correctly normalized.
Think of it as answering the question: "If I move in this precise direction, how fast does my function change?"
To find the directional derivative of a function \( f \) at a point \( (x, y) \), use a unit vector \( \vec{u} = (a, b) \). The formula is:
- \( f_{\vec{u}}(x, y) = f_x(x, y) \cdot a + f_y(x, y) \cdot b \)
- \( a \) and \( b \) are components of the unit vector specifying direction.The critical part is ensuring the unit vector follows \( a^2 + b^2 = 1 \). Only then is the direction correctly normalized.
Partial Derivatives
Partial derivatives \( f_x \) and \( f_y \) are a cornerstone of calculus, representing how a multivariable function changes with respect to each individual variable while keeping all other variables constant.
They answer the simple question: "How does the function change if I nudge one variable while holding the others fixed?"
To compute partial derivatives:
They answer the simple question: "How does the function change if I nudge one variable while holding the others fixed?"
To compute partial derivatives:
- For \( f_x \), differentiate the function concerning \( x \) while treating \( y \) as a constant.
- For \( f_y \), differentiate the function concerning \( y \) while treating \( x \) as a constant.
Gradient Vectors
The gradient vector is created by combining all the partial derivatives of a function into a single vector, \( abla f = \langle f_x, f_y \rangle \).
It's like a compass that points in the direction of the steepest increase of a function.
When you look at a hill on a terrain map, the gradient shows which path is steepest uphill. This makes it a potent tool in optimization, helping us find maxima and minima.
In the context of directional derivatives, the gradient vector gets paired with a unit vector. This pairing gives you the directional derivative through the dot product:
It's like a compass that points in the direction of the steepest increase of a function.
When you look at a hill on a terrain map, the gradient shows which path is steepest uphill. This makes it a potent tool in optimization, helping us find maxima and minima.
In the context of directional derivatives, the gradient vector gets paired with a unit vector. This pairing gives you the directional derivative through the dot product:
- Directional Derivative = \( abla f \cdot \vec{u} \)