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Show that points \(A(1,0,1), B(0,1,1)\), and \(C(1,1,1)\) are not collinear.

Short Answer

Expert verified
The points A, B, and C are not collinear because the vectors \( \overrightarrow{AB} \) and \( \overrightarrow{AC} \) are not scalar multiples of each other.

Step by step solution

01

Understanding Collinearity

Three points are collinear if they lie on the same straight line. To check this for points in 3D space, we can use vector operations. Specifically, we need to verify if the vector from point A to B is a scalar multiple of the vector from A to C.
02

Finding Vectors

Calculate the vectors \( \overrightarrow{AB} \) and \( \overrightarrow{AC} \). The vector \( \overrightarrow{AB} \) is obtained by subtracting coordinates: \([0-1, 1-0, 1-1] = [-1, 1, 0]\). Similarly, \( \overrightarrow{AC} \) is: \([1-1, 1-0, 1-1] = [0, 1, 0]\).
03

Checking for a Scalar Multiple

For points A, B, and C to be collinear, one of the vectors must be a scalar multiple of the other. Let's check if \( \overrightarrow{AB} = k \overrightarrow{AC} \) for some scalar \(k\). This condition implies that \([-1, 1, 0] = k[0, 1, 0]\).
04

Analyzing the Multiples

From the above equation, the x-component would imply \(-1 = k \times 0\), giving no solution for \(k\). Therefore, \( \overrightarrow{AB} \) and \( \overrightarrow{AC} \) are not scalar multiples of each other.
05

Conclusion on Collinearity

Since \( \overrightarrow{AB} \) is not a scalar multiple of \( \overrightarrow{AC} \), vectors \( \overrightarrow{AB} \) and \( \overrightarrow{AC} \) do not point in the same direction. Thus, points A, B, and C are not collinear.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Vector Operations
Vectors are mathematical entities that have both a direction and a magnitude. They are essential tools in physics and mathematics, particularly in analyzing motion and forces in three-dimensional space (3D space). When dealing with points in 3D space, vectors are utilized to find the relationship between these points. To express the direction and distance between two points, we calculate a vector by subtracting the coordinates of one point from another. This is known as rectilinear decomposition, resulting in a vector like \( \overrightarrow{AB} \) that extends from point \( A \) to point \( B \). Once these vectors are established, vector operations such as addition, subtraction, and checking for parallelism are used to understand spatial relationships. These operations hinge on component-wise manipulation of vector elements.
The Role of Scalar Multiples
Scalar multiples are crucial in the context of vectors because they help determine whether one vector is simply a scaled version of another. When two vectors are collinear, it means that one is a scalar multiple of the other. A scalar multiple involves multiplying each component of a vector by a constant, known as the scalar. For example, if vector \( \overrightarrow{v} = [x, y, z] \), then a scalar multiple of this vector is represented as \( k \overrightarrow{v} = [kx, ky, kz] \), where \( k \) is the scalar. In the exercise, determining if the vector \( \overrightarrow{AB} \) is a scalar multiple of \( \overrightarrow{AC} \) means checking if there exists a constant \( k \) such that every component of one vector is equal to the constant times the corresponding component of the other vector. This approach helps ascertain the collinearity of the points.
Navigating Concepts in 3D Space
3D space, or three-dimensional space, is the environment in which we live. It is characterized by the three axes: x, y, and z. Points in this space are represented with coordinates, which specify their position along each of these axes. Understanding how to navigate 3D space requires familiarity with how vectors connect points. Each vector, formed from point coordinates, conveys both the direction and the magnitude of movement from one point to another. Vector calculus in 3D space allows us to explore complex geometrical ideas like plane and line equations, normal vectors, and more. In problems that involve checking collinearity, like our exercise, the vectors must be analyzed for scalar multiples in this context, aiding in understanding their arrangement in space.

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