Chapter 13: Problem 65
Are the statements true or false? Give reasons for your answer. $$(\vec{i} \times \vec{j}) \cdot \vec{k}=\vec{i} \cdot(\vec{j} \times \vec{k})$$
Short Answer
Expert verified
The statement is true; both sides equal 1.
Step by step solution
01
Calculate the Left-Hand Side
Evaluate the expression \((\vec{i} \times \vec{j}) \cdot \vec{k}\). The cross product \(\vec{i} \times \vec{j}\) results in \(\vec{k}\), since \(\vec{i}, \vec{j}, \vec{k}\) are the standard orthonormal basis vectors in \(\mathbb{R}^3\) and \(\vec{i} \times \vec{j} = \vec{k}\). Thus the dot product \((\vec{k}) \cdot \vec{k} = 1\).
02
Calculate the Right-Hand Side
Evaluate the expression \(\vec{i} \cdot (\vec{j} \times \vec{k})\). Using the right-hand rule for cross products, \(\vec{j} \times \vec{k} = \vec{i}\). The dot product \(\vec{i} \cdot \vec{i} = 1\).
03
Compare the Results
Compare the results of both expressions. The left-hand side result is \(1\) and the right-hand side result is also \(1\). Since both sides are equal, the statement is true.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
The cross product, also known as the vector product, is a binary operation on two vectors in three-dimensional space. Unlike the dot product which returns a scalar, the cross product results in a vector. This new vector is perpendicular to the plane formed by the original vectors. In symbolic terms, for two vectors \( \mathbf{a} = [a_1, a_2, a_3] \) and \( \mathbf{b} = [b_1, b_2, b_3] \), the cross product \( \mathbf{a} \times \mathbf{b} \) is computed as:\[\mathbf{a} \times \mathbf{b} = \begin{bmatrix}a_2b_3 - a_3b_2 \a_3b_1 - a_1b_3 \a_1b_2 - a_2b_1\end{bmatrix}\]Key Characteristics:
- The cross product of two parallel vectors is the zero vector, \( \mathbf{0} \).
- The magnitude of the cross product equals the area of the parallelogram that the vectors span.
- It is anticommutative, meaning \( \mathbf{a} \times \mathbf{b} = - (\mathbf{b} \times \mathbf{a}) \).
- Commonly used to find a perpendicular vector to a plane defined by two vectors.
Dot Product
The dot product, also known as the scalar product, is a fundamental operation in vector calculus. Unlike the cross product, the dot product results in a scalar value. This value is derived from two vectors, measuring their parallelism and intensity of overlap. For vectors \( \mathbf{a} = [a_1, a_2, a_3] \) and \( \mathbf{b} = [b_1, b_2, b_3] \), the dot product is calculated as:\[\mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3\]Important Features:
- Geometric Interpretation: It can be viewed as the length of the projection of one vector onto another, scaled by the length of the other vector.
- The dot product is zero if two vectors are orthogonal, i.e., perpendicular to each other.
- It can be used to calculate the angle \( \theta \) between two vectors using \( \cos^{-1} \left( \frac{\mathbf{a} \cdot \mathbf{b}}{\|\mathbf{a}\| \|\mathbf{b}\|} \right) \).
Orthonormal Basis Vectors
Orthonormal basis vectors are a set of vectors that are both orthogonal and normalized. This means that each pair of different vectors in the set is perpendicular, and every vector has a unit length. In three-dimensional space, the standard orthonormal basis vectors are typically \( \mathbf{i} = [1, 0, 0] \), \( \mathbf{j} = [0, 1, 0] \), and \( \mathbf{k} = [0, 0, 1] \).Properties:
- Orthogonality: Their dot product with each other is zero, for example, \( \mathbf{i} \cdot \mathbf{j} = 0 \). This simplifies calculations in various applications of linear algebra.
- Normalization: Each vector has a magnitude of 1, so the dot product with itself is 1 (e.g., \( \mathbf{j} \cdot \mathbf{j} = 1 \)).
- The convenience of basis transformation: These vectors underpin transformations between coordinate systems due to their simplicity.