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Consider the acceleration due to gravity, \(g,\) at a distance \(h\) from the center of a planet of mass \(m\) (a) If \(m\) is held constant, is \(g\) an increasing or decreasing function of \(h ?\) Why? (b) If \(h\) is held constant, is \(g\) an increasing or decreasing function of \(m ?\) Why?

Short Answer

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(a) Decreasing with distance; (b) Increasing with mass.

Step by step solution

01

Understanding the Gravity Formula

The acceleration due to gravity at a distance \( h \) from the center of a planet of mass \( m \) is given by the formula \( g = \frac{Gm}{h^2} \), where \( G \) is the universal gravitational constant. This formula shows that gravity is inversely proportional to the square of the distance from the planet's center.
02

Analyzing the Effect of Distance on Gravity (Part a)

In part (a), mass \( m \) is held constant. According to the formula \( g = \frac{Gm}{h^2} \), as \( h \) increases, \( h^2 \) also increases, leading to a decrease in \( g \) because the denominator increases. Therefore, \( g \) is a decreasing function of \( h \).
03

Analyzing the Effect of Mass on Gravity (Part b)

In part (b), distance \( h \) is held constant. Examining the formula \( g = \frac{Gm}{h^2} \), as \( m \) increases, \( g \) increases linearly because \( m \) is in the numerator and impacts \( g \) directly. Therefore, \( g \) is an increasing function of \( m \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration due to gravity
The acceleration due to gravity, commonly denoted as \( g \), is a measure of how quickly an object accelerates towards a planetary body, like Earth, due to gravitational forces. It depends on two major factors: the mass of the planet and the distance from its center. The formula to calculate \( g \) is given by:
  • \( g = \frac{Gm}{h^2} \)
where \( G \) is the universal gravitational constant, \( m \) is the mass of the planet, and \( h \) is the distance from the planet's center. This equation shows that:- As the distance \( h \) increases, \( g \) decreases.- As the mass \( m \) increases, \( g \) increases.Understanding how these factors affect gravity helps us comprehend phenomena like free fall and the varying strengths of gravity felt on different planets. The Earth's average \( g \) is about 9.81 m/s², which keeps everything anchored to the surface.
Inverse square law
The inverse square law is a vital principle in physics, particularly when dealing with forces like gravity and light. When we say that gravity follows the inverse square law, it means that the gravitational force becomes weaker with the square of the distance from the source. Mathematically, this is represented in the gravity formula for \( g \):
\( g = \frac{Gm}{h^2} \)
  • As the distance doubly increases, the force of gravity becomes four times weaker.
  • This effect is noticeable in the decreased gravitational pull felt as one moves further from a planet.
The inverse square law is significant because it explains why objects weigh less on high mountains or in the upper atmosphere as compared to at sea level. It also helps astrophysicists predict planetary interactions and orbits within our solar system.
Gravitational constant
The gravitational constant, denoted by \( G \), is a crucial component in the laws of gravitation. It is a universal constant with a value approximately equal to \( 6.674 \, \times \, 10^{-11} \, \text{Nm}^2/\text{kg}^2 \). This constant serves as a proportionality factor in Newton's law of universal gravitation, and its role in the equation for gravity is critical:
  • \( G \) helps calculate the force of gravity between two masses.
  • It ensures that the gravitational force aligns with observed values measured in nature.
Without \( G \), calculations of gravitational forces between objects and their resultant acceleration would be impossible. Its precision is essential for accurately predicting everything from planetary orbits to the behavior of galaxies. Understanding \( G \) helps in resolving various cosmic puzzles and crafting technologies used for space exploration.
Planetary motion
Planetary motion refers to the movement of planets around a star, such as the Earth's motion around the Sun. This movement is described by Kepler's laws of planetary motion, which are grounded in the principles of gravity. Gravity, powered by the mass of celestial bodies and its inverse square relationship with distance, orchestrates these celestial dances:
  • Planets orbit in elliptical shapes with their star at one focus.
  • The speed of a planet in its orbit varies such that it sweeps out equal areas during equal intervals of time.
  • The time it takes for a planet to complete its orbit increases with the size of the orbit.
These laws underscore the harmony and predictability of planetary and satellite orbits. Gravity not only keeps planets in their trajectories but also affects other natural phenomena, such as tides and biological cycles. Understanding planetary motion is essential for space navigation and predicting eclipses or celestial events.

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Most popular questions from this chapter

Is the statement true or false? Give reasons for your answer. If the level surfaces of \(g\) are planes, then \(g(x, y, z)=\) \(a x+b y+c z+d,\) where \(a, b, c, d\) are constants.

A shopper buys \(x\) units of item \(A\) and \(y\) units of item \(B\) obtaining satisfaction \(s(x, y)\) from the purchase. (Satisfaction is called utility by economists.) The contours \(s(x, y)=x y=c\) are called indifference curves because they show pairs of purchases that give the shopper the same satisfaction. (a) A shopper buys 8 units of \(A\) and 2 units of \(B\). What is the equation of the indifference curve showing the other purchases that give the shopper the same satisfaction? Sketch this curve. (b) After buying 4 units of item \(A\), how many units of B must the shopper buy to obtain the same satisfaction as obtained from buying 8 units of \(A\) and 2 units of \(B ?\) (c) The shopper reduces the purchase of item \(A\) by \(k\) a fixed number of units, while increasing the purchase of \(B\) to maintain satisfaction. In which of the following cases is the increase in \(B\) largest? Initial purchase of \(A\) is 6 units Initial purchase of \(A\) is 8 units

Explain what is wrong with the statement. If the contours of \(f\) are all parallel lines, then \(f\) is linear.

Sketch and label level surfaces of \(f(x, y, z)=4-x^{2}-\) \(y^{2}-z^{2}\) for \(f=0,1,2\)

Give an example of: A table of values, with three rows and three columns, for a nonlinear function that is linear in each row and in each column.

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