/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 89 For the following exercises, fin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For the following exercises, find the equation of the plane with the given properties.The plane that passes through points \((0,1,5),(2,-1,6)\), and \((3,2,5)\).

Short Answer

Expert verified
The equation of the plane is \(-x + 3y + 8z = 43\).

Step by step solution

01

Define points and vectors

First, define the points given as points A, B, and C, where \( A = (0, 1, 5) \), \( B = (2, -1, 6) \), and \( C = (3, 2, 5) \). Now, create two vectors, \( \vec{AB} \) and \( \vec{AC} \), using these points: \( \vec{AB} = B - A = (2, -1, 6) - (0, 1, 5) = (2, -2, 1) \) and \( \vec{AC} = C - A = (3, 2, 5) - (0, 1, 5) = (3, 1, 0) \).
02

Find the normal vector to the plane

To find the normal vector \( \vec{n} \) of the plane, calculate the cross product \( \vec{AB} \times \vec{AC} \):\[ \vec{n} = \vec{AB} \times \vec{AC} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ 2 & -2 & 1 \ 3 & 1 & 0 \end{vmatrix} \]Calculating the determinant, we get:\[ \vec{n} = \left( (-2)(0) - (1)(1) \right) \mathbf{i} - \left( (2)(0) - (1)(3) \right) \mathbf{j} + \left( (2)(1) - ((-2)(3)) \right) \mathbf{k} \]Which simplifies to: \( \vec{n} = -1\mathbf{i} + 3\mathbf{j} + 8\mathbf{k} \). Thus, \( \vec{n} = (-1, 3, 8) \).
03

Write the equation of the plane

The general form of the equation of a plane given a normal vector \( (a, b, c) \) and a point \( (x_0, y_0, z_0) \) is:\[ a(x - x_0) + b(y - y_0) + c(z - z_0) = 0 \]For our problem, using the normal vector \( (-1, 3, 8) \) and the point \( A(0, 1, 5) \):\[ -1(x - 0) + 3(y - 1) + 8(z - 5) = 0 \]Which expands to:\[ -x + 3y - 3 + 8z - 40 = 0 \]Simplifying, we get:\[ -x + 3y + 8z = 43 \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross Product
In vector mathematics, the cross product is a fundamental operation that allows us to find a vector perpendicular to two vectors in three-dimensional space. When you're trying to find the equation of a plane that accommodates specific points in 3D, the cross product is instrumental.
Given vectors \( \vec{AB} = (2, -2, 1) \) and \( \vec{AC} = (3, 1, 0) \), we calculate the cross product \( \vec{AB} \times \vec{AC} \). This operation results in the normal vector, \( \vec{n} \), for the plane spanned by these vectors. Calculating a cross product involves setting up and computing the determinant of a 3x3 matrix whose first row consists of unit vectors \( \mathbf{i}, \mathbf{j}, \mathbf{k} \).
  • The second and third rows consist of the components of the vectors you are crossing.
  • The resulting vector is \( \vec{n} = (-1, 3, 8) \).

The significance of this vector is that it provides a direction perpendicular to the plane, an essential piece for defining the plane's equation.
Normal Vector
The normal vector is crucial in describing a plane in 3D space. Simply put, it is a vector that is perpendicular to the entire plane. When calculating this vector for a plane through specific points, you would typically use the cross product of two vectors lying on the plane, just as seen in the previous section.
With the computed vectors \( \vec{AB} \) and \( \vec{AC} \), the cross product yields the normal vector \( \vec{n} = (-1, 3, 8) \). This vector acts as a guiding line, dictating the orientation of the plane relative to the 3D coordinate axes.
  • It is essential for forming the plane's equation, using the plane equation formula.
  • The formula \[ a(x - x_0) + b(y - y_0) + c(z - z_0) = 0 \] incorporates components \( a, b, c \) from the normal vector.

Thus, the normal vector not only helps establish the direction perpendicular to the plane but also assists in structured plane definitions.
Vectors in 3D
Vectors in 3D are pivotal when tackling problems involving geometry in a three-dimensional space. Essentially, a 3D vector represents movement or direction along the x, y, and z axes. These vectors are significant when determining the location and orientation of shapes and planes.
In the task of defining the plane, the points \( A, B, \) and \( C \) translate into vectors \( \vec{AB} \) and \( \vec{AC} \). These vectors possess components that denote their displacement along each axis, a concept readily expressed in the form \( (x, y, z) \).
  • Vectors allow us to calculate other properties like angles and areas through operations like the dot product and cross product.
  • The expressions \( \vec{AB} = (2, -2, 1) \) and \( \vec{AC} = (3, 1, 0) \) help indicate vector direction and magnitude.

Equipped with skills in manipulating 3D vectors, we can navigate various geometric challenges, like finding the equation of a plane.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A car is towed using a force of \(1600 \mathrm{~N}\). The rope used to pull the car makes an angle of \(25^{\circ}\) with the horizontal. Find the work done in towing the car \(2 \mathrm{~km}\). Express the answer in joules \((1 \mathrm{~J}=1 \mathrm{~N} \cdot \mathrm{m})\) rounded to the nearest integer.

Rewrite the given equation of the quadric surface in standard form. Identify the surface. $$ 49 y=x^{2}+7 z^{2} $$

For the following exercises, the equations of two planes are given. Determine whether the planes are parallel, orthogonal, or neither. If the planes are neither parallel nor orthogonal, then find the measure of the angle between the planes. Express the answer in degrees rounded to the nearest integer. Consider the plane of equation \(x-y-z-8=0\) a. Find the equation of the sphere with center \(C\) at the origin that is tangent to the given plane b. Find parametric equations of the line passing through the origin and the point of tangency.

Two forces \(\mathbf{F}_{1}\) and \(\mathbf{F}_{2}\) are represented by vectors with initial points that are at the origin. The first force has a magnitude of \(20 \mathrm{lb}\) and the terminal point of the vector is point \(P(1,1,0)\). The second force has a magnitude of \(40 \mathrm{lb}\) and the terminal point of its vector is point \(Q(0,1,1) .\) Let \(\mathbf{F}\) be the resultant force of forces \(\mathbf{F}_{1}\) and \(\mathbf{F}_{2}\). a. Find the magnitude of \(\mathbf{F}\). (Round the answer to one decimal place.) b. Find the direction angles of \(\mathbf{F}\). (Express the answer in degrees rounded to one decimal place.)

Vector \(\mathbf{p}=\langle 150,225,375\rangle\) represents the price of certain models of bicycles sold by a bicycle shop. Vector \(\mathbf{n}=\langle 10,7,9\rangle\) represents the number of bicycles sold of each model, respectively. Compute the dot product \(\mathbf{p} \cdot \mathbf{n}\) and state its meaning.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.