Chapter 5: Problem 53
True or False? Justify your answer with a proof or a counterexample.For vector field \(\mathbf{F}(x, y)=P(x, y) \mathbf{i}+Q(x, y) \mathbf{j}\), if \(P_{y}(x, y)=Q_{x}(x, y)\) in open region \(D\), then \(\int_{\partial D} P d x+Q d y=0\).
Short Answer
Expert verified
True. By Green's Theorem, if \(P_y = Q_x\), then \(\int_{\partial D} P dx + Q dy = 0\).
Step by step solution
01
- Understand the Statement
We are asked to determine if the statement is true or false: For a vector field \( \mathbf{F}(x, y)=P(x, y) \mathbf{i}+Q(x, y) \mathbf{j} \), if \( P_{y}(x, y)=Q_{x}(x, y) \) in an open region \( D \), then \( \int_{\partial D} P d x+Q d y=0 \).
02
- Recall Green's Theorem
Green's Theorem relates a line integral around a simple closed curve \( \partial D \) to a double integral over the plane region \( D \) it encloses. It is given by: \( \int_{\partial D} P dx + Q dy = \int \int_D \left(Q_x - P_y\right) \, dA \).
03
- Apply the Given Condition
Substitute the condition \( P_y = Q_x \) into Green's Theorem. This makes the integrand zero: \( Q_x - P_y = 0 \).
04
- Evaluate the Right-Side Integral
Since the integrand is zero, the double integral over region \( D \) becomes \( \int \int_D 0 \, dA = 0 \).
05
- Conclude the Result
As a result of Green's Theorem, \( \int_{\partial D} P dx + Q dy = 0 \) because the right-hand side of the equation evaluates to zero.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Line Integrals
Line integrals are a fascinating concept in vector calculus, particularly concerned with summing values of a function along a curve. Imagine a curve described by the boundary of a region, and you want to accumulate some sort of quantity along this path, such as work done by a force field, or the flow of a fluid. This is essentially what a line integral does.
In more technical terms, for a vector field \(\mathbf{F}(x, y)=P(x, y) \mathbf{i}+Q(x, y) \mathbf{j}\), a line integral over a curve \(C\) is expressed as:\[\int_C P dx + Q dy\]
The vector field components \(P(x, y)\) and \(Q(x, y)\) are evaluated along the curve \(C\), typically parameterized; this may sound complicated, but it essentially involves plugging points from \(C\) into your vector field and summing them up stepwise along \(C\).
In more technical terms, for a vector field \(\mathbf{F}(x, y)=P(x, y) \mathbf{i}+Q(x, y) \mathbf{j}\), a line integral over a curve \(C\) is expressed as:\[\int_C P dx + Q dy\]
The vector field components \(P(x, y)\) and \(Q(x, y)\) are evaluated along the curve \(C\), typically parameterized; this may sound complicated, but it essentially involves plugging points from \(C\) into your vector field and summing them up stepwise along \(C\).
- Line integrals can account for direction: they might yield positive, negative, or zero depending on the alignment of the field with the path.
- They are fundamental to understanding work done by forces as well as fluid flow along paths.
Vector Fields
Vector fields are like intricate blueprints of a region in space, illustrating where and what force, flow, or movement can occur at every point. Visualize a collection of tiny arrows, each placed at a point in your space, indicating the direction and magnitude of a vector quantity, such as velocity or force.
In the exercise, we considered a vector field given by \(\mathbf{F}(x, y)=P(x, y) \mathbf{i}+Q(x, y) \mathbf{j}\), where each point \((x, y)\) in space gets a vector. The two components, \(P\) and \(Q\), define this field: \(P\) for the \(x\)-direction and \(Q\) for the \(y\)-direction.
In the exercise, we considered a vector field given by \(\mathbf{F}(x, y)=P(x, y) \mathbf{i}+Q(x, y) \mathbf{j}\), where each point \((x, y)\) in space gets a vector. The two components, \(P\) and \(Q\), define this field: \(P\) for the \(x\)-direction and \(Q\) for the \(y\)-direction.
- Vector fields can represent physical fields, like gravitational or electromagnetic fields.
- They are useful for visualizing dynamic systems and understanding the behavior of particles in those systems.
- The condition \(P_{y} = Q_{x}\) is particularly significant, as it hints at a special property related to circulation and potential energies.
Double Integrals
Double integrals extend the concept of integration into two dimensions. They help calculate quantities over a plane region, such as area, mass, or charge distribution. In contrast to line integrals which work along curves, double integrals operate over area.
One can imagine a double integral as layering ordinary integrals one over the other, effectively traversing through a field in two directions. They are represented as:\[\int \int_D f(x, y) \, dA\]
Interestingly, in the context of Green's Theorem, the double integral binds the line integral around the boundary to a broader region within.
One can imagine a double integral as layering ordinary integrals one over the other, effectively traversing through a field in two directions. They are represented as:\[\int \int_D f(x, y) \, dA\]
Interestingly, in the context of Green's Theorem, the double integral binds the line integral around the boundary to a broader region within.
- In mathematical terms, it connects the accumulation of a field over a border to the behavior of the field within the region.
- Double integrals enable us to calculate integral values over surfaces, which is vital in physics and engineering.
- When the function under the integral is zero, as shown in the exercise, it directly relates to the fact that there's no net flux or circulation inside the region.