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Use a computer algebra system to find the curl of the given vector fields. $$ \mathbf{F}(x, y, z)=\sin (x-y) \mathbf{i}+\sin (y-z) \mathbf{j}+\sin (z-x) \mathbf{k} $$

Short Answer

Expert verified
The curl of \( \mathbf{F}(x, y, z) \) is \( \cos(y-z) \mathbf{i} + \cos(z-x) \mathbf{j} + \cos(x-y) \mathbf{k} \).

Step by step solution

01

Understanding the Curl

The curl of a vector field \( \mathbf{F} = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \) is given by the formula \( abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right) \mathbf{i} + \left( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \right) \mathbf{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \mathbf{k} \). We need to apply this formula to the given vector field.
02

Identifying Components

For \( \mathbf{F}(x, y, z) = \sin(x-y) \mathbf{i} + \sin(y-z) \mathbf{j} + \sin(z-x) \mathbf{k} \), the components are \( P(x, y, z) = \sin(x-y) \), \( Q(x, y, z) = \sin(y-z) \), and \( R(x, y, z) = \sin(z-x) \).
03

Calculating Partial Derivatives

Compute the required partial derivatives: 1. \( \frac{\partial R}{\partial y} = \frac{\partial}{\partial y}[\sin(z-x)] = 0 \). 2. \( \frac{\partial Q}{\partial z} = \frac{\partial}{\partial z}[\sin(y-z)] = -\cos(y-z) \). 3. \( \frac{\partial P}{\partial z} = \frac{\partial}{\partial z}[\sin(x-y)] = 0 \). 4. \( \frac{\partial R}{\partial x} = \frac{\partial}{\partial x}[\sin(z-x)] = -\cos(z-x) \). 5. \( \frac{\partial Q}{\partial x} = \frac{\partial}{\partial x}[\sin(y-z)] = 0 \). 6. \( \frac{\partial P}{\partial y} = \frac{\partial}{\partial y}[\sin(x-y)] = -\cos(x-y) \).
04

Applying the Curl Formula

Substitute these partial derivatives into the formula for the curl: \( abla \times \mathbf{F} = \left( 0 - (-\cos(y-z)) \right) \mathbf{i} + \left( 0 - (-\cos(z-x)) \right) \mathbf{j} + \left( 0 - (-\cos(x-y)) \right) \mathbf{k} \).
05

Simplifying the Curl Expression

Simplify the expression obtained in Step 4: \( abla \times \mathbf{F} = \cos(y-z) \mathbf{i} + \cos(z-x) \mathbf{j} + \cos(x-y) \mathbf{k} \).
06

Review and Conclusion

Review the calculations to ensure accuracy. The curl of \( \mathbf{F}(x, y, z) = \sin(x-y) \mathbf{i} + \sin(y-z) \mathbf{j} + \sin(z-x) \mathbf{k} \) is given by \( abla \times \mathbf{F} = \cos(y-z) \mathbf{i} + \cos(z-x) \mathbf{j} + \cos(x-y) \mathbf{k} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Curl
The concept of **curl** is fundamental in vector calculus, especially when dealing with three-dimensional fields. Curl helps to measure how much a vector field "twists" around a point. When we talk about a vector field \( \mathbf{F} = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \), its curl is a vector operation expressed as \( abla \times \mathbf{F} \). This operation results in a new vector field that reveals the rotational characteristics of the original field.
In essence, for a given vector field, the curl is given by:

\[ abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right) \mathbf{i} + \left( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \right) \mathbf{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \mathbf{k} \]

This means you are considering how each component of the vector field changes concerning others. It's essential for fluid dynamics and electromagnetism. If the curl at a point is zero, the vector field is irrotational at that point. This information helps determine motion patterns within fields like wind or water currents.
Partial Derivatives
**Partial derivatives** are essential when working with functions involving multiple variables. They represent how a function changes concerning just one of those variables while keeping the others constant. This concept is crucial when calculating the curl of vector fields, as seen in our exercise.
Consider a function \( f(x, y, z) \), the partial derivative regarding \( x \) is written as \( \frac{\partial f}{\partial x} \). This notation tells us how \( f \) changes with tiny increments in \( x \), with \( y \) and \( z \) held steady.
  • In the exercise, we computed:
    • \( \frac{\partial R}{\partial y} \)
    • \( \frac{\partial Q}{\partial z} \)
    • \( \frac{\partial P}{\partial z} \)
    • \( \frac{\partial R}{\partial x} \)
    • \( \frac{\partial Q}{\partial x} \)
    • \( \frac{\partial P}{\partial y} \)
Each of these derivatives plays a role in determining the curl, showing how the vector field shifts locally in different directions.
Vector Calculus
**Vector calculus** is the branch of mathematics dealing with functions involving vectors and scalar fields in multiple dimensions. It extends calculus concepts to vector functions and is crucial for fields like physics and engineering.
It involves several key operations, with curl being one of them, along with gradient and divergence. These operations help in understanding and describing the behavior of vector fields. Curl, specifically, provides insights into rotational tendencies, while divergence measures how much a vector field spreads out from a point.
  • Concepts in vector calculus:
    • **Gradient**: Measures the rate and direction of change in a scalar field.
    • **Divergence**: Quantifies the density flux of a field at a point.
    • **Curl**: As discussed, it captures the rotational aspect of a vector field.
Overall, vector calculus enables us to describe and solve real-world problems related to fields, enhancing our understanding of complex systems like electromagnetic fields, fluid flow, and more.

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Most popular questions from this chapter

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