Chapter 6: Problem 13
A mass that weighs \(8 \mathrm{lb}\) stretches a spring 6 inches. The system is acted on by an external force of \(8 \sin 8 t \mathrm{lb}\). If the mass is pulled down 3 inches and then released, determine the position of the mass at any time.
Short Answer
Expert verified
The position of the mass at any time is \( x(t) = -0.25 \cos 8t \).
Step by step solution
01
Determine the Spring Constant
The weight of the mass, given as 8 lb, stretches the spring by 6 inches (or 0.5 feet). The spring constant \( k \) can be calculated using Hooke's Law, \( F = kx \), where \( F \) is the force and \( x \) is the displacement. We have \( 8 = k \times 0.5 \), so \( k = \frac{8}{0.5} = 16 \) lb/ft.
02
Write the Differential Equation
The motion of the spring-mass system is governed by the differential equation \( m \frac{d^2 x}{dt^2} + kx = F(t) \). The mass is \( \frac{8}{32} = 0.25 \) slug (using the fact that weight = mass \( \times \) gravity, and gravity \( g = 32 \) ft/s²). Thus, the equation becomes \( 0.25 \frac{d^2 x}{dt^2} + 16x = 8 \sin 8t \).
03
Simplify the Differential Equation
Divide the entire equation by 0.25 to simplify: \[ \frac{d^2 x}{dt^2} + 64x = 32 \sin 8t. \] This is a non-homogeneous linear second-order differential equation.
04
Solve the Homogeneous Equation
The homogeneous part is \( \frac{d^2x}{dt^2} + 64x = 0 \). Solving the characteristic equation \( r^2 + 64 = 0 \) gives roots \( r = \pm 8i \). The general solution is \( x_h(t) = C_1 \cos 8t + C_2 \sin 8t \).
05
Solve the Particular Solution
Use the method of undetermined coefficients to solve \( \frac{d^2x}{dt^2} + 64x = 32 \sin 8t \). Assume a particular solution of the form \( x_p = A\cos 8t + B\sin 8t \). Substitute into the differential equation, compare coefficients, and solve to find \( A = 0 \) and \( B = \frac{1}{2} \). Thus, \( x_p(t) = \frac{1}{2} \sin 8t \).
06
Form the General Solution
Combine the homogeneous solution \( x_h(t) = C_1 \cos 8t + C_2 \sin 8t \) and the particular solution \( x_p(t) = \frac{1}{2} \sin 8t \): \( x(t) = C_1 \cos 8t + C_2 \sin 8t + \frac{1}{2} \sin 8t \).
07
Apply Initial Conditions
The initial condition states the mass is pulled down 3 inches (0.25 feet) and released, so \( x(0) = -0.25 \) and \( \frac{dx}{dt}(0) = 0 \). Substituting in the general solution and its derivative, set \( x(0) = C_1 = -0.25 \) and \( \frac{dx}{dt}(0) = 8C_2 + 4 = 0 \), giving \( C_2 = -0.5 \).
08
Final Solution
Substitute the constants into the general solution: \( x(t) = -0.25 \cos 8t - 0.5 \sin 8t + \frac{1}{2} \sin 8t \). Simplify to get \( x(t) = -0.25 \cos 8t \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Spring-Mass System
A Spring-Mass System is a common mechanical model used to describe how a mass (an object) behaves when it is attached to a spring. This system follows Hooke's Law, which asserts that the force needed to either stretch or compress a spring by a certain distance is proportional to that distance. It's really like the spring's way of reacting to the changes.
- Components: It primarily consists of a mass (like our 8 lb object) and a spring.
- Behavior: The mass stretches the spring under its weight. This stretch is used to determine the spring constant, a crucial value for modeling the system's dynamics.
- \(F\) is the force exerted by the mass
- \(k\) is the spring constant
- \(x\) is the displacement (stretch in spring)
Undetermined Coefficients
The method of Undetermined Coefficients is a beautiful tool for finding particular solutions to non-homogeneous linear differential equations. These are the types of equations where not everything is on one side equal to zero. The idea is to guess a form for the solution and find the coefficients through substitution.
- Purpose: This method helps solve systems where an external force like our \(8 \sin 8t\) affects the outcome.
- Process: The assumed solution’s form is based on the nature of the non-homogeneous part (in our case, sine functions).
Initial Conditions
Initial conditions are like a movie's opening scene; they set the stage for what's to follow. In a differential equation scenario, they specify the starting position and velocity of the system. These values are crucial as they influence how the system evolves.
- Importance: Knowing initial conditions allows you to pin down the constants in your general solution.
- Setup: They're often based on the physical setup of the problem or initial actions taken (like pulling a spring a certain length and releasing it).
- \(x(0) = -0.25\)
- \(\frac{dx}{dt}(0) = 0\)