Chapter 5: Problem 68
Use Green's theorem to evaluate the following integrals.\(\oint_{C} 3 y d x+\left(x+e^{y}\right) d y\), where \(C\) is a circle centered at the origin with radius 3
Short Answer
Expert verified
The integral evaluates to \(-36\pi\).
Step by step solution
01
Set Up Green's Theorem
Green's theorem relates a line integral around a simple closed curve \(C\) to a double integral over the region \(R\) it encloses. The theorem states: \[ \oint_{C} (M \, dx + N \, dy) = \iint_{R} \left( \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} \right) \, dA \] In our case, \(M = 3y\) and \(N = x + e^y\).
02
Compute Partial Derivatives
Compute the partial derivatives required by Green's theorem. We need: \( \frac{\partial N}{\partial x} = \frac{\partial}{\partial x}(x + e^y) = 1 \) and \( \frac{\partial M}{\partial y} = \frac{\partial}{\partial y}(3y) = 3 \).
03
Set Up the Double Integral
Substitute the partial derivatives into Green's theorem:\[ \iint_{R} \left( 1 - 3 \right) \, dA = \iint_{R} -2 \, dA \]This simplifies the double integral we need to evaluate over the region \(R\).
04
Describe the Region R
The region \(R\) is the area enclosed by the circle of radius 3 centered at the origin. In polar coordinates, this region is described by: \[ 0 \leq r \leq 3 \] and \[ 0 \leq \theta \leq 2\pi \].
05
Evaluate the Double Integral
Convert the double integral to polar coordinates and evaluate:\[ \iint_{R} -2 \, dA = \int_{0}^{2\pi} \int_{0}^{3} -2r \, dr \, d\theta \]First, evaluate the inner integral with respect to \(r\):\[ \int_{0}^{3} -2r \, dr = -2 \left[ \frac{r^2}{2} \right]_0^3 = -2 \times \frac{9}{2} = -18 \]Now integrate with respect to \(\theta\):\[ \int_{0}^{2\pi} -18 \, d\theta = -18 \times 2\pi = -36\pi \].
06
Final Result
The value of the line integral over the closed path \(C\) using Green's theorem is \(-36\pi\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Line Integrals
A line integral is a way to integrate a function over a curve. It's useful to think of a line integral in terms of moving along a path and adding up small values of the function along that path.
For example, imagine walking along a trail while collecting different amounts of data at various points - the line integral represents the total data collected by the end of the trail.
In mathematical terms, a line integral is expressed as:
Line integrals are especially powerful in vector calculus because they can connect to other types of integrals under certain conditions. Green's Theorem is one such connection, relating a line integral around a closed curve in the plane to a double integral over the region it encloses.
For example, imagine walking along a trail while collecting different amounts of data at various points - the line integral represents the total data collected by the end of the trail.
In mathematical terms, a line integral is expressed as:
- \( \oint_{C} (M \, dx + N \, dy) \)
Line integrals are especially powerful in vector calculus because they can connect to other types of integrals under certain conditions. Green's Theorem is one such connection, relating a line integral around a closed curve in the plane to a double integral over the region it encloses.
Double Integrals
Double integrals are used to calculate the volume under a surface in a region of the plane. Imagine a rubber sheet over a field - the double integral would give the volume of space between the sheet and the field.
In two dimensions, a double integral can provide insightful information about physical properties like mass or charge distribution.
The double integral over a region \( R \) is given by:
By applying Green's theorem, we simplify the process of evaluating line integrals by converting them into double integrals over a region \( R \). This simplification often turns complex integration along a path into more manageable computations over an area.
In two dimensions, a double integral can provide insightful information about physical properties like mass or charge distribution.
The double integral over a region \( R \) is given by:
- \( \iint_{R} f(x, y) \, dA \)
By applying Green's theorem, we simplify the process of evaluating line integrals by converting them into double integrals over a region \( R \). This simplification often turns complex integration along a path into more manageable computations over an area.
Polar Coordinates
Polar coordinates offer a different way to describe a point in the plane using a distance from a fixed point and an angle from a fixed direction. This system is often used in situations involving circular symmetry, such as circles or spirals.
In polar coordinates, a point is represented as \((r, \theta)\), where:
In this scenario:
In polar coordinates, a point is represented as \((r, \theta)\), where:
- \(r\) is the distance from the origin.
- \(\theta\) is the angle measured from the positive x-axis.
In this scenario:
- \(0 \leq r \leq 3\)
- \(0 \leq \theta \leq 2\pi\)