Chapter 12: Problem 35
Are the statements true or false? Give reasons for your answer. If the limit of \(f(x, y)\) is 1 as \((x, y)\) approaches (0,0) along the \(x\) -axis, and the limit of \(f(x, y)\) is 1 as \((x, y)\) approaches (0,0) along the \(y\) -axis, then $$\lim _{(x, y) \rightarrow(0,0)} f(x, y) \text { exists.}$$
Short Answer
Step by step solution
Understanding the Problem
Understanding Limit Existence
Counterexample Analysis
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits of Functions
The key is uniformity of the approach. For the limit of a function \( f(x, y) \) as \((x, y)\) approaches \((a, b)\) to exist, the function must approach the same value from every possible path to \((a, b)\). Mathematically,
- As \( (x, y) \to (a, b) \), \( f(x, y) \to L \).
- \( L \) must be the same regardless of how \( (x, y) \) approaches \((a, b)\).
Path Independence
This idea stems from the fact that with multiple variables, there are infinitely many ways to approach a point. Therefore:
- If the limit exists, the value must be consistent no matter the trajectory taken.
- Path independence assures the stability and coherence of limit values across all approaches.
Counterexample Analysis
For instance, consider the function \( f(x, y) = \frac{x^2 - y^2}{x^2 + y^2} \). As you approach \((0,0)\) along different paths:
- The limit along the \(x\)-axis is 1 since when \(y = 0\), \( f(x, y) = 1 \).
- The limit along the \(y\)-axis is -1, as when \(x = 0\), \( f(x, y) = -1 \).
Multivariable Limits
Important factors when investigating multivariable limits include:
- The requirement that the function's limit must be identical across infinite paths.
- The need to confirm consistency of behavior in all directions towards the target point.
- Evaluating not just line-based paths, but also curved approaches like parabolas or hyperbolas.