Chapter 5: Problem 17
Find the divergence of \(\mathrm{F}\). $$ \mathbf{F}(x, y, z)=x^{2} z \mathbf{i}+y^{2} x \mathbf{j}+(y+2 z) \mathbf{k} $$
Short Answer
Expert verified
The divergence of \( \mathbf{F} \) is \( 2xz + 2yx + 2 \).
Step by step solution
01
Identify the Formula for Divergence
The divergence of a vector field \( \mathbf{F}(x, y, z) = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \) is given by the formula: \( abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \).
02
Extract Components of \( \mathbf{F} \)
From the given vector field \( \mathbf{F}(x, y, z) = x^{2} z \mathbf{i} + y^{2} x \mathbf{j} + (y + 2z) \mathbf{k} \), identify the components: \( P = x^{2} z \), \( Q = y^{2} x \), \( R = y + 2z \).
03
Calculate \( \frac{\partial P}{\partial x} \)
Differentiate \( P = x^{2}z \) with respect to \( x \). Keeping \( z \) constant, we get \( \frac{\partial}{\partial x}(x^{2}z) = 2xz \).
04
Calculate \( \frac{\partial Q}{\partial y} \)
Differentiate \( Q = y^{2}x \) with respect to \( y \). Keeping \( x \) constant, we find \( \frac{\partial}{\partial y}(y^{2}x) = 2yx \).
05
Calculate \( \frac{\partial R}{\partial z} \)
Differentiate \( R = y + 2z \) with respect to \( z \). Here, \( y \) is treated as a constant, thus \( \frac{\partial}{\partial z}(y+2z) = 2 \).
06
Sum the Partial Derivatives
Add the partial derivatives: \( 2xz + 2yx + 2 \). This gives the divergence of the vector field: \( abla \cdot \mathbf{F} = 2xz + 2yx + 2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Field
A vector field is a mathematical construct that assigns a vector to each point in space. When visualizing, imagine that every point in a 3D or 2D space has a little arrow attached to it.
These arrows can represent various phenomena like gravitational force, fluid flow, or electromagnetic forces.For example, imagine the vector field \[\mathbf{F}(x, y, z) = x^{2} z \mathbf{i} + y^{2} x \mathbf{j} + (y + 2z) \mathbf{k}\]Read as:
These arrows can represent various phenomena like gravitational force, fluid flow, or electromagnetic forces.For example, imagine the vector field \[\mathbf{F}(x, y, z) = x^{2} z \mathbf{i} + y^{2} x \mathbf{j} + (y + 2z) \mathbf{k}\]Read as:
- \( x^2 z \) in the direction of \( \mathbf{i} \)
- \( y^2 x \) in the direction of \( \mathbf{j} \)
- \( y + 2z \) in the direction of \( \mathbf{k} \)
Partial Derivatives
When we work with functions of multiple variables, it is essential to understand how a function changes with respect to one variable while keeping the others constant. This is where the concept of partial derivatives comes into play. A partial derivative of a function is its derivative with respect to one of those variables, treating all others as constants.For example, consider the component function \( P = x^2 z \):
- To find \( \frac{\partial P}{\partial x} \), we treat \( z \) as a constant and differentiate with respect to \( x \). The result is \( 2xz \).
- Similarly, the partial derivative \( \frac{\partial Q}{\partial y} \) where \( Q = y^2 x \) is computed by treating \( x \) as constant, leading to \( 2yx \).
Gradient Formula
The gradient formula is a crucial component in vector calculus used for determining the direction and magnitude of the greatest increase of a function. However, when examining a vector field, we use a related operation called divergence.The divergence is a scalar representation describing how much a vector field spreads out from a point. It is calculated using the formula:\[abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z}\]This formula tells us to take the partial derivative of each component of the vector field \( \mathbf{F}(x, y, z) \) with respect to its respective variable, and then sum them up to get the divergence. The result is a scalar value that provides critical insights:
- A positive divergence indicates that the line field is spreading out from a point.
- A negative divergence suggests that the field is converging.