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Are the following the vector fields conservative? If so, find the potential function \(f\) such that \(\mathbf{F}=\nabla f\).\(\mathbf{F}(x, y)=(6 x y) \mathbf{i}+\left(3 x^{2}-y e^{y}\right) \mathbf{j}\)

Short Answer

Expert verified
The vector field is conservative; potential function is \( f(x, y) = 3x^2y - (ye^y - e^y) + C \).

Step by step solution

01

Identify the components of the vector field

The given vector field \( \mathbf{F}(x, y) = (6xy) \mathbf{i} + (3x^2 - ye^y) \mathbf{j} \) has two components. The \( i \)-component is \( 6xy \) and the \( j \)-component is \( 3x^2 - ye^y \).
02

Check if the vector field is conservative

A vector field \( \mathbf{F} \) defined in \( \mathbb{R}^2 \) is conservative if its curl is zero, i.e., \( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} = 0 \), where \( P = 6xy \) and \( Q = 3x^2 - ye^y \). Compute \( \frac{\partial Q}{\partial x} \) and \( \frac{\partial P}{\partial y} \):- \( \frac{\partial Q}{\partial x} = \frac{\partial}{\partial x}(3x^2 - ye^y) = 6x \)- \( \frac{\partial P}{\partial y} = \frac{\partial}{\partial y}(6xy) = 6x \)Since \( \frac{\partial Q}{\partial x} = \frac{\partial P}{\partial y} = 6x \), the vector field is conservative.
03

Find the potential function \( f \)

Since the vector field is conservative, there exists a potential function \( f \) such that \( \mathbf{F} = abla f \).The potential function \( f \) must satisfy:\[ \frac{\partial f}{\partial x} = 6xy \]\[ \frac{\partial f}{\partial y} = 3x^2 - ye^y \]Integrate \( \frac{\partial f}{\partial x} = 6xy \) with respect to \( x \): \[ f(x, y) = \int 6xy \, dx = 3x^2y + g(y) \], where \( g(y) \) is an arbitrary function of \( y \).Next, differentiate \( f(x, y) = 3x^2y + g(y) \) with respect to \( y \) and equate it to \( \frac{\partial f}{\partial y} = 3x^2 - ye^y \):\[ \frac{\partial}{\partial y}(3x^2y + g(y)) = 3x^2 + g'(y) = 3x^2 - ye^y \]From this equation, \( g'(y) = -ye^y \), which gives:\[ g(y) = \int -ye^y \, dy = -(ye^y - e^y) + C \], where \( C \) is a constant of integration.Therefore, the potential function is \( f(x, y) = 3x^2y - (ye^y - e^y) + C \).
04

Verify the potential function

To verify that \( f(x, y) = 3x^2y - (ye^y - e^y) + C \) is indeed a potential function, calculate its gradient \( abla f \):\[ \frac{\partial f}{\partial x} = 6xy \]\[ \frac{\partial f}{\partial y} = 3x^2 - ye^y \]These derivatives match the components of the vector field \( \mathbf{F}(x, y) = (6xy) \mathbf{i} + (3x^2 - ye^y) \mathbf{j} \), confirming that \( f \) is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Function
A potential function is like a hidden treasure map for a conservative vector field. Imagine you have a vector field, and you want to know if it can be derived from a single function. Well, that function is called the potential function denoted by \( f \).

To find a potential function, you have to check if the vector field is conservative. This means it "comes from" a potential function. For a two-dimensional field \( \mathbf{F}(x, y) = P\mathbf{i} + Q\mathbf{j} \), it's conservative if
  • the curl is zero (more on that later!),
  • or equivalently, that a function \( f(x, y) \) exists such that \( abla f = \mathbf{F} \).
Once you know the field is conservative, you can find \( f \) by integrating both components of the vector field. From \( P = \frac{\partial f}{\partial x} \) and \( Q = \frac{\partial f}{\partial y} \), first integrate \( P \) with respect to \( x \) to get part of \( f \) and a function of \( y \), call it \( g(y) \).

Then, differentiate the obtained expression with respect to \( y \), compare it with \( Q \), solve for \( g(y) \), and integrate it to find that elusive \( f \)! This process verifies if \( f \) satisfies the components of the original field.
Curl of a Vector Field
The curl of a vector field is a measure of how much the field "twists" or "rotates" around a point. It's like the swirl in a pattern of water. Think of the curl as the vector field's tendency to spin.

In two dimensions, calculating the curl of a vector field \( \mathbf{F}(x, y) = P \mathbf{i} + Q \mathbf{j} \) involves checking the difference between cross derivatives: \( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \). If this difference is zero everywhere in a certain domain, the field is curl-free or irrotational. This is a key indicator that the field could be conservative, meaning, it might have a potential function.

Determining that the curl is zero is crucial. It tells us that no matter where you look, there's no twist in the field, hinting at a potential function waiting to be discovered. If the vector field isn't curling anywhere, it could mean you're delving into a conservative vector field with a precise potential function.
Gradient
The gradient is an operator that acts on a function to produce a vector field. Imagine you're hiking on a mountain, and your height is a function \( f(x, y) \). The gradient \( abla f \) of \( f \) points in the direction of the steepest ascent.

For a scalar function \( f(x, y) \), the gradient is \( abla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y} \right) \). If a vector field is the gradient of some function \( f \), it tells you how \( f \) increases or decreases at any point.

In conservative vector fields, the vector field itself can be expressed as the gradient of a potential function. This connection is profound: it means you can replace the effects of the vector field by looking at changes in \( f \). Therefore, identifying if a vector field is a gradient of a potential function opens up understanding of its behavior, like unraveling a map from the contours of a landscape.

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