Chapter 6: Problem 13
Find a power series solution for the following differential equations.The differential equation \(x^{2} y^{\prime \prime}+x y^{\prime}+\left(x^{2}-1\right) y=0\) is a Bessel equation of order \(1 .\) Use a power series of the form \(y=\sum_{n=0}^{\infty} a_{n} x^{n}\) to find the solution.
Short Answer
Expert verified
The power series solution is found by substituting a series into the equation, equating coefficients to zero, and solving the recurrence relation for coefficients.
Step by step solution
01
Assume a Power Series Solution
Start by assuming a power series solution for \( y \) in terms of \( x \). This can be written as: \[ y = \sum_{n=0}^{\infty} a_n x^n \]where \( a_n \) are coefficients that need to be determined.
02
Find the Derivatives
Compute the first and second derivatives of the power series.For the first derivative: \[ y' = \sum_{n=1}^{\infty} n a_n x^{n-1} \]For the second derivative:\[ y'' = \sum_{n=2}^{\infty} n(n-1) a_n x^{n-2} \]
03
Substitute into the Differential Equation
Substitute \( y \), \( y' \), and \( y'' \) into the original differential equation:\[ x^2 y'' + x y' + (x^2 - 1) y = 0 \] This gives:\[ x^2 \sum_{n=2}^{\infty} n(n-1) a_n x^{n-2} + x \sum_{n=1}^{\infty} n a_n x^{n-1} + (x^2 - 1) \sum_{n=0}^{\infty} a_n x^n = 0 \]
04
Adjust Summation Indices and Combine
Rewrite each series to have the index starting from \( n=0 \). This step involves adjusting the indices of summation for each series:For \( x^2 y'' \): \[ \sum_{n=0}^{\infty} (n+2)(n+1) a_{n+2} x^n \]For \( x y' \): \[ \sum_{n=0}^{\infty} (n+1) a_{n+1} x^n \]For \((x^2 - 1) y \):\[ \sum_{n=0}^{\infty} (a_n - a_n x^n) \]
05
Equate Coefficients to Zero
Combine all terms into a single series:\[ \sum_{n=0}^{\infty} \left((n+2)(n+1)a_{n+2} + (n+1)a_{n+1} + (a_{n-2} - a_n) + a_n \right) x^n = 0 \]To satisfy the equation for all \( x \), each coefficient for \( x^n \) must be zero:\[ (n+2)(n+1)a_{n+2} + (n+1)a_{n+1} + (a_{n-2} - a_n) + a_n = 0 \]
06
Solve the Recurrence Relation
From the previous equation, solve for the recurrence relation:\[ a_{n+2} = \frac{-((n+1)a_{n+1} + (a_{n-2} - a_n) + a_n)}{(n+2)(n+1)} \] This relation helps to find coefficients \( a_n \) iteratively from an initial condition. Typically, \( a_0 \) and \( a_1 \) are chosen based on initial conditions or symmetry of the problem.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Series Solution
To tackle complex differential equations like the Bessel equation, a common method is to use a power series solution. This approach involves assuming that the solution, denoted as \( y \), can be expressed as an infinite sum of terms based on powers of \( x \). Mathematically, this is represented by:
- \( y = \sum_{n=0}^{\infty} a_n x^n \)
Differential Equations
Differential equations are mathematical equations that involve the derivatives of a function. They describe how a particular quantity changes over time or space, often used to model real-world systems in physics, engineering, and other fields.The differential equation given in the exercise is:
- \(x^2 y'' + xy' + (x^2 - 1)y = 0\)
Recurrence Relation
One of the key steps in solving differential equations using a power series is establishing a recurrence relation. This relation is a formula that allows us to calculate the coefficients of the power series iteratively. From the step-by-step solution, we derived the recurrence relation:
- \( a_{n+2} = \frac{-((n+1)a_{n+1} + (a_{n-2} - a_n) + a_n)}{(n+2)(n+1)} \)
Bessel Functions
Bessel functions arise as solutions to Bessel's differential equations, which are a standard type of differential equation in mathematical physics and engineering. The equation given,
- \(x^2 y'' + xy' + (x^2 - 1)y = 0\)